Question about Compaq OA-LCM-14.1XGA+PA PARTS-PC8447-OMAHA

Without parenthesis, I assume you mean 12 a b^2 and 22 a^2 b.

To do a LCM, just find all the prime factors, select out enough to cover both entries, and multiply together. 12 is 3 * 2 * 2. 22 is 11 * 2. You need two 2's. So you need 2 * 2 * 3 * 11 = 132. And you need 2 a's and 2 b's. Answer 132 a^2 b^2.

Posted on Jun 13, 2008

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Posted on Jan 02, 2017

Let us backtrack so as to better jump.

An algebraic expression may contain one or several**algebraic terms**, separated by a plus sign or a or a minus and a sign.

Each algebraic term is the product of a constant coefficient and a power of some variable, or the powers of several variables.

Example of an algebraic term 3(x^2)(y^6)....

**If the exponents of the various powers are positive integers, the term is called a monomial. **In short no square roots, or fractionary powers of the variables appear in monomials. Thus 2/x, 3SQRT(x), or 1/x^5 are not monomials.

Finally, a polynomial is an**algebraic expression** made up of one or more monomials.

Example P(X)=(1/3)X^7-(SQRT(5)*X^4+ 16X-25 is a polynomial of degree 7 in the indeterminate/variable X

Q(X,Y)= 3(X^3)*Y^2 + 4X-5Y+10 is a polynomial of degree 5 in the variables X and Y.

An algebraic expression may contain one or several

Each algebraic term is the product of a constant coefficient and a power of some variable, or the powers of several variables.

Example of an algebraic term 3(x^2)(y^6)....

Finally, a polynomial is an

Example P(X)=(1/3)X^7-(SQRT(5)*X^4+ 16X-25 is a polynomial of degree 7 in the indeterminate/variable X

Q(X,Y)= 3(X^3)*Y^2 + 4X-5Y+10 is a polynomial of degree 5 in the variables X and Y.

Oct 01, 2014 | Office Equipment & Supplies

its round has lots of squares and has a handle

Sep 11, 2013 | Texas Instruments TI-86 Calculator

Square root equivalent to power 1/2

Fifth root equivalent to power 1/5

square root of fifth root**(if argument of square root is positive)** is equivalent to power 1/10

64^(1/10)*q^(4/5)*v^(3/5)

using 64=2^6 you get**2^(3/5)*q^(4/5)*v^(3/5)**

Fifth root equivalent to power 1/5

square root of fifth root

64^(1/10)*q^(4/5)*v^(3/5)

using 64=2^6 you get

Jul 13, 2013 | SoftMath Algebrator - Algebra Homework...

(Square root(7))*(Square root (15))=(Square root (7*15)=Square root(105)

Mar 29, 2012 | MathRescue Word Problems Of Algebra Lite

Just complete the square

x^2-22x-10=x^2-2(x)*11+11^2-11^2-10=(x-11)^2-121-10=(x-11)^2- 131.

Use the identity a^2-b^2=(a-b)(a+b) with a=(x-11) and b= square root (131)

Solutions are**x1= 11 + square root (131) **and **x2=11-square root (131)**.

By the way, the calculator you are refer to cannot perform symbolic algebra calculations.

x^2-22x-10=x^2-2(x)*11+11^2-11^2-10=(x-11)^2-121-10=(x-11)^2- 131.

Use the identity a^2-b^2=(a-b)(a+b) with a=(x-11) and b= square root (131)

Solutions are

By the way, the calculator you are refer to cannot perform symbolic algebra calculations.

Nov 30, 2011 | Casio FX-115ES Scientific Calculator

1. Square of a sum

2. Square of a difference

3. Difference of square (also called product of sum and difference)

4. Cube of a sum

5. Cube of a difference

6. Difference of cube

7. Sum of cube

For more information about each type click this link.

2. Square of a difference

3. Difference of square (also called product of sum and difference)

4. Cube of a sum

5. Cube of a difference

6. Difference of cube

7. Sum of cube

For more information about each type click this link.

Sep 04, 2011 | Computers & Internet

In Algebra

Likewise when you see

Special Binomial Products So when you multiply binomials you get ... Binomial Products

And we are going to look at

1. Multiplying a Binomial by Itself What happens when you square a binomial (in other words, multiply it by itself) .. ?

(a+b)2 = (a+b)(a+b) = ... ?

