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C++ can u give me full programme to generate palindrome numbers

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Class Tester100
{

public static void main(String[] args)
{
for (int i =100; i<=999; i++)
System.out.println("palindrome"+=((i/100)+""+((i/10)%10)+""+(i%10)+""+((i/10)%10)+""+(i/100)));

}

Posted on Mar 22, 2008

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What is the palindrome of 49


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A number is a palindrome or not, 49 is not one.

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I am also a palindrome.I am greater than the number of days in a year and less than the product of 19 and 20.What number am I?


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here is a little vbscript sample str=InputBox("Type String To check For palindrome","")
strR=StrReverse(str)
half=Int(Len(str)/2)
If Left(str,half)=Left(strR,half) Then
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Is it possible to use the random number function to simulate a dice - so the calculator gives numbers between 1 and 6.


Hello,
The random number function Rand# generates numbers between 0 and 1. The calculator is not programmable, so I do not see an easy way to make it simulate the throw of a dice.
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It is up to you.

Hope it helps.

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1 Answer

To find palindrome


// String s contains word to check
boolean palindrome = false;//always false until proven otherwise
int i=0;
int len = s.length();
int halflen = (int)len/2;
for (i=0;i<len/2;i++)
if (s.charAt(i)!=s.charAt(len-i-1))
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if (i==halflen)
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To print palindrome


// String s contains word to check
boolean palindrome = false;//always false until proven otherwise
int i=0;
int len = s.length();
int halflen = (int)len/2;
for (i=0;i<len/2;i++)
if (s.charAt(i)!=s.charAt(len-i-1))
break;
if (i==halflen)
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1 Answer

C++ programming


I hope this helps.
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()


{
clrscr();
char s[100];
int i,j,l,flag;
printf("\n enter a string:");
gets(s);
l = strlen(s);
j= l-1;
for(i=0;i<=j;i++,j--)


{
if(s[i]==s[j])


{
flag=1;
}
else
{ flag=0;
goto sar;
}
}
if(flag==1)


{
printf("\n string is palindrome");
}
else
sar:
printf("\n string is not a palindrome");
getch();
}

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C++ program


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Help me javascript just mail me at ramzy_213@yahoo.com thanx


hello there!!!
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O S

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