Question about MPS Multimedia Speedstudy Pre Calculus Full Version for PC

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Log3(u^2/v)

You can move the top as an exponent because of the rules of logs. Then subtracting two same base logs can be combined because another rule. If they are subtracting you divide them and if they adding you multiply them.

Posted on Jun 15, 2011

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Posted on Jan 02, 2017

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The Casio FX-300MS does not provide base 2 logarithms as a single key operation. However, you can use the natural logarithm (ln, base e = 2.7182818...) and the formula

log2 ( x ) = ln( x ) / ln( 2 )

To calculate the base 2 logarithm of 16, key in

[ln] 16 [/] [ln] 2 [=]

and get displayed the correct answer 4.

The same simple formula also works for any other base, and actually for any other logarithms provided by your calculator. The FX-300MS also provides a logarithm to base 10 (lg). You could also

type

[lg] 16 [/] [lg] 2 [=] to get the solution to the problem above, or

[lg] 25 [/] [lg] 5 [=] to get the base 5 logarithm of 25.

log2 ( x ) = ln( x ) / ln( 2 )

To calculate the base 2 logarithm of 16, key in

[ln] 16 [/] [ln] 2 [=]

and get displayed the correct answer 4.

The same simple formula also works for any other base, and actually for any other logarithms provided by your calculator. The FX-300MS also provides a logarithm to base 10 (lg). You could also

type

[lg] 16 [/] [lg] 2 [=] to get the solution to the problem above, or

[lg] 25 [/] [lg] 5 [=] to get the base 5 logarithm of 25.

Mar 20, 2014 | Casio FX-300MS Calculator

Simplifications of logarithmic expressions are based on the properties of logarithms

log(1)=0

log(a/b)=log(a)-log(b)

log(a^n)=n*log(a)

log_b(x)=log(x)/log(b)=ln(x)/ln(b)

As to exponentials you have

e^(0)=1

e^(-a)=1/(e^a)

(e^a)*(e^b)=e^(a+b)

(e^a)^n=e^(na)

That is the gist of it.

But I do not think that your calculator is able to handle any scientific calculations.

log(1)=0

log(a/b)=log(a)-log(b)

log(a^n)=n*log(a)

log_b(x)=log(x)/log(b)=ln(x)/ln(b)

As to exponentials you have

e^(0)=1

e^(-a)=1/(e^a)

(e^a)*(e^b)=e^(a+b)

(e^a)^n=e^(na)

That is the gist of it.

But I do not think that your calculator is able to handle any scientific calculations.

Sep 26, 2013 | Casio Model Dl-250la Heavy Duty Black/red...

The TI 86 has two logarithmic functions: natural logarithm **(ln) **and common (decimal) logarithms **(log)**. If you need the logarithm in any other base than e or 10 you need to use one of the two equivalent expressions

**log_b(x) =ln(x)/ln(b) =log(x)/log(b)**

Here b is the value of the base of the logarithm and x is the argument (the value whose logarithm you are seeking). Of course the argument x must be a positive number.

**Note:** On the TI 86 the log function can calculate the logarithm of a complex number, according to the manual.

Here b is the value of the base of the logarithm and x is the argument (the value whose logarithm you are seeking). Of course the argument x must be a positive number.

Sep 22, 2013 | Texas Instruments TI-86 Calculator

The 30XA only has logarithm functions for base e and base 10. However, you can calculate the logarithm to any base by using the relationship logb x = log x / log b = ln x / ln b

To calculate log3 of 9, press

9 LOG / 3 LOG =

or

9 LN / 3 LN =

To calculate log3 of 9, press

9 LOG / 3 LOG =

or

9 LN / 3 LN =

Apr 03, 2011 | Texas Instruments TI-30XA Calculator

The TI-30 XIIS, like most calculators, cannot do logarithms to base 5 directly. You need to apply the formula:

To calculate the logarithm at base 5 of 25, you key in: 25 [log] [ ÷] 5 [log] [=]

To calculate the logarithm at base 5 of 25, you key in: 25 [log] [ ÷] 5 [log] [=]

Jan 11, 2011 | Texas Instruments TI-30 XIIS Calculator

The 30XIIS does not have the capability of solving equations. It can, however, calculate expressions using logarithms. Use the LOG key for common logarithms and the LN key for natural logarithms. In both cases, press the function key, enter the value or expression, and then ) to match the ( the function automatically enters.

