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Algebra what is the LCM of 12ab squared and 22a squared b

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Without parenthesis, I assume you mean 12 a b^2 and 22 a^2 b.
To do a LCM, just find all the prime factors, select out enough to cover both entries, and multiply together. 12 is 3 * 2 * 2. 22 is 11 * 2. You need two 2's. So you need 2 * 2 * 3 * 11 = 132. And you need 2 a's and 2 b's. Answer 132 a^2 b^2.

Posted on Jun 13, 2008

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What does polynomial function mean?

Let us backtrack so as to better jump.
An algebraic expression may contain one or several algebraic terms, separated by a plus sign or a or a minus and a sign.
Each algebraic term is the product of a constant coefficient and a power of some variable, or the powers of several variables.
Example of an algebraic term 3(x^2)(y^6)....
If the exponents of the various powers are positive integers, the term is called a monomial. In short no square roots, or fractionary powers of the variables appear in monomials. Thus 2/x, 3SQRT(x), or 1/x^5 are not monomials.
Finally, a polynomial is an algebraic expression made up of one or more monomials.
Example P(X)=(1/3)X^7-(SQRT(5)*X^4+ 16X-25 is a polynomial of degree 7 in the indeterminate/variable X
Q(X,Y)= 3(X^3)*Y^2 + 4X-5Y+10 is a polynomial of degree 5 in the variables X and Y.

Oct 01, 2014 | Office Equipment & Supplies

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How would I factor using a TI-86?

its round has lots of squares and has a handle

Sep 11, 2013 | Texas Instruments TI-86 Calculator

1 Answer

Simplify the square root of the fifth root of 64q^8v^6

Square root equivalent to power 1/2
Fifth root equivalent to power 1/5
square root of fifth root (if argument of square root is positive) is equivalent to power 1/10
using 64=2^6 you get 2^(3/5)*q^(4/5)*v^(3/5)

Jul 13, 2013 | SoftMath Algebrator - Algebra Homework...

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What Has The Same Value As Square Root Of 7 Multiply By Square Root Of 15

(Square root(7))*(Square root (15))=(Square root (7*15)=Square root(105)

Mar 29, 2012 | MathRescue Word Problems Of Algebra Lite

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Solve x^2-22x=10

Just complete the square
x^2-22x-10=x^2-2(x)*11+11^2-11^2-10=(x-11)^2-121-10=(x-11)^2- 131.
Use the identity a^2-b^2=(a-b)(a+b) with a=(x-11) and b= square root (131)
Solutions are x1= 11 + square root (131) and x2=11-square root (131).
By the way, the calculator you are refer to cannot perform symbolic algebra calculations.

Nov 30, 2011 | Casio FX-115ES Scientific Calculator

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What are the 7 classifications of special product (algebra)

1. Square of a sum
2. Square of a difference
3. Difference of square (also called product of sum and difference)
4. Cube of a sum
5. Cube of a difference
6. Difference of cube
7. Sum of cube

For more information about each type click this link.

Sep 04, 2011 | Computers & Internet

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Definition of special product in algebra types and example of special product in algebra

Product means the result you get after multiplying.
In Algebra xy means x multiplied by y
Likewise when you see (a+b)(a-b) it means (a+b) multiplied by (a-b), which we will be using a lot here!
Special Binomial Products So when you multiply binomials you get ... Binomial Products
And we are going to look at three special cases of multiplying binomials ... so they are Special Binomial Products.
1. Multiplying a Binomial by Itself What happens when you square a binomial (in other words, multiply it by itself) .. ?

(a+b)2 = (a+b)(a+b) = ... ?

The result:

(a+b)2 = a2 + 2ab + b2
You can easily see why it works, in this diagram:

2. Subtract Times Subtract And what happens if you square a binomial with a minus inside?

(a-b)2 = (a-b)(a-b) = ... ?

The result:

(a-b)2 = a2 - 2ab + b2
3. Add Times Subtract And then there is one more special case... what if you multiply (a+b) by (a-b) ?

