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Write a system of linear inequalities whose solutuion region forms the given shape a rectangle

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Hi wnhrtlywanda,
You can try this:
K>y>0, L>x>0, where K and L are any constants.
If you need a rectangle that is not parallel to the axes, use the formulae for the rotation of the axes and replace the small x, y in the above inequalities with the following values
x = XcosA - YsinA; and y = XsinA + YcosA
where capital X and Y denote the new x and y after rotation, A is the angle of rotation measured anticlockwise from the x-axis.
I sincerely hope this helps.

Posted on Oct 17, 2009

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How many linear feet would be needed to surround a rectangle of a 63.50 acre site?


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All you can do with this polynomial is try to factor it. Here is the factored out form
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How to turn off shading when graphing inequalities.


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If x-1> 0, the absolute value is x-1. The inequality takes the form x-1<9. You can solve it as x<10

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Combine the two domains to find the intersection
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> whose entries are all 1

This is a linearly-dependent matrix -- all rows are the same.
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