Question about SoftMath Algebrator - Algebra Homework Solver (689076614429)

# 6x-5(x-5)=52 - SoftMath Algebrator - Algebra Homework Solver (689076614429)

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X=27

6x-5(x-5)=52

6x-5x+25=52
x=52-25
x=27

Posted on Jan 30, 2010

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## Related Questions:

### I need to understand how to divide a binomial.

Let's take 2x^2 - 10x +12 and divide it by x-2.
__2x_-_6____________
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How many times does x go into 2x^2. Put the answer, 2x above the 2x^2. Next mulitply (x-2) by 2x and put the answer under 2x^2. Now subtract that answer from 2x^2 - 10x and we get -6x (-10x - (-4x)).

How many time does x go into -6x. -6 time. Write this above the line and put the answer above the -10x. Next multiply (x-2) by -6 and put the answer under the -6x. Subtract and we get 0 and we are done. If we want to check our answer we can multiply (x-2) and (2x - 6) and we should get 2x^2 - 10 x + 12.

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### 3x(7x+6x)

For 3x(7x+6x)=0, x=0
For 3x(7x+6x)=1, x=1/39
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### (2x+3y)(3x+2y)

(2x - 3y)(3x + 2y) = 2x*3x + 2x*2y - 3y*3x - 3y*2y
= 6x^2 + 4xy - 9xy - 6y^2
= 6x^2 - 5xy - 6y^2 You multiply each element in the first set of brackets by each element in the second set of brackets and then consolidate like terms and arrange them in sequence of powers, first x and then y. So:
2x by 3x = 6x squared
2x by 2y = 4xy
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6x squared -5xy + 6y squared

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### Ind the area of the region bounded by the two circles y=x^3-6x^2+

The first step here is to draw a rough sketch of the two curves, and find the two points they meet. If you set x^3-6x^2+8x = x^3-4x, then you can rearrange this into the quadratic equation 6x^2-12x = 0. Solving this tells you x=0 or 2 : these are the two x values where the curves meet, and they give the bounds on your integral.

When you sketch the curves, you'll see that x^3-4x is below x^3-6x^2+8x, so the thing you need to integrate is (x^3-6x^2+8x)-(x^3-4x), that is, 12x-6x^2. If you integrate this from 0 to 2, you'll have the answer you need!

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6x+5(x+9y)+7y
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11x+52y - Simplified version
Further learning:
Distributive property of multiplication:
http://www.math.unt.edu/mathlab/emathlab/distributive_property_of_multipl.htm

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### Is the ordered pair a solution of the equation? 6x - 3 = y; (0, -3)

6x- 3 = y; (0, -3)

Here 6x - 3 = y is the equation
The ordered pair is (0, -3 )
It means if you substitutes 0 for x and -3 for y the equation will be true
Let us substitute and see:-
'6x' (means 6 times x) means 6 times 0 which is equal to 0
So the equation 6x - 3 = y becomes
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Good luck
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6x+6=4x+12
Since 4x contains the variable to solve for, move it to the left-hand side of the equation by subtracting 4x from both sides.
6x+6-4x=12
Since 6x and -4x are like terms, add -4x to 6x to get 2x.
2x+6=12
Since 6 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 6 from both sides.
2x=-6+12
Add 12 to -6 to get 6.
2x=6
Divide each term in the equation by 2.
(2x)/(2)=(6)/(2)
Simplify the left-hand side of the equation by canceling the common factors.
x=(6)/(2)
Simplify the right-hand side of the equation by simplifying each term.
x=3

Good Luck

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