(a+b)(a-b) = ... ?

The result:

(a+b)(a-b) = a2 - b2
That was interesting! It ended up very simple.
And it is called the "difference of two squares" (the two squares are a2 and b2).
This illustration may help you see why it works:
apb-amb-why.gif a2 - b2 is equal to (a+b)(a-b) Note: it does not matter if (a-b) comes first:

(a-b)(a+b) = a2 - b2
The Three Cases Here are the three results we just got:
(a+b)2 = a2 + 2ab + b2 } (the "perfect square trinomials") (a-b)2 = a2 - 2ab + b2 (a+b)(a-b) = a2 - b2 (the "difference of squares") Remember those patterns, they will save you time and help you solve many algebra puzzles.
Using Them So far we have just used "a" and "b", but they could be anything.
Example: (y+1)2
We can use the (a+b)2 case where "a" is y, and "b" is 1:

(y+1)2 = (y)2 + 2(y)(1) + (1)2 = y2 + 2y + 1

Example: (3x-4)2
We can use the (a-b)2 case where "a" is 3x, and "b" is 4:

(3x-4)2 = (3x)2 - 2(3x)(4) + (4)2 = 9x2 - 24x + 16

Example: (4y+2)(4y-2)
We know that the result will be the difference of two squares, because:

(a+b)(a-b) = a2 - b2

(4y+2)(4y-2) = (4y)2 - (2)2 = 16y2 - 4
Sometimes you can recognize the pattern of the answer:
Example: can you work out which binomials to multiply to get 4x2 - 9
Hmmm... is that the difference of two squares?
Yes! 4x2 is (2x)2, and 9 is (3)2, so we have:

4x2 - 9 = (2x)2 - (3)2
And that can be produced by the difference of squares formula:

(a+b)(a-b) = a2 - b2
Like this ("a" is 2x, and "b" is 3):

(2x+3)(2x-3) = (2x)2 - (3)2 = 4x2 - 9
So the answer is that you can multiply (2x+3) and (2x-3) to get 4x2 - 9

Jul 26, 2011 | Computers & Internet

1 Answer

Wat is special product

Here, We deal with Some Special Products in Polynomials.

Certain products of Polynomials occur more often
in Algebra. They are to be considered specially.

These are to be remembered as Formulas in Algebra.

Remembering these formulas in Algebra is as important
as remembering multiplication tables in Arithmetic.

We give a list of these Formulas and Apply
them to solve a Number of problems.

We give Links to other Formulas in Algebra.

Here is the list of Formulas in
Polynomials which are very useful in Algebra.
Formulas in Polynomials :

Algebra Formula 1 in Polynomials:

Square of Sum of Two Terms:

(a + b)2 = a2 + 2ab + b2
Algebra Formula 2 in Polynomials:

Square of Difference of Two Terms:

(a - b)2 = a2 - 2ab + b2
Algebra Formula 3 in Polynomials:

Product of Sum and Difference of Two Terms:

(a + b)(a - b) = a2 - b2
Algebra Formula 4 in Polynomials:

Product giving Sum of Two Cubes:

(a + b)(a2 - ab + b2) = a3 + b3
Algebra Formula 5 in Polynomials:

Cube of Difference of Two Terms:

(a - b)3 = a3 - 3a2b + 3ab2 - b3 = a3 - 3ab(a - b) - b3
Algebra Formula 8 in Polynomials:

Each of the letters in fact represent a TERM.

e.g. The above Formula 1 can be stated as
(First term + Second term)2
= (First term)2 + 2(First term)(Second term) + (Second term)2

Jul 02, 2011 | Computers & Internet

1 Answer

The square root of one-fifth minus the square root of 5

Sq. Rt of 1/5 (or .2) is:


Sq Rt of 5 is:


0.44721359549995793928183473374626 - 2.2360679774997896964091736687313 =


Rounded it is -1.79.

Thanks for using Fixya.

Mar 30, 2010 | SoftMath Algebrator - Algebra Homework...

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