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Maths find the coefficient ofx2 (x-1) (x-3) (2x+3)

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2x+7y-16=0

Posted on Aug 16, 2008

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The three x^2 coeficients are 3 -6 -2. Add them together. Answer -5.

Posted on Jun 13, 2008

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Mather chod

Posted on Mar 08, 2008

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1 Answer

Simplify 3 · 2x. What is the coefficient?


Do the operation 3*2=6. Put the 6 in front of x. 6 is the coefficient
The result, in simplified form, is 6x

Mar 26, 2014 | Office Equipment & Supplies

1 Answer

Casio FX - 9860G SD have complex equations?? edit


The Casio FX-9860G SD can solve a polynomial equation of degree 2 or 3 with REAL coefficients. If the complex MODE is set to REAL it will find the real roots. If the complex mode is set to a+ib, it will find the real and complex roots.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Addendum.
The calculator CANNOT solve equations with complex coefficient. YOU can however convert the system of linear equations with ccomplex coefficients ( of the type you show) as a system of 4 linear equations in 4 unknowns; Split x into a real and an imaginary part, split y into a real and an imaginary part. Substitute Real(x)+iIm(x) for variable x in the equations; substitute Real(y)+iIm(y) for y in the two equations; do the algebra. In each of the original equations split the Real and imaginary parts. You should be able to derive 4 linear equations in unknowns Real(x), Im(x), Real(y), and Im(y).
Use the linear equation solver to obtain the solutions. Recompose x=Real(x)+iIm(x), and y=Real(y)+iIm(y)

Mar 17, 2012 | Casio Office Equipment & Supplies

1 Answer

Casio FX - 9860G SD have complex equations??


Your question (?) is not clear so I will not try to guess what you really mean.
Be it as it may, the Casio FX-9860G SD can solve a polynomial equation of degree 2 or 3 with REAL coefficients. If the complex MODE is set to REAL it will find the real roots. If the complex mode is set to a+ib, it will find the real and complex roots.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Mar 16, 2012 | Casio Office Equipment & Supplies

1 Answer

Casio FX - 9860G SD have complex equations??


Your question (?) is not clear so I will not try to guess what you really mean.
Be it as it may, the Casio FX-9860G SD can solve a polynomial equation of degree 2 or 3 with REAL coefficients. If the complex MODE is set to REAL it will find the real roots. If the complex mode is set to a+ib, it will find the real and complex roots.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Mar 16, 2012 | Casio FX-9750GPlus Calculator

1 Answer

Graph y=x2-4x+3.? what answer?


y=x2-4x+3
here,a=1(coefficient of x2)
b=-4(coefficient of x)
c=3(the constant term)
as this is a quadratic equation this will have two solutions
solution 1=(-b+square root of(b2-4ac))/2a
=(-(-4)+square root of(16-4*a*c)/2*1
=3
solution 2=(-b-square root of(b2-4ac))/2a
=1

Aug 07, 2011 | TOPICS Entertainment Snap! Geometry...

2 Answers

TI-89 Titanium: I want to solve a Binomial Theorem problem (x+y)^6 how would i go about solving this in the calculator?


Using elementary algebria in the binomial theorem, I expanded the power (x + y)^n into a sum involving terms in the form a x^b y^c. The coefficient of each term is a positive integer, and the sum of the exponents of x and y in each term is n. This is known as binomial coefficients and are none other than combinatorial numbers.

Combinatorial interpretation:

Using binomial coefficient (n over k) allowed me to choose k elements from an n-element set. This you will see in my calculations on my Ti 89. This also allowed me to use (x+y)^n to rewrite as a product. Then I was able to combine like terms to solve for the solution as shown below.
(x+y)^6= (x+y)(x+y)(x+y)(x+y)(x+y)(x+y) = x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

This also follows Newton's generalized binomial theorem:


oneplusgh_15.jpg
Now to solve using the Ti 89.


