Question about SoftMath Algebrator - Algebra Homework Solver (689076614429)

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Let A = number of adult tickets and S = number of senior tickets.

The total number of tickets is 444. This equals A + S.

444 = A + S

Total receipts were $7345. This can be represented as:

7345 = A*20 + S*15

Solve for A in first equation.

A = 444 - S

Substitute this into the 2nd equation for A

7345 = (444 - S)*20 + S*15

Solve for S

7345 = 8880 - 20*S + 15*S

7345 = 8880 - 5*S

-1535 = -5*S

307 = S

Therefore there were 307 senior tickets sold.

The number of adult tickets would be 444-307 = 137

Posted on Feb 01, 2011

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Posted on Jan 02, 2017

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Jun 29, 2017 | Computers & Internet

6 adults and 20 kids.

If this is homework, be sure to show your work.

If this is homework, be sure to show your work.

Oct 04, 2014 | Cycling

Generally, teenage drivers with no driving record have very

expensive insurance, as do senior citizens

expensive insurance, as do senior citizens

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check malaysia airlines website for cheap tickets

Oct 16, 2012 | Daron HE561549 Herpa Air Macau A321 East...

450 times 25=11250 230 times 14=3220 add 11250and3220=14470 divide by 48 =301.4, i hope ive got my maths right

Jul 10, 2011 | Samsung Computers & Internet

Let S = number of senior tickets and A = number of adult tickets.

From the given information you know a) that S+A = 444 (total tickets sold) and b) 20A+15S = 7345 (amount of money taken in).

Rearrange a): A = 444-S and substitute it in b), then solve for S.

20(444-S) + 15S = 7345

8880 - 20S + 15S = 7345

8880 - 7345 = 20S - 15S

1535 = 5S

S = 307

From the given information you know a) that S+A = 444 (total tickets sold) and b) 20A+15S = 7345 (amount of money taken in).

Rearrange a): A = 444-S and substitute it in b), then solve for S.

20(444-S) + 15S = 7345

8880 - 20S + 15S = 7345

8880 - 7345 = 20S - 15S

1535 = 5S

S = 307

Mar 24, 2010 | SoftMath Algebrator - Algebra Homework...

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