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Excel 2003 formula

Hi All
I'm trying to find a formula that gives me the LAST entry in a row based on TODAY()
the row looks like this:
date1 Interest Balance date2 Interest Balance date3 ...etc

What I need is the LAST entry under 'Balance' based on TODAY()
I've got this, but it doesnt work properly:
{=SUM((N2:FP2<=TODAY()),(N2:FP2="Balance"),N4:FP4)}
(where N4:FP4 contains the actual data)

Can anyone help?

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  • Anonymous Jan 25, 2008

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Try it using =now() function. I think it will work

Posted on Feb 07, 2008

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SOURCE: excel formula

Assuming that all of your data is in a single row number 4 and between columns N and PF

Try:
{=OFFSET(N4,0,MATCH(TODAY(),N4:PF4,0)+1,1,1)}

The MATCH function looks up the value of today() in the range N4 to PF4 and returns the number of columns offset from the beginning of the range. (The 0 here does an exact match)

The OFFSET function returns a value from a cell a specified number of columns from a reference cell, in this case N4, which is the first column that contains the search data. We need to add on to this value to skip the Interest column.

Regards,
Daryl

Posted on Mar 19, 2009

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Assuming that all of your data is in a single row number 4 and between columns N and PF

Try:
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The MATCH function looks up the value of today() in the range N4 to PF4 and returns the number of columns offset from the beginning of the range. (The 0 here does an exact match)

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