Question about Bagatrix Algebra Solved! 2005 (105101) for PC

# 1.01^1000000 is greater or 10000 ?

This has to be solved using binomial theorem

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Try this... here we represent 1.01 as 1+.01
and so we have nCr and stuff... it can be noted that a number lesser than .01 when raised to power will result in a number lesser than it and hence the first term which is 1^1000000 will be greatest among the terms... so it can never be greater than 10000

Posted on Jan 31, 2008

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I am sorry to come in like that (5 years after the question was asked) and spoil your fun.
If you try to enter it on a regular calculator you will get an overflow error, memory error or some such thing. On the Windows calculator here is what I get.
2.3647358888701483369966440045217x10^(4321)

Posted on Mar 01, 2013

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Posted on Jan 02, 2017

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## Related Questions:

### What to do if c is x+ in pythagoras theorem

a^2 + b^2 = c^2

If you are given a and c and have to solve for b, let's do it this way.

5^2 + b^2 = 13^2
25 + b^2 = 169
25 + b^2 -25 = 169 - 25
b^2 = 144
b = sqrt(144)
b = 12.

I hope this helps.

Good luck.

Paul

p.s. Here is a great video of Pythagorean Theorem in water;)
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Try to seek these: By using the suggested format:
Suggested su
• 1

Arrange each term in each binomial in order of degree from greatest to least. The degree of a binomial is the exponent attached to the term. For example, 4x^2 is a second degree term.

• 2

Multiply each term in the binomial that is being subtracted by -1 to turn it into an addition problem. For example, the problem (8x^2 + 8) - (x^2 - 2) becomes (8x^2 + 8) + (-x^2 + 2).

• 3

Combine like terms. In the example problem, the x^2 terms are combined and the constant terms are combined, yielding (8x^2 + 8) + (-x^2 + 2) = 7x^2 + 10.

Multiplying Binomials
• 4

Understand the F.O.I.L. method. F.O.I.L. is an acronym standing for first, outside, inside and last. It means that you multiply the first number of the first binomial by the first number of the second, then the numbers on the outside (the first term of the first binomial by the second term of the second binomial) and so on. This ensures that both numbers in the first binomial are multiplied by both numbers in the second.

• 5

Use the F.O.I.L. method to multiply the two binomials together. For example, (3x + 4)(3x - 4) = 9x^2 +12x - 12x - 16. Notice that -12x is the product of the outside terms and -16 is the product of the last terms, 4 and -4.

• 6

Simplify. There will almost always be like terms to combine. In the example, 12x and -12x cancel out, yielding the answer 9x^2 - 16.

Dividing Binomials
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Use the distributive property to divide both terms in the binomial by the monomial divisor. For example, (18x^3 + 9x^2) / 3x = (18x^3 / 3x) + (9x^2 / 3x).

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Understand how to divide by a term. If you are dividing a higher order term by a lower order term, you subtract the exponent. For example, y^3/y = y^2. The number part of each term is handled like any other division problem. For example, 20z / 4 = 5z.

• 9

Divide each term in the binomial by the divisor; (18x^3 / 3x) + (9x^2 / 3x) = 6x^2 + 3x.

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Use the quadratic formula, or factor the quadratic polynomial. Once factored into a product of two first degree binomials, the roots are obtained by setting (in TURN) each binomial factor equal to zero.

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### (3x-2y)^4 use the binomial theorem

You have to type expand((38x-28y)^4,x). See captured images

Jan 04, 2012 | Texas Instruments TI-89 Calculator

### Definition of special product types and examples of special products

In mathematics, special products are of the form:
(a+b)(a-b) = a2 - b2 (Product of sum and difference of two terms) which can be used to quickly solve multiplication such as:
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(a+b)^2 = a^2 + 2ab + b^2
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2. Square of a Trinomial
(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc
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3. Cube of a Binomial
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Jul 28, 2011 | Computers & Internet

### How to solve foil method

The FOIL Method is a process used in algebra to multiply two binomials. The lesson on the Distributive Property, explained how to multiply a monomial or a single term such as 7 by a binomial such as (4 + 9x).
But, what if there was a binomial instead of a single term outside of the parentheses? That is, what if a binomial was being multiplied by another binomial? An example of this is given below.

FOIL stands for:
First - Multiply the first term in each set of parentheses Outer - Multiply the outer term in each set of parentheses Inner - Multiply the inner term in each set of parentheses Last - Multiply the last term in each set of parentheses Now let's give it a try in our problem. We'll start by multiplying the first term in each set of parentheses and then marking down the answer below the problem.
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And the Inners.
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Jun 12, 2011 | Computers & Internet

### TI-89 Titanium: I want to solve a Binomial Theorem problem (x+y)^6 how would i go about solving this in the calculator?

Using elementary algebria in the binomial theorem, I expanded the power (x + y)^n into a sum involving terms in the form a x^b y^c. The coefficient of each term is a positive integer, and the sum of the exponents of x and y in each term is n. This is known as binomial coefficients and are none other than combinatorial numbers.

Combinatorial interpretation:

Using binomial coefficient (n over k) allowed me to choose k elements from an n-element set. This you will see in my calculations on my Ti 89. This also allowed me to use (x+y)^n to rewrite as a product. Then I was able to combine like terms to solve for the solution as shown below.
(x+y)^6= (x+y)(x+y)(x+y)(x+y)(x+y)(x+y) = x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

This also follows Newton's generalized binomial theorem:

Now to solve using the Ti 89.

Using sigma notation, and factorials for the combinatorial numbers, here is the binomial theorem:

The summation sign is the general term. Each term in the sum will look like that as you will see on my calculator display. Tthe first term having k = 0; then k = 1, k = 2, and so on, up to k = n.
Notice that the sum of the exponents (n ? k) + k, always equals n.

The summation being preformed on the Ti 89. The actual summation was preformed earlier. I just wanted to show the symbolic value of (n) in both calculations. All I need to do is drop the summation sign to the actual calculation and, fill in the term value (k), for each binomial coefficient.

This is the zero th term. x^6, when k=0. Notice how easy the calculations will be. All I'm doing is adding 1 to the value of k.

This is the first term or, first coefficient 6*x^5*y, when k=1.
Solution so far = x^6+6*x^5*y

This is the 2nd term or, 2nd coefficient 15*x^4*y^2, when k=2.
Solution so far = x^6+6*x^5*y+15*x^4*y^2

This is the 3rd term or, 3rd coefficient 20*x^3*y^3, when k=3.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3

This is the 4th term or, 4th coefficient 15*x^2*y^4, when k=4.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4

This is the 5th term or, 5th coefficient 6*x*y^5, when k=5.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5

This is the 6th term or, 6th coefficient y^6, when k=6.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5+y^6

Putting the coefficients together was equal or, the same as for when I used the expand command on the Ti 89.

binomial coefficient (n over k) for (x+y)^6
x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5+y^6

Jan 04, 2011 | Texas Instruments TI-89 Calculator

### {Use the binomial theorem to find the eight term of (3x-2y)^13}

This may help:
http://en.wikipedia.org/wiki/Binomial_theorem
Rate me, thanks.

Jun 19, 2009 | Texas Instruments TI-89 Calculator

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