Question about NetGear DG834G Router

Do you get the log on screen to type username / password? I´d need more information about your problem..

Posted on May 08, 2010

Hi,

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Posted on Jan 02, 2017

Under assumptions your are trying to logon to a networked machine which requires that PC to contact a server to download your account.

now if this PC has been disconnected from the network but still has your temporary user profile stored on it, you can still log on but only as a temp user.

to solve this make sure your connected to the network either through wireless or wired.

now if this PC has been disconnected from the network but still has your temporary user profile stored on it, you can still log on but only as a temp user.

to solve this make sure your connected to the network either through wireless or wired.

Dec 20, 2013 | Computers & Internet

Please be more specific-Is it on your computer or mobile?which mobile(or mobile os)?

Also try forgot password

Also try forgot password

Dec 27, 2012 | Facebook Social Network

Must be a programming error. I have the same it says you must log in first everytime i try to log in. This is one of those problems that is just brushed aside untill no one cares. Try and download the facebook bookmark onto your phone again.

Feb 04, 2010 | Facebook Social Network

you need to replace your modem with a router that is capable of running Network Address Translation. You are trying to route private IP's (192,168.x.x) over the public IP (internet) network.

Jan 31, 2010 | Microsoft Windows 2000 Professional for PC

Hi,

Ex: calculate -log(15.32)

Here is a picture of the change sign

Hope it helps

Ex: calculate -log(15.32)

- Calculate the log 15.32 [LOG] [=] result 1.185258765
- Then press the change sign key (-) result -1.185258765

Here is a picture of the change sign

Hope it helps

Dec 13, 2009 | Texas Instruments TI-30XA Calculator

Hi,

It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.

Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

**2*log(4,x) -log(4,x) +log(4,3) = log(4,x)-log(4,x) -log(4,2) **

which is equivalent to**log(4,x) +log(4,3) = -log(4,2)**

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) =**- { log(4,2)+log(4,3)}** = -log(4,2*3)

You get**log(4,x)= -log(4,6)**.

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain

log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.

It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.

Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

which is equivalent to

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) =

You get

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain

log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.

Nov 25, 2009 | Casio FX-300MS Calculator

It's simple here some logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

Jul 01, 2009 | Texas Instruments TI-83 Plus Calculator

Look it's simple in the calculator the default base is 10 so when you input log 3 its log 3 base 10 so:

maybe you know in math log x base y = log x / log y . So if you need log 3 base 3 its => log 3 / log 3 (by the way its 1)

maybe you know in math log x base y = log x / log y . So if you need log 3 base 3 its => log 3 / log 3 (by the way its 1)

Mar 27, 2009 | Casio FX-300MS Calculator

Try restarting your computer and then try logging in to Myspace. I had the same problem yesterday but after I restarted my computer I was able to log in. It's worth a try, it worked for me. Let me know if it works for you

Jan 08, 2009 | MySpace Social Network

May 04, 2014 | NetGear DG834G Router

Feb 15, 2014 | NetGear DG834G Router

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