Question about Microsoft Windows Vista Home Basic for PC

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You are solving for "z". First, bracket the "z" values ad combine them to get this:

17 - (4z+2z) = 13.

This breaks down to:

17 - 6z = 13

Now, subtract 17 from both sides of the equation to get the "z" value isolated and the result is:

-6z = -4 (13-17= -4)

Since both sides are negative, you can drop the signs and get this:

6z = 4

To get the value of "z", divide both sides by 6 and the result is

z = 4/6

Simplify the fraction to z = 2/3.

17 - (4z+2z) = 13.

This breaks down to:

17 - 6z = 13

Now, subtract 17 from both sides of the equation to get the "z" value isolated and the result is:

-6z = -4 (13-17= -4)

Since both sides are negative, you can drop the signs and get this:

6z = 4

To get the value of "z", divide both sides by 6 and the result is

z = 4/6

Simplify the fraction to z = 2/3.

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I AM LOOKING FOR CONROD BOLT TORQUE SETTING FOR A TOYOTA 2Z FORKLIFT

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Soultion: False

unfortunately as an equation that is false, and is not possible

unfortunately as an equation that is false, and is not possible

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Type solve(exp1 and exp2 and exp3, {x,y,z})

See cap images

See cap images

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Go to your matrix button and enter a "3x4" matrix.

Then enter it as follows:

-3 4 5 7

4 3 2 9

-5 5 3 -10

Then exit out and go to "2nd->matrix->math->rref(". Then press enter.

Your screen should look like this:

rref(

Then go to matrix and select your 3x4 matrix, press enter and close it with a parathesis. Your screen should look like this:

rref([A])

Press enter and the screen should say this:

1 0 0 2

0 1 0 -3

0 0 1 5

So,

x=3

y=-3

z=5

Hope this cleared up the confusion!

SJ_Sharks

Then enter it as follows:

-3 4 5 7

4 3 2 9

-5 5 3 -10

Then exit out and go to "2nd->matrix->math->rref(". Then press enter.

Your screen should look like this:

rref(

Then go to matrix and select your 3x4 matrix, press enter and close it with a parathesis. Your screen should look like this:

rref([A])

Press enter and the screen should say this:

1 0 0 2

0 1 0 -3

0 0 1 5

So,

x=3

y=-3

z=5

Hope this cleared up the confusion!

SJ_Sharks

Mar 03, 2009 | Texas Instruments TI-84 Plus Calculator

Consider the following system of **3 equations in 3 unknowns**:

*x + y = *2

**2***x + *3*y + z = *4

*x + *2*y + *2*z = *6Our goal is to transform this system into an equivalent system from which it is easy to find the solutions. We now do this step by step.
* x + y = *2

* y + z = *0

* y + *2*z = *4
*z = *4, *y = *-4, and *x =* 2*-*(*-4*)* = *6Equivalently, we say that the unique solution to this system is **(***x, y, z*) = (6, -4, 4).

- Subtract 2*(Row1) from Row2 and place the result in the second row; subtract Row1 from Row2 and place in the third row. Leave Row1 as is.

- Subtract Row2 from Row3, and place the result in row3. Leave Row1 and Row2 as they are.

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