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I want to see the length and width of a rectangle with an area of 265.68sqm

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Hi Roger,

Since any rectangle will do, how about 88.56m x 3m.

Mike

Posted on Nov 14, 2009

Testimonial: "thanks mike, i will consider that one"

  • Justin Case
    Justin Case Nov 14, 2009

    Hey Roger,

    I don't mind the math problems, I actually like them.

    I don't mind helping you out either.

    What I do mind is my rating going down for giving good solutions. I would rather not be rated as this has no damaging effect on a record I work hard to maintain. Of course The 4thumbs is gladly accepted.

    I know you couldn't know this, but with a rating above 90% anything below four thumbs brings it down

    Bottom line: I was helping you. Don't damage me for doing it. Please either remove it or .....



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1 Answer

The width of a rectangle is 2 meters less than the length. if the area is 120square meters, find the length and width.


Width is 10 metres
Length is 12 metres
Derive an equation for area in the form of x
Area= length x width
120sqm = x(x-2)
120sqm = xsquared - 2x
Then apply to formula for solving a quadratic equation.
Hope that helps.

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Nov 25, 2017 | The Computers & Internet

1 Answer

The length, l, of a rectangle is 5/2 its width, w. The length, l, of the rectangle is 10 inches. What is the perimeter of the rectangle? What Iis the area of the rectangle, in sauare inches?


We are given the following data:

length = 5/2 * width
length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5
width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width
Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width
Area = (10 in)(4 in)=40 in^2

Nov 29, 2016 | The Computers & Internet

1 Answer

X(2x+3)=90


Solve the resulting quadratic equation
2X^2+3X-90=0
Discriminant: (3)^2-4(2)(-90)=729=(27)^2
Two roots
X_1=(1/4)*(-3+27)=6
X-2=(1/4)*(-3-27) =-(15/2), negative
Since the width must be positive, reject the negative root and keep X_1=6
Width =6
Length=2(6)+3=15

Check 6*(15)=90. Checks OK

Apr 23, 2014 | Office Equipment & Supplies

1 Answer

Volume of rectangle formula


A rectangle is a two-dimensional figure and doesn't have a volume. It has an area equal to length times width. A rectangular prism has a volume equal to length times width times height.

Feb 06, 2014 | Office Equipment & Supplies

2 Answers

How do you solve a rectangle is eight inches longer than its width. find the dimensions of the rectangle if the perimeter is 60 cm


The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Oct 11, 2013 | Lands Phones

1 Answer

Area of rectangle is 4122cm2 .width of rectangle is 3cm.how do i find the length of it


Area = length X width, and you know the area and the width. So,

4122 sq cm = length X 3 cm

length = 4122 sq cm / 3 cm

length = 1374 cm

(That is one long, skinny rectangle, isn't it?)

Mar 02, 2011 | Office Equipment & Supplies

1 Answer

Area and perimeter


Area= width * length
Perimeter= 2 * width + 2* length

Are you looking for an Excel function?
There are no Area or Perimeter functions I am aware of in Excel.

Mar 03, 2008 | Microsoft Office Standard for PC

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