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O/p plzzzzzzz help me What does the code "cout<<(0==0);" print?

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What is the limit for cout.

Posted on Feb 26, 2008


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1 Answer

Create a class called date and a child called time in c++


Where to begin?
Easy: FIND SUITABLE LIBRARY
answer is easy, but finding is hard enough.
Hopefully c++ standart has time.h that has functions you need.
Without any talking source code below:
I created 2 files: data.h which has classes and functions and main.cpp :)

-----------------data.h-----------------
#ifndef _DATA_H_
#define _DATA_H_

#include <time.h>

class Data
{
public:
time_t rawtime; // time.h requres this
struct tm *timeinfo; // and this also
public:
Data(); // constructor
int getMonth();
int getDay();
int getYear();
char *getAll();
};


class Time : public Data // child funqcion
{
public:
int getH();
int getM();
int getS();
};

Data::Data() // copy of constructor
{
time(&rawtime);
timeinfo = localtime(&rawtime);
}

int Data::getMonth()
{

return timeinfo->tm_mon;
}

int Data::getDay()
{
return timeinfo->tm_wday;
}

int Data::getYear()
{
return timeinfo->tm_year;
}

char *Data::getAll()
{
return asctime(timeinfo);
}

int Time::getH()
{
return timeinfo->tm_hour;
}

int Time::getM()
{
return timeinfo->tm_min;
}

int Time::getS()
{
return timeinfo->tm_sec;
}

#endif
----------------------END OF FILE--------------------
I hope you know include file rule when working with multiple files. I mean you understand #ifndef and #define...

and the main.cpp:

#include "data.h"
#include <iostream>

//I hope you understand all this...

using namespace std;

Data myData;
Time myTime;
const char *months[12] =
{
"January",
"Febryary",
"March",
"April",
"May",
"June",
"Jule",
"August",
"September",
"October",
"November",
"December",
};

const char *days[7] =
{
"Sunday",
"Monday",
"Tuesday",
"Wednesday",
"Thursday",
"Friday",
"Saturday",
};

int gmonth;
int gday;
int gyear;
int ghour;
int gmin;
int gsec;
char *compact; // why char *compact and not char compact? because Data.getAll returns *char

int main(int argc, char *argv[])
{
cout << "Getting month...\n";
gmonth = myData.getMonth();
cout << "Current month: " << months[gmonth];
cout << endl;
cout << "Getting week day...\n";
gday = myData.getDay();
cout << "Current week day: " << days[gday];
cout << endl;
cout << "Getting year...\n";
gyear = myData.getYear() + 1900; // +1900 is necessary :) because year is calculating after 1900
cout << "Current year: " << gyear;
cout << endl;
cout << "Getting hour...\n";
ghour = myTime.getH();
cout << "Current hour: " << ghour;
cout << endl;
cout << "Getting minutes...\n";
gmin = myTime.getM();
cout << "Current minutes: " << gmin;
cout << endl;
cout << "Getting seconds...\n";
gsec = myTime.getS();
cout << "Current seconds: " << gsec;
cout << endl;
cout << endl;
compact = myData.getAll(); // Coolest one :)
cout << compact << endl;
system("PAUSE");
return EXIT_SUCCESS;
}
----------------END OF FILE--------------------
I clearly don't understand what set hours, minutes, secs mean:'
Tested and working.
If you have any questions write comment.
I compiled this project in DevCpp, but it will work for Visual Studio too.
This might be different what you expected but solve any problem AS EASY AS POSSIBLE in programming. Solve problem i mean everything is working.

Aah, I've written a lot :)
Please rate my solution...
And Successful Programming!

May 08, 2012 | HP Computers & Internet

1 Answer

What is the source code having an output of 1 21 321 using for loop statement in microsoft visual c++?


I believe you're asking for a loop that will output that sequence specifically. One way to go about it is with the following code:

for (int i = 0; i < 3; i++)
{
if (i == 0)
cout << i+1 << endl;
else if (i == 1)
cout << i + 1 << i << endl;
else
cout << i +1 << i << i - 1 << endl;
}

I know the hard coded numbers is a bit inelegant, but in this case this snippet of code will solve the problem.

Aug 24, 2011 | Microsoft Visual C++ 6.0 Professional...

1 Answer

Write a program to sum of all even integer numbers


#include <iostream>
using namespace std;
int main ()
{
int num = 0, i = 1, sum = 0;
cout << "Enter a positive integer: ";
cin >> num;
while (i <= num)
{
sum += i;
i++;
}
cout << "The sum is " << sum << endl;
return 0;
}

Oct 30, 2010 | Compaq Visual Fortran Professional Edition...

