Question about Heating & Cooling

Http://www.ebinderup.com/pdf/OCB453.pdf service manual

http://www.mitsubishielectric.it/mitsa/pdf/OCH453%5B1%5D.pdf parts

Posted on May 11, 2010

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Posted on Jan 02, 2017

pKa=-logKa

-pKa=logKa

10^(-pKa)=10^(log(Ka))=Ka

Ka=10^(-3.89)

I don't know where you got the value you give but here is what my calculator finds.

-pKa=logKa

10^(-pKa)=10^(log(Ka))=Ka

Ka=10^(-3.89)

I don't know where you got the value you give but here is what my calculator finds.

Jan 14, 2016 | Texas Instruments TI-30 XIIS Calculator

If the lenses are PK / PKA bayonet fitting, yes - if they are autofocus as well, this is a bonus, as that too should work. If they are M42 screw-fit, then you'll need an adapter, and all functions (zoom, focus, exposure) will be strictly manual.

Dec 20, 2015 | Pentax Cameras

try this. http://www.manualslib.com/

Jan 25, 2015 | Filter Heating & Cooling

when

Jan 28, 2014 | Personalised Grandmas Wish List Print, Not...

(-) LOG 1 . 7 5 EE (-) 5 ENTER

The (-) is just to the right of the decimal point, the LOG key is in the leftmost column between the GRAPH and LN keys, the EE key is just above the 7 key.

The (-) is just to the right of the decimal point, the LOG key is in the leftmost column between the GRAPH and LN keys, the EE key is just above the 7 key.

Dec 11, 2010 | Texas Instruments TI-85 Calculator

Go to site www.manualsonline.com for download of manual. Rus

Mar 17, 2010 | Mitsubishi Heating & Cooling

You need the [EE] key to enter powers of 10 exponents.

You need the change sign key [+/-] key.

You need the [LOG] key.

pKa: 6.5 [EE] [+/-] 5 [LOG] [+/-]

There are two change sign: The first (either before or after the exponent 5), the last is entered after you press the log key , so as to negate (make negative if result is positive, and make positive is result is negative) the value.

The result should be 4.1870866 or 4.19

You need the change sign key [+/-] key.

You need the [LOG] key.

pKa: 6.5 [EE] [+/-] 5 [LOG] [+/-]

There are two change sign: The first (either before or after the exponent 5), the last is entered after you press the log key , so as to negate (make negative if result is positive, and make positive is result is negative) the value.

The result should be 4.1870866 or 4.19

Mar 08, 2010 | Texas Instruments TI-36 X Solar Calculator

Hi,

Let Ka be the acidity constant (acid dissociation constant). The pKa is defined as the negative of the log in base 10 of the acidity constant.

pKa= - log_10(Ka) where log_10 is the logarithm in base 10.

To calculate the pKa you use the key labeled [LOG], just above [COS].**Be careful with the negative sign: **For that, you use the key **[(-)]** just above the RCL key. Press the keys in the order specified below

pKa =**[(-)] [LOG] number [ ) ] [=] **

Although the right parenthesis is not required in this particular case, it is better to accustom oneself to close the parenthesis.

Hope it helps.

Let Ka be the acidity constant (acid dissociation constant). The pKa is defined as the negative of the log in base 10 of the acidity constant.

pKa= - log_10(Ka) where log_10 is the logarithm in base 10.

To calculate the pKa you use the key labeled [LOG], just above [COS].

pKa =

Although the right parenthesis is not required in this particular case, it is better to accustom oneself to close the parenthesis.

Hope it helps.

Dec 07, 2009 | Casio FX-115ES Scientific Calculator

I need your Email. I will send you the Manual.

Thanks

George

send yuor Email to me gtjinusa@yahoo.com

Thanks

George

send yuor Email to me gtjinusa@yahoo.com

Apr 28, 2009 | Mitsubishi Heating & Cooling

Hello,

If I guessed right you are talking about the Chemistry notion of the pKa

Let the equilibrium constant be Ka =1.8x10^(-5). Then by definition pKa=-log(Ka) , log in base 10

pKa = - log(1.8x 10^(-5))

First set [MODE] to [COMP] by pressing [MODE] 1.

** [LOG] [(] 1.8 [x] [SHIFT] [10 to the x] [(-)] 5 [)] . [(-)]**

The [(-)] key is the change sign key : a small - between parentheses. The last [(-)] sign in the expression takes the negative of the whole calculation to obtain the correct value of the pKa.

The value you should find for the above exemple is 4.74

Hope it helps.

If I guessed right you are talking about the Chemistry notion of the pKa

Let the equilibrium constant be Ka =1.8x10^(-5). Then by definition pKa=-log(Ka) , log in base 10

pKa = - log(1.8x 10^(-5))

First set [MODE] to [COMP] by pressing [MODE] 1.

The [(-)] key is the change sign key : a small - between parentheses. The last [(-)] sign in the expression takes the negative of the whole calculation to obtain the correct value of the pKa.

The value you should find for the above exemple is 4.74

Hope it helps.

Dec 17, 2008 | Casio FX-115MS Plus Calculator

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