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University theater sold 444 tickets for a play. Tickets cost $20 per adult and $15 per senior citizen. If total receipts were $7345 how many senior citizen tickets were sold?

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Let A = number of adult tickets and S = number of senior tickets.
The total number of tickets is 444. This equals A + S.
444 = A + S
Total receipts were $7345. This can be represented as:
7345 = A*20 + S*15
Solve for A in first equation.
A = 444 - S
Substitute this into the 2nd equation for A
7345 = (444 - S)*20 + S*15
Solve for S
7345 = 8880 - 20*S + 15*S
7345 = 8880 - 5*S
-1535 = -5*S
307 = S

Therefore there were 307 senior tickets sold.
The number of adult tickets would be 444-307 = 137

Posted on Feb 01, 2011

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University theater sold 444 tickets for a play. Tickets cost $20 per adult and $15 per senior citizen. If total receipts were $7345, how many senior citizen tickets were sold?


Let S = number of senior tickets and A = number of adult tickets.
From the given information you know a) that S+A = 444 (total tickets sold) and b) 20A+15S = 7345 (amount of money taken in).
Rearrange a): A = 444-S and substitute it in b), then solve for S.

20(444-S) + 15S = 7345

8880 - 20S + 15S = 7345

8880 - 7345 = 20S - 15S

1535 = 5S

S = 307

Mar 24, 2010 | SoftMath Algebrator - Algebra Homework...

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