# Problem A circle with a radius of 6 in. is moved vetically 10 in. along an axis drawn through its center, I need to find the volume of the dimensional figure It looks like a cylinder Then what type of three-dimensional figure is generated in the problem?

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Hi,
You are absolutely right.
The 3-D figure is of cylinder.
Cylinder's volume is given by (pie)*r*r*h.
Here, r is the radius = 6 in.
and h is the height = 10 in.
Volume = 3.14*6*6*10. = 1130.4 cubic in.
Thanks for using Fixya.
Good Luck and have a nice day.

Posted on May 27, 2010

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Posted on Jan 02, 2017

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## Related Questions:

### Area of circle

(pi)R squared (Fixya won't let me use the sign for Pi)

example: suppose the radius of a circle is 10 inches, then the Area of the circle would be pi times 10 times 10 or 100*pi

pi represents the circumference (distance around) of a circle / diameter and for any circle is constantly the same number which is approximately 3.14

so in my example 100*pi=100*3.14 or 314 square inches

Jul 03, 2014 | Computers & Internet

### Formula for circumference

Circumference of a Circle: 2 x pi x radius - OR - pi x diameter,

or if you need some sphere calculations?

Sphere Surface Area: 4 X pi X radius squared OR
pi X diameter squared Sphere Volume: 4/3 X pi X radius cubed OR
( pi X diameter cubed ) / 6
By the way.......... "pi" = 3.1415926536

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### I want to cut a circle where the outside line is 18 inches

To get a circle with a perimeter of 18 inches, you want a diameter of about 5.73 inches (just under 5 3/4 inches) or a radius of 2.86 inches (call it 2 7/8 inches). Get a compass, set its legs 2 and 7/8 inches apart, put one end at the center, and turn.

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### I need open gl source code to make a point move along the circumference of the circle.

Hi
I'm studying Physics, not CS, but I've had a few brushes with OpenGL.
I'll use a Basic-like pseudocode syntax since I don't know what language you're using, and basic is very easy to read:

Const PI = 3.14159, Radius = 10

'Current angle, and angular velocity (dTheta / dt)
Dim Shared Theta as Single, Omega as Single

'Frame is called when you want to draw a new frame
Sub Frame(dt as Single)
'dt is number of seconds passed since last frame (typically less than one, since you want several frames per second)

'Initialize the frame (clear buffers, set up projection, etc)
InitFrame

'Increase angle
Theta = Theta + (Omega * dt)

'Calculate co-ordinates of point

glBegin(GL_POINTS)

'Set the colour of the point
glColor(<r>, <g>, <b>, <a>)

'Draw the point
glVertex2f(X, Y)

glEnd()

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May 16, 2009 | Advanced Graphics Programming Using OpenGL...

Hello,
Sorry to say it but the question does not make sense. A circle is a figure that is perfectly defined by the knowledge of its center (or centre depending of the English you use) and its radius.

An ellipse is perfectly defined if you know its two foci (plural of focus) and the length each of its two axes (major and minor).
Is it the perimeter, the area, the parameter p of the ellipse you are lookong for.

Feb 19, 2009 | The Learning Company Achieve! Math &...

### What is the forular/working out of- ellipse with a long axis 2.500mm and short axis .850 (double the 0.425 radius) the area is 1.669 thus the area of the part circle is 0.835. what is the formular

I'm not sure what your ellipse looks like but the equation for the area of an ellipse is given by:

pi times the long axis times the short axis

pi = 3.1416
The length of the long axis is from the center of the ellipse to the outer edge of the ellipse
The length of the short axis is from the center of the ellipse to the outer edge of the ellipse

Hope this helps Loringh

Nov 01, 2008 | The Learning Company Achieve! Math &...

### Analytic geometry

assuming the question is what is the circle equation?
and if (-2,2) is the center of the circle
the equation should look like this: (x+2)^2+(Y-2)^2=R^2

And now only R is needed.

given 2x-5y+4=0 equation of line perpendicular

we can rearange the equation to be y=(2x+4)/5
from that we can see that the slope of the line is 2/5
And from the fact of perpendicular line we can say that the slope
of the radius line is -2/5.

The motivation now is to calculate the distance between the center of the circle to the cross point of the radius with the line perpendicular

For that we would calculate the radius line equation and compare it to the equation of line perpendicular

As mentioned earlier the slope of the radious line is -2/5.

So the equation is y=-2/5x+b and b can be calculated by using the center of the circle coordinates

2= - (2/5)*(-2)+b ------> b=2-4/5=1.2

Now the cross point is calculated by comparing the equations:
-(2/5)x+1.2=(2x+4)/5 --> -2x+6=2x+4 --> 4x=2 --> x=1/2 --> y=1

So the cross point is (1/2,1).

The distance between the points is calculated by the following
Formula:

R=SQR(((1/2)-(-2))^2+(2-1)^2)=SQR(2.5^2+1^2)=SQR(6.25+1)=
SQR(7.25)

Therefore the circle eq is (x+2)^2+(Y-2)^2=7.25

Oct 26, 2008 | Casio FX-115ES Scientific Calculator

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