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How do i get the correct answer to this problem using the this calculator, log 4 3

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Assuming you mean the log-base-3 of 4,
press 4 LN / 3 LN =

Posted on Feb 22, 2011

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Not getting right answer when I enter natural log (1/37+4)..


1.393 is the correct answer for the natural log of (1/37 + 4). I believe you want natural log(1/37) + 4, which is .3891 .

Watch those parenthesis. By putting the "+4" inside, you're doing the addition before calculating the log. You want to calculate the log and then add 4.

Nov 27, 2012 | Texas Instruments TI 30XIIS Scientific...

1 Answer

I have a Casio fx-82au plus and want to input logs to the base less than 10. Is there a way to do this? eg log to the base of 2 = 16 (answer is 4 but how do we get that to work on this calculator).


You can calculate the logarithm to any base by using the relationship
logb(x) = log(x)/log(b) = ln(x)/ln(b).

To calculate the log base 2 of 16, either divide the log of 16 by the log of 2 or the ln of 16 by the ln of 2.

Apr 07, 2011 | Casio FX-115ES Scientific Calculator

1 Answer

How do you find the logarythm of log 4^1/64


I believe you will have to calculate part of this then input the rest of it. So one way to do this would be
to press [1/x] [6] [4] get an answer of .015625. Clear the calculator then press [4] [y^x] then put in the previous answer .015625 then [log] . This should give you .009407.

Mar 07, 2011 | Texas Instruments TI-30XA Calculator

1 Answer

When I substract log(2) from log(4) I get .301029957, the answer should be 2, what is wrong?


The answer for the problem log(4) - log(2) is actually 0.301, so the good news is that your calculator is working properly! Here's a quick breakdown of the solution for the problem:

1) We know that log(x) = N means that 10^N = x. So in this case, we need to find a number that 10 can be raised to in order to get 4 and 2.
2) To get a better idea of what the answer to the problem will be, we look at the scale of the numbers. 4 and 2 are both smaller than 10. In order to raise any number to a power and get a smaller number, that power must be less than 1. If the power was 1 or greater, the answer would be more than 10. Therefore, we know that log(4) is a decimal less than 1 and log(2) is a decimal less than 1.
3) Now we'll simplify the problem. A logarithm rule states that:

log(x) - log(y) = log(x/y)

We can use this rule to simplify the equation in the problem.

log(4) - log(2) = log(4/2)

Since 4/2 = 2,

log(4) - log(2) = log(4/2) = log(2)

4) Now to solve the equation, the only thing that must be calculated is log(2). This would be done on a calculator. In step 2, we analyzed that log(2) must be less than 1. Therefore, the calculator is correct with the answer 0.301.

Hope this helped!

Nov 30, 2010 | Texas Instruments TI-84 Plus Calculator

1 Answer

DB to Power ratio using antilog


The conversion formula is
# dB =10*log(Pout/Pin) for say an amplifier.
For your case
Pout/Pin= 10^4 then #dB =10*log(10^4)=10*4=40 dB

Let us take a less obscure exemple

# dB= 57.39, what is the power ratio?
10*log(Pout/Pin)= 57.39
log(Pout/Pin)=57.39/10=5.739
Pout/Pin=Ratio =10^(5.739)= 548276.9649, not a number you would hear or see quoted, but a correct value.

To calculate the power ratio
  1. Convert the decibels in Bels (divide by 10)
  2. While the number just calculated is still in Answer memory (ANS), press [SHIFT] [LOG] to access the the 10^x function
  3. Press [SHIFT][(-)] to enter (ANS)
  4. Close the parenthesis [)]
  5. Press [ENTER]
Here is the screen capture for the calculation one way and back.

6930c92.jpg

Mar 02, 2010 | Sharp EL-531VB Calculator

3 Answers

Hoe do you use logarithm on TI-36X SOLAR?


Basically you first have to put your answer into scientific notation by pressing the 3rd key then the 6 key. The screen display should change to one big zero and two small zeros.

I was workinggon the same problem with a -log of a chemistry problem to get pH and I knew the answer because I calculated it on it TI-85, but we are not allowed to use graphing calulators on the exam (:-((() so I had to figure out how to do it on this one!

For example, I had pH =-log(2.828947x10^4)

On the TI-36X you change to scientific notation using the instructions above. Once the three zeros enter on the screen:
[4]
[-]
[2nd]
[10^x]

1^-04 should appear on screen, then you multiply by 2.828947

[x]
[2][.][828947]
then your screen will show the answer in scientific notation.

2.828947 in big numbers and in small numbers -04
From there you simply press:
[log]
and your answer will show up as a negative number. Just take the absolute value of that and you have your answer. Took me like 30 minutes the night before a huge chemistry exam to figure that out! Hope it helps someone!

May 09, 2009 | Texas Instruments TI-36 X Solar Calculator

6 Answers

How do i use the inverse log operation on the TI-84


The problem is simple. You're trying to get an [H+] concentration which is obviously going to have a value of some number times ten raised to a negative power. Therefore, you have to insert the negative value of the pH into the 10^(x). When you insert said negative number you will come out with the right answer.
i.e.
The pH of a sample of human blood was calculated to be 7.41. What is the [H+] concentration of the blood?
10^(-7.41) = [H+]
[H+] = 3.9 E-8  
(the answer should only have two sig. figs because the pH has two digits after the decimal.

Jun 10, 2008 | Texas Instruments TI-84 Plus Calculator

11 Answers

How to calculate log value in calculator with different base value


In any scientific calculator log2(n) can be  calculated with either ln or log function as follows
 
Log2(n)= ln(n) / ln(2)
 
Or
Log2(n)=log(n) / log(2)

both will give nearly the same answers

Dec 08, 2007 | Casio FX-300MS Calculator

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