Question about Texas Instruments TI-83 Plus Calculator

Will the ti83 work simultaneous equations?

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Download the polynomial root finder and Simultaneous Equation Solver Version 2.0 from the TI website. Use the TIConnect software to transfer the application to the calculator. It will be more efficient for you to use it. Here is the link. Enjoy

Posted on May 02, 2010

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Yes. Since there's far too much material for a single post, please refer to the chapter "Matrices" in the Guidebook. If you've misplaced your guidebook, you can download a new one from http://education.ti.com

Posted on Apr 28, 2010

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Posted on Jan 02, 2017

What you want to do is solve the linear equation 2x=10 to find the value of the unknown x that makes the equality true. Solving an equation usually involves rearranging therms, factors and so on. However your calculator was not designed to handle the solution of equations, no matter how simple they are.

Some Casio scientific calculators can solve some types of equations (polynomials of degree 2 or 3, simultaneous linear equations in up to 3 unknowns). These are the FX-115 ES (Plus) and FX-991 ES (Plus C). Other equivalent models are sold in the world under different names.

Some Casio scientific calculators can solve some types of equations (polynomials of degree 2 or 3, simultaneous linear equations in up to 3 unknowns). These are the FX-115 ES (Plus) and FX-991 ES (Plus C). Other equivalent models are sold in the world under different names.

Oct 16, 2013 | Casio FX350MS Scientific Calculator

Most probable that you are not using the correct syntax.

Press MATH, then scroll down to reach the SOLVER line. Press ENTER. Create the equation, using the ALPHA keyboard to type in letter symbols.

Press ENTER. The screen that opens displays the equation and a list of the variable present in your equation. Each letter (variable) must have a value, except the unknown. If there is a 0 after the = sign on the same line as the unknown, you must clear it so as to leave a blank.

Specify the lower bound and the upper bound to speed up the search.

Once finished press [ALPHA][ENTER] to execute the (SOLVER)

Press MATH, then scroll down to reach the SOLVER line. Press ENTER. Create the equation, using the ALPHA keyboard to type in letter symbols.

Press ENTER. The screen that opens displays the equation and a list of the variable present in your equation. Each letter (variable) must have a value, except the unknown. If there is a 0 after the = sign on the same line as the unknown, you must clear it so as to leave a blank.

Specify the lower bound and the upper bound to speed up the search.

Once finished press [ALPHA][ENTER] to execute the (SOLVER)

Oct 20, 2011 | Texas Instruments TI-83 Plus Calculator

The simultaneous equation solver requires the coefficients to be real. Similarly matrices must have real coefficients.

Your only alternative is to express each of A and B as a real part and imaginary part.

A= x1+iy1

B=x2+iy2.

Substitute x1+iy1 for A in the two equations. Substitute x2+iy2 for B in the two equations. Do the algebra. Gather real parts and gather imaginary parts. Split each original equation into two equations: One equation comes from setting Real Part of left side = real part of right side (1); the other equations comes from setting the imaginary part of left side= imaginary part of right side (here 0).

Do the same procedure for the 2nd original equation.

At the end of the process you will have 4 coupled linear equations in the 4 unknowns (x1,y1,x2,y2).

Then you might want to use the calculator to solve the derived system. Once you have x1,y1,x2,y2 you reconstruct A=x1+iy1, etc.

Your only alternative is to express each of A and B as a real part and imaginary part.

A= x1+iy1

B=x2+iy2.

Substitute x1+iy1 for A in the two equations. Substitute x2+iy2 for B in the two equations. Do the algebra. Gather real parts and gather imaginary parts. Split each original equation into two equations: One equation comes from setting Real Part of left side = real part of right side (1); the other equations comes from setting the imaginary part of left side= imaginary part of right side (here 0).

Do the same procedure for the 2nd original equation.

At the end of the process you will have 4 coupled linear equations in the 4 unknowns (x1,y1,x2,y2).

Then you might want to use the calculator to solve the derived system. Once you have x1,y1,x2,y2 you reconstruct A=x1+iy1, etc.

Aug 29, 2011 | Casio FX-9860G Graphic Calculator

The absolutely-best, most-robust, software for solving systems of linear equations is the LINPACK software library.

It was originally written in FORTRAN.

But, see: http://www.greenecomputing.com/apps/linpack/

which indicates that a JAVA version exists.

It was originally written in FORTRAN.

But, see: http://www.greenecomputing.com/apps/linpack/

which indicates that a JAVA version exists.

Mar 02, 2011 | Computers & Internet

There are a few routines to solve simultaneous LINEAR equations that are embedded in the Operating system of the calculator.

