Question about Texas Instruments TI-83 Plus Calculator
Parabolas
Open Y= editor and type in the two functions
The calculaus functions are accessible by pressing [2nd][TRACE] to open the CALCulate menu options. For the gradient (I think you mean the derivative) use option 6:dy/dx. But first choose the point where you want it calculated (use cursor to move along the curve) and press ENTER. The value of the deivative will be calculated at the chosen poTI-83 graph problems-help please. - 50e3257.jpg>
TI-83 graph problems-help please. - 24d4168.jpgertex of the parabolas are maxima. Thus yoTI-83 graph problems-help please. - b57bf8d.jpgoption 4:maximum
You will be prompted for a left bound. Move cursor to the left of the maximum (not too far) and press [ENTER]. A fat arrow is displayed on the graph that shows the left limit of the interval. You will be prompted for a right bound. Move cursor along the curve to the right of the the vertex. Press ENTER. A seconf fat arrow will be displayed to show the right limiTI-83 graph problems-help please. - 3b702ee.jpgterval.
You will be prompted foTI-83 graph problems-help please. - 22c11ef.jpgf the maximum. Move cursor newar the max or enter a numerical value and press ENTER.
The location of the vertex is displayed (X and Y values)
I have no idea what you mean by the equation of symmetry
Intercept.
Posted on May 18, 2010
For the Y-intercept , use the Trace function (4th function key). Move the cursor near the point of intersection and read the Y-value. -1E-9 is practically zero. The intercept is at Y=2.
I do not know what you mean by the two graphs are the same because they are not. The second function is 3 times the first. They do intersect the X-axis at the same points. Because if equation 2+3x-2x^2=0 for a certain value of x, then 6+9x-6x^2= 3(2+3x-2x^2) is also equal to zero for the same value.
For the points 2 and 3 regression reread my earlier post answering you question about an exponential regression. Point C shows you how to configure calculator to calculate the correlation coefficient, if one is defined for the regression
Press the [STAT] key then Right arrow to highlight CALC and select the option C:SineReg
Once you have the equation of best fit stored in Y1 you can draw it and use the trace to move the cursor to X=3.5 and read off the value or substitute the value x=3.5 in the equation to calculate the corresponding Y
Concerning the goodness of a fit, only YOU can decide if it is good enough for you: It may help to
draw the scatter plot and the equation of best fit stored in Y1 on the same graph. See my post on exponential regression to review how to draw them on same screen.
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Try contacting the company that manufactured the product.
Posted on Oct 04, 2010
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Posted on Jan 02, 2017
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I have after hours managed to work out how to do question 4 and think that I have the correct answers.
The other 3 I keep still doing something wronge as get error messages. I have viewed lots of you tube videos, but none seem to give me a simple step by step way to to these probems.
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