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# Write a system of linear inequalities whose solutuion region forms the given shape a rectangle

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Hi wnhrtlywanda,
You can try this:
K>y>0, L>x>0, where K and L are any constants.
If you need a rectangle that is not parallel to the axes, use the formulae for the rotation of the axes and replace the small x, y in the above inequalities with the following values
x = XcosA - YsinA; and y = XsinA + YcosA
where capital X and Y denote the new x and y after rotation, A is the angle of rotation measured anticlockwise from the x-axis.
I sincerely hope this helps.

Posted on Oct 17, 2009

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Posted on Jan 02, 2017

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All you can do with this polynomial is try to factor it. Here is the factored out form
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To find the solution set you need to study the two cases for the absolute value.
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If x-1<0, then the absolute value is 1-x. The inequality becomes 1-x<9. The solution for this inequality is x>-8

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> whose entries are all 1

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