Question about Texas Instruments BA-II Plus Calculator

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Posted on Jan 02, 2017

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1.393 is the correct answer for the natural log of (1/37 + 4). I believe you want natural log(1/37) + 4, which is .3891 .

Watch those parenthesis. By putting the "+4" inside, you're doing the addition before calculating the log. You want to calculate the log and then add 4.

Watch those parenthesis. By putting the "+4" inside, you're doing the addition before calculating the log. You want to calculate the log and then add 4.

Nov 27, 2012 | Texas Instruments TI 30XIIS Scientific...

You can calculate the logarithm to any base by using the relationship

logb(x) = log(x)/log(b) = ln(x)/ln(b).

To calculate the log base 2 of 16, either divide the log of 16 by the log of 2 or the ln of 16 by the ln of 2.

logb(x) = log(x)/log(b) = ln(x)/ln(b).

To calculate the log base 2 of 16, either divide the log of 16 by the log of 2 or the ln of 16 by the ln of 2.

Apr 07, 2011 | Casio FX-115ES Scientific Calculator

I believe you will have to calculate part of this then input the rest of it. So one way to do this would be

to press [1/x] [6] [4] get an answer of .015625. Clear the calculator then press [4] [y^x] then put in the previous answer .015625 then [log] . This should give you .009407.

to press [1/x] [6] [4] get an answer of .015625. Clear the calculator then press [4] [y^x] then put in the previous answer .015625 then [log] . This should give you .009407.

Mar 07, 2011 | Texas Instruments TI-30XA Calculator

The answer for the problem log(4) - log(2) is actually 0.301, so the good news is that your calculator is working properly! Here's a quick breakdown of the solution for the problem:

1) We know that log(x) = N means that 10^N = x. So in this case, we need to find a number that 10 can be raised to in order to get 4 and 2.

2) To get a better idea of what the answer to the problem will be, we look at the scale of the numbers. 4 and 2 are both smaller than 10. In order to raise any number to a power and get a smaller number, that power must be less than 1. If the power was 1 or greater, the answer would be more than 10. Therefore, we know that log(4) is a decimal less than 1 and log(2) is a decimal less than 1.

3) Now we'll simplify the problem. A logarithm rule states that:

log(x) - log(y) = log(x/y)

We can use this rule to simplify the equation in the problem.

log(4) - log(2) = log(4/2)

Since 4/2 = 2,

log(4) - log(2) = log(4/2) = log(2)

4) Now to solve the equation, the only thing that must be calculated is log(2). This would be done on a calculator. In step 2, we analyzed that log(2) must be less than 1. Therefore, the calculator is correct with the answer 0.301.

Hope this helped!

1) We know that log(x) = N means that 10^N = x. So in this case, we need to find a number that 10 can be raised to in order to get 4 and 2.

2) To get a better idea of what the answer to the problem will be, we look at the scale of the numbers. 4 and 2 are both smaller than 10. In order to raise any number to a power and get a smaller number, that power must be less than 1. If the power was 1 or greater, the answer would be more than 10. Therefore, we know that log(4) is a decimal less than 1 and log(2) is a decimal less than 1.

3) Now we'll simplify the problem. A logarithm rule states that:

log(x) - log(y) = log(x/y)

We can use this rule to simplify the equation in the problem.

log(4) - log(2) = log(4/2)

Since 4/2 = 2,

log(4) - log(2) = log(4/2) = log(2)

4) Now to solve the equation, the only thing that must be calculated is log(2). This would be done on a calculator. In step 2, we analyzed that log(2) must be less than 1. Therefore, the calculator is correct with the answer 0.301.

Hope this helped!

Nov 30, 2010 | Texas Instruments TI-84 Plus Calculator

LOG 1 . 9 ) / 4 LOG 1 . 0 1 7 5 ENTER

Jul 05, 2010 | Texas Instruments TI-83 Plus Calculator

The conversion formula is

# dB =10*log(Pout/Pin) for say an amplifier.

For your case

Pout/Pin= 10^4 then #dB =10*log(10^4)=10*4=40 dB

Let us take a less obscure exemple

# dB= 57.39, what is the power ratio?

10*log(Pout/Pin)= 57.39

log(Pout/Pin)=57.39/10=5.739

Pout/Pin=Ratio =10^(5.739)= 548276.9649, not a number you would hear or see quoted, but a correct value.

