Question about RCA HD52W59 HDTV Projection Television

2n = 1st even integer

2n + 2 = 2nd even integer

Product = 2n(2n + 2) = 4n^2 + 4n = 4(n^2 + n)

1520 = 4(n^2 + n)

1520/4 = 4(n^2 + n)/4

380 = n^2 + n

0 = n^2 + n - 380

0 = (n + 20)(n - 19)

n = -20, +19

Answer can not be negative so n = +19

2n = 2(19) = 38

2n + 2 = 2(19) + 2 = 40

ANSWER: the integers are 38 and 40

Posted on Dec 02, 2009

Hi,

a 6ya expert can help you resolve that issue over the phone in a minute or two.

best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

goodluck!

Posted on Jan 02, 2017

The integers of the numbers on three raffle tickets are consecutive integers whose sum is 7,530 are 2509, 2510, and 2511.

Feb 24, 2015 | SoftMath Algebrator - Algebra Homework...

Let x be the smallest number.

Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)

three times the smaller 3(x)

19 more -19

sum of the two integers - (x) +( x+2)

Pulling it together,

3x -19 = x + x +2

collect like terms

3x - 19 = 2x + 2

Put all the constants on one side by adding 19 to both sides.

3x - 19 +19= 2x + 2 + 19

3x = 2x +21

Subtract 2x from both sides to have all the x's on one side.

3x - 2x = 2x +21 - 2x

x = 21

The other number is 21 + 2, or 23

Check:three times the smaller = 3 x 21 = 63

sum of the two integers = 21 + 23 or 44

is 63 at least 19 more than 44

Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)

three times the smaller 3(x)

19 more -19

sum of the two integers - (x) +( x+2)

Pulling it together,

3x -19 = x + x +2

collect like terms

3x - 19 = 2x + 2

Put all the constants on one side by adding 19 to both sides.

3x - 19 +19= 2x + 2 + 19

3x = 2x +21

Subtract 2x from both sides to have all the x's on one side.

3x - 2x = 2x +21 - 2x

x = 21

The other number is 21 + 2, or 23

Check:three times the smaller = 3 x 21 = 63

sum of the two integers = 21 + 23 or 44

is 63 at least 19 more than 44

Feb 19, 2015 | Office Equipment & Supplies

38.

The three numbers are 34, 36, and 38.

The three numbers are 34, 36, and 38.

Jun 03, 2014 | Office Equipment & Supplies

The two numbers are 32 and 34. The rest is your homework, you do it.

Dec 19, 2013 | Office Equipment & Supplies

Let x be first (smaller) integer and y second (larger) integer.

These two numbers are 20 and 22.

- They are consecutive (and even) : y=x+2
- Twice the smaller exceeds the larger by 18: 2*x=y+18
- Substitute first equation into second: 2x=x+2+18
- 2x-x=2+18
- x=20
- y=x+2=22

These two numbers are 20 and 22.

Oct 03, 2011 | Office Equipment & Supplies

We'll call x the smaller integer and y the larger. So we know x+3y=22. We can rearrange this to say:

x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

Sep 15, 2011 | Texas Instruments TI-84 Plus Calculator

X + ( X + 2 ) + ( X + 4 ) = 105

3X + 6 = 105

3X = 105 - 6

3X = 99

X = 99/3

X = 33

So 33 + 35 + 37 = 105

3X + 6 = 105

3X = 105 - 6

3X = 99

X = 99/3

X = 33

So 33 + 35 + 37 = 105

Oct 06, 2010 | American Standard Plumbing

try this website:

http://www.homeworkspot.com/

http://www.homeworkspot.com/

Sep 15, 2010 | Lufkin C213C 600" x 38" Long Consecutive...

Let X be the lowest of the 3 integers

The sum of the 3 integers can be represented as X + (X+1) + (X+2).

Set this sum equal to 378 and solve for X.

X + (X+1) + (X+2) = 378

3X + 3 = 378

3X = 375

X = 125

Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

The sum of the 3 integers can be represented as X + (X+1) + (X+2).

Set this sum equal to 378 and solve for X.

X + (X+1) + (X+2) = 378

3X + 3 = 378

3X = 375

X = 125

Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

Aug 23, 2010 | SoftMath Algebrator - Algebra Homework...

find two consecutive cube numbers or integers whose difference is a square number. i know it is 8 and 7 but hav to get the equation

Jan 15, 2010 | Garmin GPSMAP 376C GPS Receiver

521 people viewed this question

Usually answered in minutes!

×