Question about Mathsoft StudyWorks! Middle School Deluxe Math 5.0 (11543) for PC

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To find x using calculator x = ( 1.086956522 ) ^ 1/1.017

gives you the answer.

Alternate method is my taking logarithm on both sides and solving for x.

Posted on May 27, 2010

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Posted on Jan 02, 2017

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How it Works
### Stone and Mulch Calculators

As an example, let's use 500 square feet to be mulched at a

3" depth.

### For Your Information

3" depth.

- First, the depth must be converted to feet. To convert inches to feet, simply divide inches by 12, the number of inches in a foot.

So for our example: 3 inches divided by 12 equals a 0.25 foot depth. - Now that we have the depth in feet, we can multiply the depth by the area.

So for our example: 0.25 foot depth times 500 square feet equals 125 cubic feet. - If you are calculating 0.5, 2, or 3, cubic foot bags, simply divide 125 cubic feet by the size of the bag.

So for our example: if we are using 2 cubic foot bags, we can divide 125 cubic feet by 2 which equals 62.5 bags. - If you are calculating cubic yards, we need to convert 125 cubic feet to cubic yards by dividing by 27. One cubic yard is equal to 27 cubic feet, see the diagram below.

So for our example: 125 cubic feet divided by 27 equals 4.63 cubic yards.

- 1 inch equals 0.08333 feet
- 1.5 inches equals 0.125 feet
- 2 inc

Jun 29, 2016 | Office Equipment & Supplies

1) 2x + 5y = 7

2) 3x + 6y = 3

I'm going to use the method of elimination to solve for x and y.

Multiply 1) by 3 and 2) by 2 to allow the x's to be eliminated.

1) 6x + 15y = 21

2) 6x + 12y = 6

Now subtract line 2 from line 1.

0x + 3y = 15

---- ----

3 3 divide both sides by 3 to get y by itself.

y =5.

Substitute into 1) to calculate x.

2x + 5(5) = 7

2x + 25 = 7

2x + 25 -25 = 7 - 25

2x = -18

---- ----- divide both sides by 2 to get x by itself

2 2

x = -9

Check by plugging in answer into the other equation, in this case 2)

3 (-9) + 6(5) = 3

-27 + 30 = 3

3 = 3

We did it correctly and checked to prove that we did it right.

Good luck.

Paul

2) 3x + 6y = 3

I'm going to use the method of elimination to solve for x and y.

Multiply 1) by 3 and 2) by 2 to allow the x's to be eliminated.

1) 6x + 15y = 21

2) 6x + 12y = 6

Now subtract line 2 from line 1.

0x + 3y = 15

---- ----

3 3 divide both sides by 3 to get y by itself.

y =5.

Substitute into 1) to calculate x.

2x + 5(5) = 7

2x + 25 = 7

2x + 25 -25 = 7 - 25

2x = -18

---- ----- divide both sides by 2 to get x by itself

2 2

x = -9

Check by plugging in answer into the other equation, in this case 2)

3 (-9) + 6(5) = 3

-27 + 30 = 3

3 = 3

We did it correctly and checked to prove that we did it right.

Good luck.

Paul

Mar 12, 2015 | Office Equipment & Supplies

Use this http://www.calculatorsoup.com/calculators/math/percent-to-fraction-calculator.php

**OR** to work it out yourself.....#

### How to convert percent to fraction

1% = 1/100

So in order to convert percent to fraction, divide the percent by 100% and reduce the fraction.

For example 56% is equal to 56/100 with gcd=4 is equal to 14/25:

56% = 56/100 = 14/25

- Divide the percent by 100 to get decimal number.
- Count the number of digits (d) to the right of the decimal point of the decimal number.Example: 2.56 has 2 digits to the right of the decimal point, so d=2.
- Calculate the factor (f) for making the decimal number an integer:
*f*= 10*to power d*

Example:

*f*= 10 power 2 = 100

- Multiply and divide the decimal number x by the factor f:
*x***f*/*f*=*y*/*f*

Example:

2.56 * 100 / 100 = 256 / 100

- Find the greatest common divisor (gcd) of the fraction.
Example:

gcd(256,100) = 4

- Reduce the fraction by dividing the numerator and denominator by the gcd value:
Example:

256 / 100 = (256/4) / (100/4) = 64/25

1% = 1/100

So in order to convert percent to fraction, divide the percent by 100% and reduce the fraction.

For example 56% is equal to 56/100 with gcd=4 is equal to 14/25:

56% = 56/100 = 14/25

Sep 07, 2014 | Office Equipment & Supplies

Press 2 ^ 2ND ^ ENTER .

If you get a symbolic result, press diamond ENTER .

If you get a symbolic result, press diamond ENTER .

Jan 18, 2013 | Texas Instruments TI-89 Calculator

(abc)4 does not equal a x b x c4

For example

if you plug in a = 1, b = 2, c = 3

(1 x 2 x 3)4 = (6)4=1,296

where as

1 x 2 x 34 =162

Jun 28, 2011 | Texas Instruments TI-84 Plus Calculator

It is unclear whether your equation is:

a: ((SQRT61) - 7) / 2

or

b: ((SQRT61) / 2) - 7

For a:

Type 61 SQRT.

Subtract 7.

Equals.

Divide by 2.

Equals. (Should be 0.4051248...)

For b:

Type 61 then SQRT.

Then divide by 2.

Equals.

Then subtract 7.

Equals. (Should be -3.094875...)

