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A painter and his son can paint a room together in 8 hr.If the father works alone for 3 hr and then is joined by his son,the two together can complete the job in 6 hr more.How long will it take each person alone to paint the room?

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Sorry but this is not an appropriate question for FixYa ads it's not related to technical support, instructions, repair or recommendations. Making exceptions to this will encourage more inappropriate questions from others.

Please consider posting your question elsewhere such as on Yahoo! Answers.

Sorry that this is not the solution you were after but it's the only appropriate answer.

Posted on Oct 08, 2009

  • Obertelli
    Obertelli Oct 09, 2009

    1st line of my answer has a typo: "FixYa ads"... Sorry folks, I meant to type "Fixya as".




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Work problem


Here is the answer:
Daisy did 2/5ths or %40 of the barn in those two days as she can do the whole lot in 5 days she did 2/5ths or %40 in 2 days so thats %40 of the barn done.
Didith did 2/8ths or %25 of the barn in those two days, 
so the amount of barn painted in the first two days is: 1/4 + 2/5 which equals %65 of the barn complete in the first two days. so there is %35 of the barn left to paint and only Daisy (who can paint %20 of the barn in one day) 
so to figure out how many days it takes Daisy to paint %35 of the barn this is what to do:
%20 = 1day %35 - %20 = %15 5x5x5x5 = 20 5x5x5 = 15 therefore it takes Daisy 1/4 of a day to paint %5 of the barn therefore it takes Daisy 3/4 of a day to paint %15 of the barn (i hope you are following me here!) 1 + 3/4 = one and three quarters of a day
Therefore it took Daisy one and three quarter days to paint the remaining %35 of the barn.
So it took Days one and three quarter days to finish the job after Didith left.
Hope this is helpful
Emmanuel

Sep 17, 2008 | Computers & Internet

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