Using sigma notation, and factorials for the combinatorial numbers, here is the binomial theorem:

oneplusgh.gif

The summation sign is the general term. Each term in the sum will look like that as you will see on my calculator display. Tthe first term having k = 0; then k = 1, k = 2, and so on, up to k = n.
Notice that the sum of the exponents (n ? k) + k, always equals n.



oneplusgh_26.jpg


The summation being preformed on the Ti 89. The actual summation was preformed earlier. I just wanted to show the symbolic value of (n) in both calculations. All I need to do is drop the summation sign to the actual calculation and, fill in the term value (k), for each binomial coefficient.



oneplusgh_18.jpg

This is the zero th term. x^6, when k=0. Notice how easy the calculations will be. All I'm doing is adding 1 to the value of k.


oneplusgh_19.jpg

This is the first term or, first coefficient 6*x^5*y, when k=1.
Solution so far = x^6+6*x^5*y



oneplusgh_20.jpg


This is the 2nd term or, 2nd coefficient 15*x^4*y^2, when k=2.
Solution so far = x^6+6*x^5*y+15*x^4*y^2



oneplusgh_27.jpg



This is the 3rd term or, 3rd coefficient 20*x^3*y^3, when k=3.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3



oneplusgh_28.jpg



This is the 4th term or, 4th coefficient 15*x^2*y^4, when k=4.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4



oneplusgh_21.jpg


This is the 5th term or, 5th coefficient 6*x*y^5, when k=5.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5



oneplusgh_22.jpg

This is the 6th term or, 6th coefficient y^6, when k=6.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5+y^6



oneplusgh_23.jpg

Putting the coefficients together was equal or, the same as for when I used the expand command on the Ti 89.

binomial coefficient (n over k) for (x+y)^6
x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5+y^6












Jan 04, 2011 | Texas Instruments TI-89 Calculator

1 Answer

How to solve matices as in finding the values to


I assume you want to solve a linear system of three equations i three unknowns (x,y,z).

  1. Turn calculator ON.
  2. If you do not see icons, press [MENU] key.
  3. Use arrows to move focus to [EQUA] and press [EXE]
  4. In new screen select F1: Simultaneous
  5. Select the numbewr of unknows (in your case 3): Press [F2:3]
  6. A table opens: it has 3 rows and 4 columns
  7. Enter the coefficients in first equation on first line (a1, b1,c1) and the constant term d1.
  8. Enter the other coefficients and the constant terms at the right places, pressing [EXE] after each entry.
  9. When finished coefficients and constant terms, press [F1:Solv]
  10. The solution vector (X,Y,Z) is displayed on next screen.
  11. Note: if the coefficients are integers, it is possible that the solution vector will be displayed as mixed fractions (exact solutions),
  12. If not, the solution vector will be in decimal format.
82a2c0e.jpge69b451.jpgac9ab46.jpg

f79e545.jpg

Mar 02, 2010 | Casio FX-9750GPlus Calculator

2 Answers

Steps in solving matrix on my ti 89 calculator.


I assume you are speaking of solving a system of equations with a number of unknowns. If not, please correct me. Here's an example in practice:

If you have a system of 3 equations with 3 unknowns, you would set up your matrix so that the coefficients of each variable for a particular equation are on one row. So, given equations x + y + z = 0, 2x + 3y - 4z = 1, x + -z = -1 you would type the following into your calculator: [[1,1,1,0][2,3,-4,1][1,0,-1,-1]] and press enter to make sure you typed it correctly. notice that in the third row there is a zero, since we have zero time y for the third equation. Then row-reduce the matrix (2nd > 5 > 4 > 4 or in the CATALOG as rref). You should get out the matrix [[1,0,0,-1][0,1,0,1][0,0,1,0]]. This says that x=-1 y = 1 z=0 since my first column contained the coefficients for the x variable, the second for the y variable, and the third for the z variable. The last column contains the solution, the part on the other side of the equals sign.

Hope this helps! For more reading (from someone else; I just made this one up), check out the Wikipedia articles on Gaussian elimination and Systems of linear equations

May 03, 2009 | Texas Instruments TI-84 Plus Calculator

2 Answers

Factoring polynomials "Algebra"


Mode>choose "5"
choose equation format "4"
input the coefficient for a which is "1" and hit "="
input the coefficient for b which is "4" and hit "="
input the coefficient for c which is "3" and hit "="
input the coefficient for d which is "12" and hit "="
Hit "=" for X1
Hit "=" again for X2
Hit "=" again for X3

Nov 18, 2007 | Casio Office Equipment & Supplies

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