I have a Lakewood Oil-filled radiator Model 6500 which has stopped working. After opening the unit, I found the fuse wrapped in the black tape casing to be open. Can you let me know what is the fuse rating and where I can get it ?
Thanks
Siva
Your heater will probably work if the fuse your referring to is the same thing as what they call a Thermal Coupler. I don't think it regulates the heat in any way, so just by cutting out the coupler and bypassing it should give you power to the unit and it should work fine. However, be aware that there is not a fuse inline anymore and there's no way for the unit to cut the 110 volts your feeding it out of your wall, which could potentially cause a fire. So if you do it, I would not leave the heater unattended, at least until after a long period of time has past and you trust it enough. Better yet, you could use a fuse in its place, as far as the amp it would be, I would start out with a low amp fuse first, then turn the heater on low. If it does not blow, turn the heater up gradually to see if it will blow. If by the time you have the heat setting on high and its been on for a period of time and its good and hot, still not blowing the fuse. I would decrease the amps of the fuse until it blew the fuse.. When you get the heater to blow a fuse then put a fuse it it, that is slightly larger than the one it blew and it "MIght" be fine. Im not telling you to do this, but I myself would try it. Peace Out.....
Thats a thermal limit, youre heaters junk!
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