Good luck.

a: ((SQRT61) - 7) / 2

or

b: ((SQRT61) / 2) - 7

For a:

Type 61 SQRT.

Subtract 7.

Equals.

Divide by 2.

Equals. (Should be 0.4051248...)

For b:

Type 61 then SQRT.

Then divide by 2.

Equals.

Then subtract 7.

Equals. (Should be -3.094875...)

Good luck.

Apr 15, 2011 | Texas Instruments TI-30XA Calculator

I am not sure what you are asking for?

Repeated multiplication (with same factor) is called raising a number (base) to a power. The exponent of the power is equal to the number of times the factor is repeated.

The calculator has several buttons to calculate powers.

For the square X*X you have a key [X^2].

For the cube X*X*X you MIGHT have a dedicated key [X^3].

However all calculators (scientific) have a universal power key marked [^] or [X^y] or [Y^x]

Example : In 5x5x5x5x5x5x5 you have a repeated multiplication, so the base is the factor (5) and the exponent is equal to 5. It is equal to the number of times the factor is repeated.

So 5x5x5x5x5x5x5 can be written much more efficiently as 5^7

Entering 5 then pressing the [^] key, followed by the exponent 7 gives the result 78125.

Repeated multiplication (with same factor) is called raising a number (base) to a power. The exponent of the power is equal to the number of times the factor is repeated.

The calculator has several buttons to calculate powers.

For the square X*X you have a key [X^2].

For the cube X*X*X you MIGHT have a dedicated key [X^3].

However all calculators (scientific) have a universal power key marked [^] or [X^y] or [Y^x]

Example : In 5x5x5x5x5x5x5 you have a repeated multiplication, so the base is the factor (5) and the exponent is equal to 5. It is equal to the number of times the factor is repeated.

So 5x5x5x5x5x5x5 can be written much more efficiently as 5^7

Entering 5 then pressing the [^] key, followed by the exponent 7 gives the result 78125.

Jun 23, 2010 | Texas Instruments TI-30X-IISTK Scientific...

The cotangent function is not implemented on the TI84PLUS native OS and consequently you will not find its inverse function on the calculator. However, there exits an equivalence (definition) between arc cotangent(x) and arc tangent (1/x).

Thus cot^(-1)(X)= tan^(-1)(1/X),

Be careful. Since it is a multivariate function, some authors define the principal branch in the domain [0, PI], while others define the domain on [-Pi/2, Pi/2]. You will have to consult your textbook, or the documents you are using to find out the domain of the principal branch.

Thus cot^(-1)(X)= tan^(-1)(1/X),

Be careful. Since it is a multivariate function, some authors define the principal branch in the domain [0, PI], while others define the domain on [-Pi/2, Pi/2]. You will have to consult your textbook, or the documents you are using to find out the domain of the principal branch.

Apr 12, 2010 | Texas Instruments TI-84 Plus Calculator

This is not a calculator problem. Use the rules you have learned to simplify your problem.

For a a log in any base.** log(a*b) =log(a) +log(b)** or log(a)+log(b) =log(a*b).

Thus

log(x+1)+log(x-2)= log[(x+1)*(x-2)]=1

Use the fact that log4=log in base 4 and rewrite the equation with the appropriate symbols.** log4[(x+1)*(x-2)] =1 **

However**1=log4(4)** and

l**og4[(x+1)*(x-2)]=log4(4)**

The equality of the two logs implies the equality of their arguments (contents) and

**(x+1)*(x-2) =4**

Now you solve this quadratic equation by the methods you must have learned (sorry I have to leave some thing for you to do, to ensure that proper learning is achieved).

Once you find the roots of the quadratic equation, verify that each term in your original expression has meaning-- x+1 positive and x-2 positive.

If one of the roots makes the argument (x+1) or (x-2) negative, reject it. because the argument of a log function cannot be negative.

For a a log in any base.

Thus

log(x+1)+log(x-2)= log[(x+1)*(x-2)]=1

Use the fact that log4=log in base 4 and rewrite the equation with the appropriate symbols.

However

l

The equality of the two logs implies the equality of their arguments (contents) and

Now you solve this quadratic equation by the methods you must have learned (sorry I have to leave some thing for you to do, to ensure that proper learning is achieved).

Once you find the roots of the quadratic equation, verify that each term in your original expression has meaning-- x+1 positive and x-2 positive.

If one of the roots makes the argument (x+1) or (x-2) negative, reject it. because the argument of a log function cannot be negative.

Dec 14, 2009 | Casio FX-300MS Calculator

Hello,

To raise 10 to the 2nd power, if you do not have a dedicated key, you use the (^) or (X to the y) or (Y to the x) depending on calculator.

The EE key is a shortcut. It has another meaning

** EE 0 = 10^0 =1**

EE 1 = 10^1 =10

EE 2 = 10^2 = 100

Thus if you enter 10 EE 2 this is equal to 10 x** EE 2**=10x 100= 1000.

This is the correct way.

Hope you will remember it : It is the source of much grief to the learners.

To raise 10 to the 2nd power, if you do not have a dedicated key, you use the (^) or (X to the y) or (Y to the x) depending on calculator.

The EE key is a shortcut. It has another meaning

EE 1 = 10^1 =10

EE 2 = 10^2 = 100

Thus if you enter 10 EE 2 this is equal to 10 x

This is the correct way.

Hope you will remember it : It is the source of much grief to the learners.

Oct 08, 2009 | Texas Instruments TI-30X-IISTK Scientific...

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