1 Answer

How i make calculator by using source code in c++?


hi,
here is the code u looking for

#include <iostream.h>
using namespace std;
float sub (float a, float b)
{
float dif;
dif=a - b;
return dif;
}

float addition (float c, float d)
{
float sum;
sum=c+d;
return sum;
}

float divi (float e, float f)
{
float quo;
quo = e/f;
return quo;
}
float multi (float f, float g)
{
float pro;
pro=f * g;
return pro;
}

int main ()
{
float a;
float b;
float opt;

cout << "Welcome to the calculator" << endl;
cout << "There are four options " << endl;
cout << "Option 1 is subtraction, Option 2 is addition, option 3 is division, and option 4 is multiplication " << endl;
cout << "Enter your option and two digits " << endl;
cin >> opt >> a >> b;


if (opt == 1)
{
float temp= sub (a, b);
cout << "Your difference is " << temp << endl;
}

else
if (opt==2)
{
float temp2= addition (a, b);
cout << "Your sum is " << temp2 << endl;
}
else
if (opt == 3)
{
float temp3= divi (a,b);
cout << "Your quotient is " << temp3 << endl;
}
else
if (opt == 4)
{
float temp4= multi (a,b);
cout << "Your product is " << temp4 << endl;
}
else
{
cout << "That function is not supported in calculator!" << endl;
}
cout << "Thank you for using calculator" << endl;

return 0;
}

Thanks!

Mar 19, 2009 | Microsoft Computers & Internet

1 Answer

Do while


Hi,

a very simple example scriptlet:

#include <iostream>

int main()
{
using namespace std;

int i=1;

do
{
cout << "value of i:" << i << endl;
} while (i<=10);
return 0;
}


Thanks.

Mar 17, 2009 | Microsoft Visual Basic 6.0 for PC

2 Answers

C++ problem


When it comes to else, if, or else-if statements, once you understand how they work you will be laughing. It is not very difficult to understand, and for all C/C++ programmers (New or Experienced alike) I would suggest reading the information and tutorials located at http://www.cprogramming.com/tutorial.html

This is a great resource site for any C/C++ programmers out there, especially if you have been single tasked and forgot how to do something.

Feb 13, 2009 | Microsoft Computers & Internet

2 Answers

C++ program for insertion, deletion in linked list and 2d array pls send the details for linked list so that i can understand it the best..considering me as a beginner.


program for deletion


#include<iostream.h>
void main()
{
int a[10],i,n,x;
cout<<"\n\t\tPROGRAM TO DELETE AN NUMBER FROM AN ARRAY";
cout<<"\nEnter the size of the array:";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"\nEnter the number:";
cin>>a[i];
}
cout<<"\nEnter the position to be deleted:";
cin>>x;
for(i=x;i<n;i++)
a[i]=a[i+1];
for(i=0;i<n-1;i++)
cout<<a[i]<<" ";
}

Oct 13, 2008 | Computers & Internet

3 Answers

C programming coading


1
2 2
3 3 3
4 4 4 4
5 5 5 5 5

Apr 30, 2008 | Computers & Internet

2 Answers

C++ programs


An array is a series of elements of the same type placed in contiguous memory locations that can be individually referenced by adding an index to a unique identifier
Initializing arrays. When declaring a regular array of local scope (within a function, for example), if we do not specify otherwise, its elements will not be initialized to any value by default, so their content will be undetermined until we store some value in them. The elements of global and static arrays, on the other hand, are automatically initialized with their default values, which for all fundamental types this means they are filled with zeros
include <iostream>
using namespace std;

int billy [] = {16, 2, 77, 40, 12071};
int n, result=0;

int main ()
{
for ( n=0 ; n<5 ; n++ )
{
result += billy[n];
}
cout << result;
return 0;
}
multidimensional array pseudo-multidimensional array #define WIDTH 5 #define HEIGHT 3 int jimmy [HEIGHT][WIDTH]; int n,m; int main () { for (n=0;n<HEIGHT;n++) for (m=0;m<WIDTH;m++) { jimmy[n][m]=(n+1)*(m+1); } return 0; } #define WIDTH 5 #define HEIGHT 3 int jimmy [HEIGHT * WIDTH]; int n,m; int main () { for (n=0;n<HEIGHT;n++) for (m=0;m<WIDTH;m++) { jimmy[n*WIDTH+m]=(n+1)*(m+1); } return 0; }
and now for trignometry
#include<iostream>
#include<cmath>
using namespace std;

int main()
{
int factorial(int);
int n = 3, i = 1;
double x, x2, b, PI, r;
char choice;
//r = x * (PI / 180)

cout<<"Please enter an angle value => ";
cin>>x;
cout<<"Is the angle value in Degree or Radian?"<<endl;
cout<<"Type D if its in degree "<<endl;
cout<<"Type R if its in radian "<<endl;
cin>>choice;


if((choice = 'R')||(choice = 'r'))
do{
i++; n = 3; x2 = 0; b = x2;
{
if(i == 1)
x2 = x - (pow(x,n) /factorial(n));
n = n + 2;
};
else
{
x2 = (x2 + ((pow(x,n)) /(factorial(n))) - (pow(x,n+2)) / (factorial(n+2)));
n = n + 4;
}


}while(abs(b - x2) > 0.000001);
else
//convert it to r

r = x * PI /180;

//cout<<"error occured/n";
cout<<"sin(x) = "<<x2<<endl;

return 0;
}

Mar 24, 2008 | ArcMedia JavaScript Source Code 3000 Pro...

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