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Posted on Oct 26, 2009
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I want to create an application that when running would make appear a circle ( radius and color configurable ) move from centre-down of my laptop screen to centre-up ( speed of motion configurable ). this animation should run in a loop as long as the program is running and i want to know is it also possible that when this circle is running other work on the laptop can be done please suggest how can i create this application ( which programming language ) which functions ? etc. rergardless for whether it is possible to continue normal work while animation runs or not.

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marley mcelhinney

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  • Posted on Oct 26, 2009
marley mcelhinney
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Joined: Apr 06, 2009
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Doing that sought of thing is high level tech programming and is certainly not achievable by just anyone, the only possible way is to make it a screen saver which isnt wat you want because you want to be able to do other things at the same time, your best bet would be to try and find a program already like that on the net but i dint like your chances of finding one

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Related Questions:

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An equation of the circle whose center is at(2,-3) and whose radius measures4 is it A, B, C or D?

A. The equation of a circle is (x-a)^2 + (y-b)^2 = r^2, with (a,b) being the centre of the circle and r being the radius.

Good luck,

Paul
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Write the equation in standard form for the circle with radius 1 centered at the origin.

The formula for a circle in standard form in (x-h)^2 + (y-k)^2 = r^2, where r is the radius, the point (h,k) is the centre of the circle, and ^2 means squared.

Substituting in 0 for h and 0 for k, and 1 for r, you will get your formula.

Good luck.

Paul
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Find the equations of circles passing through (1,-1),touching the lines 4x+3y+5=0 and 3x-4y-10=0

First, I graphed the lines and the point using Desmos.com.

I noticed that the two lines are perpendicular to each other and the point (1,-1) appears to be on the right side of the circle, on a line parallel to 3x -4y-10=0. The equation of this line is y= 3/4x - 1.75. The y-intercept is -1.75. Now we have two points on the opposite sides of the circle, (1, -1) and (0,-1.75). The midpoint formula will give you the centre of the circle and the distance formula will provide the radius.

Let me know if you have any questions.

Good luck.

Paul
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Circle equation

(x-h)^2+(y-k)^2=r^2
where (h,k) is the centre of the circle and r is the radius of the circle.

Good luck.

Paul
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Circle equation

(x-h)^2+(y-k)^2=r^2
where (h,k) is the centre of the circle and r is the radius of the circle.

Good luck.

Paul
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Circle equation

(x-h)^2+(y-k)^2=r^2
where (h,k) is the centre of the circle and r is the radius of the circle.

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Circle middle

Draw two chords of the circle (any two chords will do, as long as they aren't parallel). Construct perpendicular bisectors of each chord. The center of the circle will be where the two bisectors intersect.
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To graph a circle with radius 4

Press [2nd][PGRM] to open the (DRAW) utility. Scroll down to reach the line 9: Circle( and press ENTER. Complete the command by supplying the coordinates of the circle center and the radius.
Circle(0,0,4) draws a circle with center at the origin (0,0) and radius 4.
By the way the equation of a circle is not a function. You have to cut it into the upper brach and the lower part to graph it.
y=+SQRT(16-x^2) and y=-SQRT(16-x^2)
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WHEN GRAPHING A CIRCLE ON THE TI83, THERE ARE POINTS MISSING.

Use the DRAW program.
Press [2nd][PRGM] (DRAW)
Select [9:Circle (]
Command echoes on main screen
Complete the command with coordinates of the center and the radiius
Close parenthesis and press [ENTER]
The circle is displayed.

Ex: Circle(0,3,2) draw a circle with cntere at (0,3) and radius equal to 2.

Alternatively: If the conics application is on the calculator run it.
Press [APPS]
Select [Conics]
Select [1:CIRCLE]
Choose the canonical form (X-H)^2 + (Y-K)^2=R^2 where H, and K are the coordinates of the center and R is the radius.
You will be prompted to enter the values for H,K, and R

You can also use the general equation for a circle aX^2 +aY^2+BX+CY +D=0
Enter the values of a, B, C and D.Change the values to get what you want.

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