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Analytic geometry find the equation of the circlepassing through (3,7) and tangent to the line x-4y-15=0 at (3,-3).

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Nice..let's see..counts on fingers..

x=a(b)-(d-n)/z.com

Posted on Feb 19, 2008

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Find the equations of circles passing through (1,-1),touching the lines 4x+3y+5=0 and 3x-4y-10=0


First, I graphed the lines and the point using Desmos.com.

I noticed that the two lines are perpendicular to each other and the point (1,-1) appears to be on the right side of the circle, on a line parallel to 3x -4y-10=0. The equation of this line is y= 3/4x - 1.75. The y-intercept is -1.75. Now we have two points on the opposite sides of the circle, (1, -1) and (0,-1.75). The midpoint formula will give you the centre of the circle and the distance formula will provide the radius.

Let me know if you have any questions.

Good luck.

Paul
Desmos Beautiful Free Math

Jun 09, 2014 | Office Equipment & Supplies

1 Answer

How to solve equations with two variables by usin CASIO fx901 calculater? eg- 6x+9y=2700 5x+4y=1560


The FX-901 calculator seems to be the equivalent of the FX 260 Solar sold in North America. It does fraction calculations, permutation, statistics but lack the Equation Solver.
You cannot use it to solve equations.
Casio Scientific calculators that can handle equation solving are the FX-115 and FX-991.
Simplify your first equation by dividing all its terms by 3, then use elimination to carry out the solution by hand.

Sep 02, 2012 | Office Equipment & Supplies

1 Answer

What are perpendicular lines


Two lines are perpendicular if they belong to the same plane and intersect (cut) one another at right angle. They make a 90 degree angle. If you are doing analytic geometry, two lines are perpendicular if the product of their slopes ia equal to -1.
Other relative positions of lines are parallel (they have the same slope/direction) or they are just secant at an angle not equal to 90 degrees.

Feb 03, 2012 | Office Equipment & Supplies

2 Answers

2x - 4y = 20 4x + 2y = -20


This should start wit X=something and Y=something, sorry I'm not an human algebra calculator....

Jul 29, 2011 | Computers & Internet

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Can i ask how to answer this?2x-4y-9=o


That is an equation describing a straight line. The "slope-intercept" form of a line is

y = mx + b

where m is the slope (change in y-value / change in x-value)
and b is the y-intercept (the point where the line crosses the y-axis when x=0)

Positive slope means the line is rising and negative slope means it's falling.

You can rewrite the original equation 2x - 4y -9 = 0 in slope-intercept form:

y = (1/2)x - (9/4)

So you know the slope is positive 1/2 (line rises 1 y-unit for each 2 x-unit change) and crosses the y-axis at -9/4. With this information you can graph the line.

Jul 12, 2011 | Sewing Machines

1 Answer

Solve y in terms of x using this equation x=4y+5


what is the value of x?

if x = 1 in the equation then,
1 = 4y+5
1 - 5 = 4y
-4 = 4y
y = -4/4
y = -1

Jun 30, 2011 | Computers & Internet

2 Answers

How do I solve x and y in the following equations? 5x+3y=6 2x-4y=5 Thank you


You can solve it with following method.

5x+3y=6 2x-4y=5
So 5x=6-3y so 2[(6-3y)/5]-4y=5
So x=(6-3y)/5 so 12-6y-20y=25
so -26y=25-12
so -26y=13
so y= -(1/2)
2x-4y=5
so 2x=5+4y
so 2x=5+4(-1/2)
so 2x=(10-4)/2
so 2x=6/4
so x =3/2

The value of x=3/2 and value of y= -1/2

Let me know if you need further assistance.
Thanks for using FixYa.

Mar 03, 2010 | Office Equipment & Supplies

2 Answers

How do I enter and graph the equation: 6 - 3/8y = x 2/3x + 1/4y = 4 Thanks!!


At first you have to slving this equations in explicit form y=f(x) and the graphing it. See captured images



3_3_2012_5_25_37_pm.jpg

3_3_2012_5_25_56_pm.jpg

Jan 23, 2009 | Texas Instruments TI-83 Plus Calculator

1 Answer

Analytic geometry


assuming the question is what is the circle equation?
and if (-2,2) is the center of the circle
the equation should look like this: (x+2)^2+(Y-2)^2=R^2

And now only R is needed.

given 2x-5y+4=0 equation of line perpendicular

we can rearange the equation to be y=(2x+4)/5
from that we can see that the slope of the line is 2/5
And from the fact of perpendicular line we can say that the slope
of the radius line is -2/5.

The motivation now is to calculate the distance between the center of the circle to the cross point of the radius with the line perpendicular

For that we would calculate the radius line equation and compare it to the equation of line perpendicular

As mentioned earlier the slope of the radious line is -2/5.

So the equation is y=-2/5x+b and b can be calculated by using the center of the circle coordinates

2= - (2/5)*(-2)+b ------> b=2-4/5=1.2
radius equation is y=-(2/5)x+1.2

Now the cross point is calculated by comparing the equations:
-(2/5)x+1.2=(2x+4)/5 --> -2x+6=2x+4 --> 4x=2 --> x=1/2 --> y=1

So the cross point is (1/2,1).

The distance between the points is calculated by the following
Formula:

R=SQR(((1/2)-(-2))^2+(2-1)^2)=SQR(2.5^2+1^2)=SQR(6.25+1)=
SQR(7.25)

Therefore the circle eq is (x+2)^2+(Y-2)^2=7.25



Oct 26, 2008 | Casio FX-115ES Scientific Calculator

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