If you need download and install instructions, you will find them here.

- solve(
- Simult(

If you need download and install instructions, you will find them here.

Aug 01, 2010 | Texas Instruments TI-89 Calculator

Press the [MODE] button 3 times then 1 to enter EQN mode. Then press the right pointing arrow. You can select the degree of the polynomial (2 or 3) or press again the right pointing arrow to select the number of unknowns for simultaneous linear equations( 2 or 3).

The form of the equations are as follows.

The form of the equations are as follows.

Jul 15, 2010 | Casio FX-115ES Scientific Calculator

You can use symbols (X,Y,A,B,C,D, and M, =) to create expressions to use
in the SOLV program or to generate a table of values.

To type them you use [ALPHA] followed by the symbol you want. The symbols on the body of the calculator are of the same color as the ALPHA key. The [=] in expressions is different from the general = sign at the bottom of the keypad.

There are also some typical equations already in the calculator: simultaneous linear equation in 2 or 3 unknowns, and polynomial equations of 2nd and 3rd degree. They are accessed under the EQUATion Mode.

To type them you use [ALPHA] followed by the symbol you want. The symbols on the body of the calculator are of the same color as the ALPHA key. The [=] in expressions is different from the general = sign at the bottom of the keypad.

There are also some typical equations already in the calculator: simultaneous linear equation in 2 or 3 unknowns, and polynomial equations of 2nd and 3rd degree. They are accessed under the EQUATion Mode.

Jun 21, 2010 | Casio FX-115ES Scientific Calculator

Hello,

Let us assume you have two simultaneous linear equations :

**a_1*x+ b_1*y+c_1=0**

a_2*x +b_2*y+c_2=0

where a_1, a_2, b_1, b_2, c_1,c_2 are coefficients (numerical or algebraic).

The problem is to obtain the particular values of the unknowns x and y for which the two equations are both satisfied: If you substitute the particular values of x and y you find in any of the two equations you discover that both equalities are true.

A small system of equations like the one above can be solved by some very simple algorithms (elimination, substitution, combination) which can be carried out by hand.

The solution of large systems of linear equations can be sought by making use of the concepts of matrices (plural of matrix), determinants, and certain rules called Cramer's rules.

Due to its repetitive nature, the algorithm ( a well defined, limited sequence of steps) is suitable for a calculating machine (computer or calculator).

Certain calculators have, embedded in their ROM, a program that solves linear systems of simultaneous equations. Usually you are asked to enter the values of the coefficients a_1, etc. in a set order, then you press ENTER or EXE (Casio) . If a solution exits (not all linear systems have solutions) the calculator displays it.

Hope that satisfies your curiosity.

Let us assume you have two simultaneous linear equations :

a_2*x +b_2*y+c_2=0

where a_1, a_2, b_1, b_2, c_1,c_2 are coefficients (numerical or algebraic).

The problem is to obtain the particular values of the unknowns x and y for which the two equations are both satisfied: If you substitute the particular values of x and y you find in any of the two equations you discover that both equalities are true.

A small system of equations like the one above can be solved by some very simple algorithms (elimination, substitution, combination) which can be carried out by hand.

The solution of large systems of linear equations can be sought by making use of the concepts of matrices (plural of matrix), determinants, and certain rules called Cramer's rules.

Due to its repetitive nature, the algorithm ( a well defined, limited sequence of steps) is suitable for a calculating machine (computer or calculator).

Certain calculators have, embedded in their ROM, a program that solves linear systems of simultaneous equations. Usually you are asked to enter the values of the coefficients a_1, etc. in a set order, then you press ENTER or EXE (Casio) . If a solution exits (not all linear systems have solutions) the calculator displays it.

Hope that satisfies your curiosity.

Aug 12, 2009 | Sharp EL-531VB Calculator

To view both graphs, the = signs on both y1 and y2 must be contained in black boxes. If you put your cursor over the = sign on the second equation and hit enter, it turns that graph off and you won't be able to see anything but the equation in y1 line. If there is not black box around the = sign of any equation in any of the lines you have typed an equation into, you will not see the graph.

Aug 12, 2009 | Texas Instruments TI-84 Plus Calculator

Here is a site dedicated to teaching simultaneous equations. Hopefully that'll help.

http://www.themathpage.com/alg/simultaneous-equations.htm

-John

http://www.themathpage.com/alg/simultaneous-equations.htm

-John

Aug 31, 2007 | Sony Playstation 3 (PS3) Console

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Usually answered in minutes!

by equations, do you mean functions of x? as in "f(x)=2sin(x)", or do you mean calculate answers of one equation by using another "rule" to solve it?

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