The LOG and LN keys are the second and third keys from the top in the leftmost column of the keyboard.

The LOG and LN keys are the second and third keys from the top in the leftmost column of the keyboard.

Nov 13, 2010 | Office Equipment & Supplies

For common logarithm use the LOG key just below the blue 2nd key. For natural logarithm use the LN key just below the LOG key.

In either case, press the appropriate key, then type in the expression whose log you want, then the ) key. Type in whatever else there might be in the total expression, then the ENTER key.

For example, to calculate the natural log of 2:

LN 2 ) ENTER

In either case, press the appropriate key, then type in the expression whose log you want, then the ) key. Type in whatever else there might be in the total expression, then the ENTER key.

For example, to calculate the natural log of 2:

LN 2 ) ENTER

Aug 16, 2010 | Texas Instruments TI-30 XIIS Calculator

Your calculator knows only the decimal logarithms log or log_10 and the natural logarithms (ln or log in base e).

So you cannot compute directly the logarithms in any bases other than 10 and e.

A workaround consists in using the relation

log in base b of a number a (log_b (a))

log_b(a)= (log_10(a) ) / (log_10 (b))

or the relation

log_b(a)= ln(a)/ln(b)

log_2(0.3)=log(0.3)/log(2) where log is log in base 10

Similarly

log_2(0.3)=ln(0.3)/ln(2)

As to the multiplicative factor you had at the beginning of your expression, just multiply the value obtained by one on the formulas above (both formulas will give the same result) by 0.3

So you cannot compute directly the logarithms in any bases other than 10 and e.

A workaround consists in using the relation

log in base b of a number a (log_b (a))

log_b(a)= (log_10(a) ) / (log_10 (b))

or the relation

log_b(a)= ln(a)/ln(b)

log_2(0.3)=log(0.3)/log(2) where log is log in base 10

Similarly

log_2(0.3)=ln(0.3)/ln(2)

As to the multiplicative factor you had at the beginning of your expression, just multiply the value obtained by one on the formulas above (both formulas will give the same result) by 0.3

Jul 18, 2010 | Casio FX-115ES Scientific Calculator

Press LOG for common (base-10) logarithm or LN

Jul 04, 2010 | Texas Instruments TI-83 Plus Calculator

There are very few instances where you have two press two keys AT THE SAME TIME, the most notable of them is when you want to force the calculator into the BOOT SCREEN. Most key combinations are key sequences, meaning you press a key and THEN press another.

This said, let us get back to your question.

When you apply a function on an expression, then apply the inverse of the function on the result you get the original expression back.

If f is a function and f^-1 its inverse, by definition f^-1[f(x)]=f[f^-1(x)] =x

As you can see you do not need a calculator to find the result.

Concerning the logarithmic functions

For the natural logarithms (logarithms in base e) labeled [ln], the inverse of the logarithm is the exponential function e^

ln[e^(x)] =e^[ln(x)] =x

For the common logarithms (logarithms in base 10), labeled [log], the inverse function of the log is the raising 10 to the power of. It is usually called the antilogarithm or antilog.

y= log(x) is equivalent to x=10^(y)

Try the following exemple

log(14) = 1.146128036

10^(1.146128036) =14

To access the 10^x function you press [2nd][LOG]

To access the exponential function you press [2nd][LN]

This said, let us get back to your question.

When you apply a function on an expression, then apply the inverse of the function on the result you get the original expression back.

If f is a function and f^-1 its inverse, by definition f^-1[f(x)]=f[f^-1(x)] =x

As you can see you do not need a calculator to find the result.

Concerning the logarithmic functions

For the natural logarithms (logarithms in base e) labeled [ln], the inverse of the logarithm is the exponential function e^

ln[e^(x)] =e^[ln(x)] =x

For the common logarithms (logarithms in base 10), labeled [log], the inverse function of the log is the raising 10 to the power of. It is usually called the antilogarithm or antilog.

y= log(x) is equivalent to x=10^(y)

Try the following exemple

log(14) = 1.146128036

10^(1.146128036) =14

To access the 10^x function you press [2nd][LOG]

To access the exponential function you press [2nd][LN]

Jan 06, 2010 | Texas Instruments TI-84 Plus Calculator

Feb 26, 2010 | MPS Multimedia Speedstudy Pre Calculus...

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