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Hi........ Pls.... help me in my problem, Give me the code in visual basic. It is all about determining the number of vowel and consonant in a given word. pls... responce as soon as possible. thanks

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I wrote this as a vbscript. It's Visual Basic code in windows script. If you have XP, just copy the text into notepad and save it as "vowel.vbs". Now double click the newly created script file.

' vowel.vbs
'
' This VBScript is used to count the vowels and consonants in a string.
' Designed and Tested on Windows XP Pro SP2
'
' Version 1.0.0 - 02.20.2008
'
' This code may be freely distributed or modified.
' -----------------------------------------------------------------'

Option Explicit
Dim str
Dim vowels
Dim consonants
Dim i

vowels = 0
consonants = 0
str = "hello"

for i = 1 to len(str)
select case mid(str,i,1)
case "a"
vowels = vowels + 1
case "e"
vowels = vowels + 1
case "i"
vowels = vowels + 1
case "o"
vowels = vowels + 1
case "u"
vowels = vowels + 1
case else
consonants = consonants + 1
end select
next

msgbox "Vowels = " & vowels
msgbox "Consonants = " & consonants
'End of script.

Posted on Feb 21, 2008

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#
# Since no language was specifiec, here's a solution in the
# gawk dialect of awk.
#
# Familiarity with awk is assumed, so only minimal comments
# are present. I have a version with more comments...
#


BEGIN {
IGNORECASE = 1
}

{ r0 = $0 } # Copy the input record into the variable r0, for efficiency

wc += gsub(/[[:blank:]]+/, "", r0) {} # Destructively count all the white spaces in r0

vc += gsub(/[AEIOU]/, "", r0) {} # Destructively count all the vowels in r0

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END {
printf("%d vowel%s\n", vc, (vc != 1) ? "s" : "")
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1 Answer

Program


I wrote this as a vbscript. It's Visual Basic code in windows script. If you have XP, just copy the text into notepad and save it as "vowel.vbs". Now double click the newly created script file.

' vowel.vbs
'
' This VBScript is used to count the vowels and consonants in a string.
' Designed and Tested on Windows XP Pro SP2
'
' Version 1.0.0 - 02.20.2008
'
' This code may be freely distributed or modified.
' -----------------------------------------------------------------'

Option Explicit
Dim str
Dim vowels
Dim consonants
Dim i

vowels = 0
consonants = 0
str = "hello"

for i = 1 to len(str)
select case mid(str,i,1)
case "a"
vowels = vowels + 1
case "e"
vowels = vowels + 1
case "i"
vowels = vowels + 1
case "o"
vowels = vowels + 1
case "u"
vowels = vowels + 1
case else
consonants = consonants + 1
end select
next

msgbox "Vowels = " & vowels
msgbox "Consonants = " & consonants
'End of script.

Feb 21, 2008 | Computers & Internet

1 Answer

Help


i did not solve my problem yesterday.
that's why i need your help..
please help me to solve my problem that i posted yesterday.i need your help.
thank you very much.

Feb 21, 2008 | Computers & Internet

2 Answers

Help me


this the code for your problem. by the way this for vb6.0

Sub CountCharacters(Text As String)
Dim iVowel As Integer
Dim iCons As Integer
Dim iNum As Integer
Dim iSpace As Integer
Dim iOther As Integer

Dim cnt As Integer
Dim sChar As String

For cnt = 1 To Len(Text)
sChar = LCase(Mid(Text, cnt, 1))

Select Case sChar
Case "a", "e", "i", "o", "u" ' And sometimes "y"?
' Vowel
iVowel = iVowel + 1
Case "a" To "z"
' Includes the first case, but VB matches the first case and stops
iCons = iCons + 1
Case "0" To "9"
' Numbers
iNum = iNum + 1
Case " ", vbTab, vbLf
' Space characters
' Not including vbCr as this will likely be dealing with Windows text
' and I only want to match one character for a newline
iSpace = iSpace + 1
Case Else
If sChar <> vbCr Then iOther = iOther + 1
End Select
Next cnt

Debug.Print "Text: " & Text
Debug.Print "Vowels: " & CStr(iVowel)
Debug.Print "Consonants: " & CStr(iCons)
Debug.Print "Numbers: " & CStr(iNum)
Debug.Print "Space characters: " & CStr(iSpace)
Debug.Print "Other: " & CStr(iOther)
End Sub

Feb 21, 2008 | Computers & Internet

1 Answer

Help me


Sub CountCharacters(Text As String)
Dim iVowel As Integer
Dim iCons As Integer
Dim iNum As Integer
Dim iSpace As Integer
Dim iOther As Integer

Dim cnt As Integer
Dim sChar As String

For cnt = 1 To Len(Text)
sChar = LCase(Mid(Text, cnt, 1))

Select Case sChar
Case "a", "e", "i", "o", "u" ' And sometimes "y"?
' Vowel
iVowel = iVowel + 1
Case "a" To "z"
' Includes the first case, but VB matches the first case and stops
iCons = iCons + 1
Case "0" To "9"
' Numbers
iNum = iNum + 1
Case " ", vbTab, vbLf
' Space characters
' Not including vbCr as this will likely be dealing with Windows text
' and I only want to match one character for a newline
iSpace = iSpace + 1
Case Else
If sChar <> vbCr Then iOther = iOther + 1
End Select
Next cnt

Debug.Print "Text: " & Text
Debug.Print "Vowels: " & CStr(iVowel)
Debug.Print "Consonants: " & CStr(iCons)
Debug.Print "Numbers: " & CStr(iNum)
Debug.Print "Space characters: " & CStr(iSpace)
Debug.Print "Other: " & CStr(iOther)
End Sub

Feb 21, 2008 | Computers & Internet

2 Answers

Visual basic code


'Text1 is a textbox or a string you can use

Private Sub Command1_Click()
Dim a
Dim vow, con As Integer
vow = 0
con = 0
For i = 1 To Len(Text1)
a = Mid(Text1, i, 1)
If (a = "a" Or a = "e" Or a = "i" Or a = "o" Or a = "u") Then
vow = vow + 1
Else
con = con + 1
End If
Next
MsgBox "Vowels: " & vow & vbNewLine & "Consonants : " & con

End Sub

Feb 19, 2008 | Computers & Internet

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