To calculate the power ratio

# dB =10*log(Pout/Pin) for say an amplifier.

For your case

Pout/Pin= 10^4 then #dB =10*log(10^4)=10*4=40 dB

Let us take a less obscure exemple

# dB= 57.39, what is the power ratio?

10*log(Pout/Pin)= 57.39

log(Pout/Pin)=57.39/10=5.739

Pout/Pin=Ratio =10^(5.739)= 548276.9649, not a number you would hear or see quoted, but a correct value.

To calculate the power ratio

- Convert the decibels in Bels (divide by 10)
- While the number just calculated is still in Answer memory (ANS), press [SHIFT] [LOG] to access the the 10^x function
- Press [SHIFT][(-)] to enter (ANS)
- Close the parenthesis [)]
- Press [ENTER]

Mar 02, 2010 | Sharp EL-531VB Calculator

Basically you first have to put your answer into scientific notation by pressing the 3rd key then the 6 key. The screen display should change to one big zero and two small zeros.

I was workinggon the same problem with a -log of a chemistry problem to get pH and I knew the answer because I calculated it on it TI-85, but we are not allowed to use graphing calulators on the exam (:-((() so I had to figure out how to do it on this one!

For example, I had pH =-log(2.828947x10^4)

On the TI-36X you change to scientific notation using the instructions above. Once the three zeros enter on the screen:

[4]

[-]

[2nd]

[10^x]

1^-04 should appear on screen, then you multiply by 2.828947

[x]

[2][.][828947]

then your screen will show the answer in scientific notation.

2.828947 in big numbers and in small numbers -04

From there you simply press:

[log]

and your answer will show up as a negative number. Just take the absolute value of that and you have your answer. Took me like 30 minutes the night before a huge chemistry exam to figure that out! Hope it helps someone!

I was workinggon the same problem with a -log of a chemistry problem to get pH and I knew the answer because I calculated it on it TI-85, but we are not allowed to use graphing calulators on the exam (:-((() so I had to figure out how to do it on this one!

For example, I had pH =-log(2.828947x10^4)

On the TI-36X you change to scientific notation using the instructions above. Once the three zeros enter on the screen:

[4]

[-]

[2nd]

[10^x]

1^-04 should appear on screen, then you multiply by 2.828947

[x]

[2][.][828947]

then your screen will show the answer in scientific notation.

2.828947 in big numbers and in small numbers -04

From there you simply press:

[log]

and your answer will show up as a negative number. Just take the absolute value of that and you have your answer. Took me like 30 minutes the night before a huge chemistry exam to figure that out! Hope it helps someone!

May 09, 2009 | Texas Instruments TI-36 X Solar Calculator

The problem is simple. You're trying to get an [H+] concentration which is obviously going to have a value of some number times ten raised to a negative power. Therefore, you have to insert the negative value of the pH into the 10^(x). When you insert said negative number you will come out with the right answer.

i.e.

The pH of a sample of human blood was calculated to be 7.41. What is the [H+] concentration of the blood?

10^(-7.41) = [H+]

[H+] = 3.9 E-8

(the answer should only have two sig. figs because the pH has two digits after the decimal.

i.e.

The pH of a sample of human blood was calculated to be 7.41. What is the [H+] concentration of the blood?

10^(-7.41) = [H+]

[H+] = 3.9 E-8

(the answer should only have two sig. figs because the pH has two digits after the decimal.

Jun 10, 2008 | Texas Instruments TI-84 Plus Calculator

In any scientific calculator log2(n) can be calculated with either ln or log function as
follows

Log2(n)= ln(n) / ln(2)

Or

Log2(n)=log(n) / log(2)

both will give nearly the same answers

Log2(n)= ln(n) / ln(2)

Or

Log2(n)=log(n) / log(2)

both will give nearly the same answers

Dec 08, 2007 | Casio FX-300MS Calculator

Sep 11, 2014 | Texas Instruments BA-II Plus Calculator

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