The result:

(a+b)2 = a2 + 2ab + b2

You can easily see why it works, in this diagram:

2. Subtract Times Subtract
And what happens if you square a binomial with a **minus** inside?

(a-b)2 = (a-b)(a-b) = ... ?

The result:

(a-b)2 = a2 - 2ab + b2

3. Add Times Subtract
And then there is one more special case... what if you multiply (a+b) by (a-b) ?

(a+b)(a-b) = ... ?

The result:

(a+b)(a-b) = a2 - b2

That was interesting! It ended up very simple.

And it is called the "**difference of two squares**" (the two squares are **a2** and **b2**).

This illustration may help you see why it works:

a2 - b2 is equal to (a+b)(a-b)
Note: it does not matter if (a-b) comes first:

(a-b)(a+b) = a2 - b2

The Three Cases
Here are the three results we just got:

(a+b)2
= a2 + 2ab + b2
} (the "perfect square trinomials")
(a-b)2
= a2 - 2ab + b2
(a+b)(a-b)
= a2 - b2
(the "difference of squares")
Remember those patterns, they will save you time and help you solve many algebra puzzles.

Using Them
So far we have just used "a" and "b", but they could be anything.

Example: (y+1)2

We can use the (a+b)2 case where "a" is y, and "b" is 1:

(y+1)2 = (y)2 + 2(y)(1) + (1)2 = y2 + 2y + 1

Example: (3x-4)2

We can use the (a-b)2 case where "a" is 3x, and "b" is 4:

(3x-4)2 = (3x)2 - 2(3x)(4) + (4)2 = 9x2 - 24x + 16

Example: (4y+2)(4y-2)

We know that the result will be the difference of two squares, because:

(a+b)(a-b) = a2 - b2

so:

(4y+2)(4y-2) = (4y)2 - (2)2 = 16y2 - 4

Sometimes you can recognize the pattern of the answer:

Example: can you work out which binomials to multiply to get 4x2 - 9

Hmmm... is that the difference of two squares?

Yes! **4x2** is **(2x)2**, and **9** is **(3)2**, so we have:

4x2 - 9 = (2x)2 - (3)2

And that can be produced by the difference of squares formula:

(a+b)(a-b) = a2 - b2

Like this ("a" is 2x, and "b" is 3):

(2x+3)(2x-3) = (2x)2 - (3)2 = 4x2 - 9

So the answer is that you can multiply **(2x+3)** and **(2x-3)** to get **4x2 - 9**

Jul 26, 2011 | Computers & Internet

Here, We deal with Some Special Products in Polynomials.

Certain products of Polynomials occur more often

in Algebra. They are to be considered specially.

These are to be remembered as Formulas in Algebra.

Remembering these formulas in Algebra is as important

as remembering multiplication tables in Arithmetic.

We give a list of these Formulas and Apply

them to solve a Number of problems.

We give Links to other Formulas in Algebra.

Here is the list of Formulas in

Polynomials which are very useful in Algebra.

Formulas in Polynomials :

** Algebra Formula 1 in Polynomials: ** * Square of Sum of Two Terms: *

** (a + b)2 = a2 + 2ab + b2 **

** (a - b)2 = a2 - 2ab + b2 **

** (a + b)(a - b) = a2 - b2 **

** (a + b)(a2 - ab + b2) = a3 + b3 **

** (a - b)3 = a3 - 3a2b + 3ab2 - b3 = a3 - 3ab(a - b) - b3 **

(First term + Second term)2

= (First term)2 + 2(First term)(Second term) + (Second term)2

Jul 02, 2011 | Computers & Internet

Sq. Rt of 1/5 (or .2) is:

0.44721359549995793928183473374626

Sq Rt of 5 is:

2.2360679774997896964091736687313

0.44721359549995793928183473374626 - 2.2360679774997896964091736687313 =

-1.788854381999831757127338934985

Rounded it is -1.79.

Thanks for using Fixya.

0.44721359549995793928183473374626

Sq Rt of 5 is:

2.2360679774997896964091736687313

0.44721359549995793928183473374626 - 2.2360679774997896964091736687313 =

-1.788854381999831757127338934985

Rounded it is -1.79.

Thanks for using Fixya.

Mar 30, 2010 | SoftMath Algebrator - Algebra Homework...

4(x square) minus 30x plus 3

Dec 16, 2009 | SoftMath Algebrator - Algebra Homework...

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