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Ind the area of the region bounded by the two circles y=x^3-6x^2+

Find the area of the region bounded by the two circles y=x^3-6x^2+8x and y=x^3-4x.

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The first step here is to draw a rough sketch of the two curves, and find the two points they meet. If you set x^3-6x^2+8x = x^3-4x, then you can rearrange this into the quadratic equation 6x^2-12x = 0. Solving this tells you x=0 or 2 : these are the two x values where the curves meet, and they give the bounds on your integral.

When you sketch the curves, you'll see that x^3-4x is below x^3-6x^2+8x, so the thing you need to integrate is (x^3-6x^2+8x)-(x^3-4x), that is, 12x-6x^2. If you integrate this from 0 to 2, you'll have the answer you need!

Posted on May 28, 2010

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Find the equations of circles passing through (1,-1),touching the lines 4x+3y+5=0 and 3x-4y-10=0


First, I graphed the lines and the point using Desmos.com.

I noticed that the two lines are perpendicular to each other and the point (1,-1) appears to be on the right side of the circle, on a line parallel to 3x -4y-10=0. The equation of this line is y= 3/4x - 1.75. The y-intercept is -1.75. Now we have two points on the opposite sides of the circle, (1, -1) and (0,-1.75). The midpoint formula will give you the centre of the circle and the distance formula will provide the radius.

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The preset region in DVD players cannot be changed, sorry.

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Playstation2 Region Free Fix


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There is more than one model of PS2, and more than one PS2 DVD player module. For some models or modules, only a Messiah 2 or Magic 2 chip installation will make them region free. However, many can be made region free, for free.

Follow these steps to unlock your Sony Playstation 2 DVD Player:

  1. Press and hold CIRCLE, RIGHT, L1
  2. Press and hold L3 and push the stick in hard
  3. Boot into the PS2 browser without a CD/DVD in the tray
  4. Press CIRCLE and R1 on the DVD
  5. Hold RIGHT until a menu appears
  6. Press CIRCLE and R1 again
OR
  1. Load the DVD into the PS2
  2. At the browser screen, select the CD icon the press and hold SQUARE then CIRCLE until the DVD menu appears, holding both buttons all of the time
  3. Either select the PLAY icon or the MOVIE START icon

Your Sony Playstation 2 DVD Player is now Region Free.

I hope that helps.

on May 02, 2010 | Sony PlayStation 2 (PS2) Console

Tip

PS2 DVD Region Free Fix


Sony Playstation 2 DVD Player Region Free Fix

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Would you like to unlock your Sony Playstation 2 DVD Player to Region Free?

There is more than one model of PS2, and more than one PS2 DVD player module. For some models or modules, only a Messiah 2 or Magic 2 chip installation will make them region free. However, many can be made region free, for free.

Follow these steps to unlock your Sony Playstation 2 DVD Player:

  1. Press and hold CIRCLE, RIGHT, L1
  2. Press and hold L3 and push the stick in hard
  3. Boot into the PS2 browser without a CD/DVD in the tray
  4. Press CIRCLE and R1 on the DVD
  5. Hold RIGHT until a menu appears
  6. Press CIRCLE and R1 again
OR
  1. Load the DVD into the PS2
  2. At the browser screen, select the CD icon the press and hold SQUARE then CIRCLE until the DVD menu appears, holding both buttons all of the time
  3. Either select the PLAY icon or the MOVIE START icon

Your Sony Playstation 2 DVD Player is now Region Free.

I hope that helps.

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The circumference of a circle is given by the expression
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C=2*Pi*R
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Area= PI*R^2

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Y>x^2-4x+3


You need to draw the curve y= x^2-4x+ 3. It is a parabola. The equality (=) is verified by all points on the curve. The curve divides the whole plane in two regions. In one region y will be less than x^2-4x+3. In the other regions y will be larger than x^2-4x+3
The regions are the interior of the parabola and its exterior. To find out the region where your inequality is verified you proceed as follow.
  1. Look at the graph and choose the coordinates of one point. Select integer values (BTW the point (0,0) is usually a good candidate) and write y ? x^2-4x+3 where the ? stands for the inequality sign you will have to insert to make the relation correct.
  2. Take x=0, and y=0 and substitute in y ? x^2-4x+3
  3. 0 ? (0^2)-4*(0)+3.
  4. Clearly the ? stands for < because 0 <3.
  5. So at all the points in the region where (0,0) is located the condition y< x^2-4x+3 is TRUE.
In the other region y < x^2-4x+3, is FALSE and that second region (the one that does not contain the origin (0,0) is the one you need to find. It represents your solution set. Note that the origin (0,0) does not lie in the solution set region

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If you know about area formulas of class 8 and 9,please solve my question?there is a circle.in the between of the circle,there is a rectangle of dimension 4cm and 3cm.if the rectangle will cut out what...


The diameter of the circle is the diagonal of the rectangle use Pythagoras this rectangle is a made from two 3,4,5 triangles, so the diameter is 5cm, the radius will be 2.5cm don't forget the BODMAS ordering rule (Brackets of Division Multiplication Addition and Subtraction) Also rounding to 2 decimal places. This solution is based on all four corners of the rectangle touching the circumference of the circle.

Area of a circle is P (22/7) i x Radius (squared ^2) ====> 22/7 x 2.5cm ^ 2 ====> 22/7 x 6.25cm

TOTAL AREA of CIRCLE = 19.64 cm^2

Area of the rectangle is length x width ====> 4 cm x 3 cm

TOTAL AREA of RECTANGLE = 12 cm ^2

The remaining portion is the circle area minus the rectangle 19.64-12 = 7.64 cm^2


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Find the area of a square whose sides are (4x+3)meters long each.


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(4x+3)(4x+3)

16x^2(i.e.squared) + 24x + 9


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area would be 121m squared

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