Question about Mathsoft StudyWorks! Middle School Deluxe Math 5.0 (11543) for PC

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Do you mean

m=n/5 That is m=n divided by 5

Multiply both sides by 5

5m = n

which is the sme as n=5m

luciana44

Posted on Dec 09, 2009

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Posted on Jan 02, 2017

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Check your formulae for a small error. Use F1 to guide you.

Jul 14, 2017 | The Computers & Internet

If result is positive it is an increase. If it is negative it is a decrease

Here

Dec 07, 2013 | Office Equipment & Supplies

The median of a finite list of numbers can be found by arranging all the observations from lowest value to highest value and picking the middle one (e.g., the median of {3, 5, 9} is 5). If there is an even number of observations, then there is no single middle value; the median is then usually defined to be the mean of the two middle values. It is similar to an average. or a root mean square value (RMS).

Nov 30, 2013 | Computers & Internet

When you buy it is worth $60, 000

I will assume that at the end of a year it is the whole new value of the house that is increased by 5%.

After**1 year** value=60,000*(1+0.05)**^1**

After**2 years** value=$60,000(1+0.05)*(1+0.05)=60,000*(1.05**)^2**

Do you see the pattern?

After**7 years,** the value of the house will be 60,000*(1.05)**^7**

However if the increase is not compounded

Then after 1 year value=60,000*(1+0.05)

After** 2** years, value=60,000*(1+0.05+0.05)=60,000*(1+**2***0.05)

After** 7 **years, value=60,000*(1+**7***0.05)

Depending on the coumpounding or not the two values will be different

With compounding: final value=$84,426.02

Without compunding: final value is $81, 000.

I showed you the possible mathematical solutions. It is now up to you to decide which is the one that applies to your case.

I will assume that at the end of a year it is the whole new value of the house that is increased by 5%.

After

After

Do you see the pattern?

After

However if the increase is not compounded

Then after 1 year value=60,000*(1+0.05)

After

After

Depending on the coumpounding or not the two values will be different

With compounding: final value=$84,426.02

Without compunding: final value is $81, 000.

I showed you the possible mathematical solutions. It is now up to you to decide which is the one that applies to your case.

Jan 28, 2012 | HP 10bII Calculator

Those are absolute value signs. Absolute value is defined as a number's distance from 0. So both 5 and -5 are a count of 5 away from 0 therefore the absolute value of both 5 and -5 would be 5.

I hope this helps! If this did help you, please give a thumbs up!

I hope this helps! If this did help you, please give a thumbs up!

Jun 28, 2011 | Computers & Internet

create a flowchart that will increase the value of the number by 5 if it is greater than 10 and display the result. otherwise multiply the value by 5 and display the result.

Jun 23, 2011 | Audio Players & Recorders

OK, you just have to put those values into the equation, do the math, and see if it works.

-6 * 5/6 - 7 * (-2) = 9 does it?

-5 - (-14) = -5 + 14 = 9 yes it does

You can (and probably should) always check a solution by testing this way. The definition of a solution is a value or set of values that cause the equation to work out. If the test had failed (say we had gotten -6 = 9 before, which is obviously wrong), we'd know that the values weren't a solution.

-6 * 5/6 - 7 * (-2) = 9 does it?

-5 - (-14) = -5 + 14 = 9 yes it does

You can (and probably should) always check a solution by testing this way. The definition of a solution is a value or set of values that cause the equation to work out. If the test had failed (say we had gotten -6 = 9 before, which is obviously wrong), we'd know that the values weren't a solution.

Jun 09, 2011 | Computers & Internet

The following solution shows how to find the value of x:

Start with the general equation given:

y = -(3/5)x - 8

Substitute the known value of y:

-11 = -(3/5)x - 8

Add 8 to both sides:

-11 + 8 = -(3/5)x - 8 + 8

-3 = -(3/5)x

Now multiply both sides by 5 to get rid of the denominator:

-3 * 5 = -(3/5)x * 5

-15 = -3x

Now divide by -3 to get x:

-15/3 = -3x/3

x = 5

The answer is x = 5.

Start with the general equation given:

y = -(3/5)x - 8

Substitute the known value of y:

-11 = -(3/5)x - 8

Add 8 to both sides:

-11 + 8 = -(3/5)x - 8 + 8

-3 = -(3/5)x

Now multiply both sides by 5 to get rid of the denominator:

-3 * 5 = -(3/5)x * 5

-15 = -3x

Now divide by -3 to get x:

-15/3 = -3x/3

x = 5

The answer is x = 5.

Apr 27, 2011 | Texas Instruments TI-84 Plus Calculator

2 0 0 0 0 +/- PV (present value, negative because you're paying it out)

5 *P/YR (5 years)

1 0 . 5 I/YR (interest rate)

FV (calculate future value, about 33,732)

5 *P/YR (5 years)

1 0 . 5 I/YR (interest rate)

FV (calculate future value, about 33,732)

Aug 09, 2010 | HP 10bII Calculator

Hello,

Here how you do it taking as exemples y1=x^3 -5 and y2=abs(x^3-5)

Turn calculator ON by pressing [AC/On] . Use arrows to select [Graph] icon and press [EXE]

On line Y1= enter X[^]3 -5 [EXE]

On line Y2= press [OPTN] [F5:NUM][F1:abs] [(] X [^]3 -5 [)] [EXE]

The graphs will be drawn one after the other. You might have to adjust the window limits.

Here is an ouput drawn on another calculator.

For negative values of the x-variable, Y1 has negative values, while in the same range, Y2 has positive values, equal and opposite to those of Y1. In that range, Y1 and Y2 are symetric of each other with respect to the X axis.

For positive values of the x-variable, Y1 and Y2 are identical.

Hope it helps

Here how you do it taking as exemples y1=x^3 -5 and y2=abs(x^3-5)

Turn calculator ON by pressing [AC/On] . Use arrows to select [Graph] icon and press [EXE]

On line Y1= enter X[^]3 -5 [EXE]

On line Y2= press [OPTN] [F5:NUM][F1:abs] [(] X [^]3 -5 [)] [EXE]

The graphs will be drawn one after the other. You might have to adjust the window limits.

Here is an ouput drawn on another calculator.

For negative values of the x-variable, Y1 has negative values, while in the same range, Y2 has positive values, equal and opposite to those of Y1. In that range, Y1 and Y2 are symetric of each other with respect to the X axis.

For positive values of the x-variable, Y1 and Y2 are identical.

Hope it helps

Jan 30, 2009 | Casio CFX-9850G Plus Calculator

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