Question about Texas Instruments TI-84 Plus Calculator

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Hello,

Clear the you the RAM to revert to default settings and restart. I am including screen capture fro a TI to show you how to set up the calculator.

Notice the white-on-black equal signs. For a function to be drawn, the equal sign in its definition must be highlighted. To effect that you scroll left to the = and press ENTER. You will know the function has been selected for graphing if its equal sign remains white-on-black after cursor has moved to another location.

Here is what the 4 functions look like. They all are on same graph.

Now we will change the graph stythe calculator only allows one line equation to - fce7a77.jpgosine function.

The only difference between the first screen and this one is the style of the line at the left of the Y4. To change the style, you move to the cursor to the left of the Y and press ENTER. Each time you pressthe calculator only allows one line equation to - 00e0856.jpgR, the style for the function in question changes. Here is the product.

The wavy curve (cosine) is now dotted.

Hope it helps.

Posted on Oct 05, 2009

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Posted on Jan 02, 2017

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What are the question marks in the two equations? Get rid of them or replace them with numbers and you'll get rid of the error.

Apr 28, 2012 | Texas Instruments TI-83 Plus Graphing...

This is problem with graphing differential equation. Invalid Axes error occurs if Axes=TIME or if t(time) is set as a CUSTOM axis. This is important to noticed: if Fields=DIRFLD you cannot plot a time axis. See captured image:

This graph represented differential system of equations y1'(x)=y2(x), y2'(x)=-y1(x) for initial conditions y1(0)=0, y2(0)=-1.Finally, x axes=y1(x) and y axes=y2(x)

This graph represented differential system of equations y1'(x)=y2(x), y2'(x)=-y1(x) for initial conditions y1(0)=0, y2(0)=-1.Finally, x axes=y1(x) and y axes=y2(x)

Feb 08, 2012 | Texas Instruments TI-89 Calculator

The site seems to eat the plus signs I enter, so I will use PLUS to symbolize addition.

To find the equation of the straight line (y = a*x PLUS b) that passes through two points P1(x1,y1) and P(x2,y2) , you need to use

1. the coordinates of the points to calculate the slope a (gradient) as a=(y2-y1)/(x2-x1)

2. Replace the calculated value of a in the equation and write that one of the points ( P1(x1,y1) for example) satisfies the equation. In other words y1=a*x1 PLUS b.

Here y1 and x1 are known values, a has been calculated, and only b is still unknown. You can now use the equation y1=a*x1 PLUS b to calculate b as

b=(y1-a*x1)

Example: Equation of the line through (1,5) and (3,6)

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=(1/2)*3 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

I trust you can substitute you own values for (x1,y1, x2,y2) to duplicate the calculations above.

To find the equation of the straight line (y = a*x PLUS b) that passes through two points P1(x1,y1) and P(x2,y2) , you need to use

1. the coordinates of the points to calculate the slope a (gradient) as a=(y2-y1)/(x2-x1)

2. Replace the calculated value of a in the equation and write that one of the points ( P1(x1,y1) for example) satisfies the equation. In other words y1=a*x1 PLUS b.

Here y1 and x1 are known values, a has been calculated, and only b is still unknown. You can now use the equation y1=a*x1 PLUS b to calculate b as

b=(y1-a*x1)

Example: Equation of the line through (1,5) and (3,6)

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=(1/2)*3 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

I trust you can substitute you own values for (x1,y1, x2,y2) to duplicate the calculations above.

Jan 27, 2011 | Texas Instruments TI-84 Plus Calculator

Example: Equation of the line through (1,5) and (3,6)

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=3/2 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=3/2 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

Jan 10, 2011 | Texas Instruments TI-84 Plus Calculator

Calculate
the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5,
x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=3/2 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=3/2 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

Oct 20, 2010 | Texas Instruments TI-84 Plus Calculator

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=1, y1=0, x2=0, and x1=-6. You should get a=(1-0)/(0-(-6))=1/6

The y-intercept is the y-cordinate for x=0. Its value is 1.

The equation is then y=(x/6) 1.

The y-intercept is the y-cordinate for x=0. Its value is 1.

The equation is then y=(x/6) 1.

Oct 18, 2010 | Texas Instruments TI-84 Plus Calculator

1.) make sure the two lines are not the same line

2.) under the y= button, when you enter the two equations make sure for both y1 and y2 the icon on the far left for both is a solid \ and the = on the right of y1 and y2 should be highlighted.

3.) clear memory if all else fails as a last resort.

hope this helps

2.) under the y= button, when you enter the two equations make sure for both y1 and y2 the icon on the far left for both is a solid \ and the = on the right of y1 and y2 should be highlighted.

3.) clear memory if all else fails as a last resort.

hope this helps

Apr 27, 2010 | Texas Instruments TI-84 Plus Calculator

Hello,

The marking that so puzzle you define the type of line (or dots) to represent the graphs. Enter as many functions as there are Y variables.

After entering a function press [ENTER] to jump to the next one.

When finished entering all functions press GRAPH. If you want graphs drawn one after the other, in MODE highlight Sequential (6th line) and press ENTER. If you want graphs drawn simultaneously, in MODE (6th line) highlight Simul and press ENTER. Press 2ND QUIT to return to previous screen . Execute graph again.

Hope itr helps.

The marking that so puzzle you define the type of line (or dots) to represent the graphs. Enter as many functions as there are Y variables.

After entering a function press [ENTER] to jump to the next one.

When finished entering all functions press GRAPH. If you want graphs drawn one after the other, in MODE highlight Sequential (6th line) and press ENTER. If you want graphs drawn simultaneously, in MODE (6th line) highlight Simul and press ENTER. Press 2ND QUIT to return to previous screen . Execute graph again.

Hope itr helps.

Sep 23, 2009 | Texas Instruments TI-83 Plus Silver...

Hello,

Suppose you want to draw the circle the equation of which is X^2+Y^2=4, a circle centered at the origin with radius 2.

When you isolate Y^2 and then extarct the squre root you obtain two solutions, call them Y1 and Y2

Y1=SQRT(4-X^2), Y2= -SQRT(4-X^2)

You press[Y=] and type in the right hand side of the equations above, one in Y1= and the other in Y2. Press [GRAPH].

Ih a graphic does not appear within the scree window adjust the window parameters ( [WINDOW]) or Press [ZOOM] and select ZoomIn, ZoomOut, ZoomSTD, etc.

Explore the program Draw accessible by pressing [2nd][DRAW].

Hope it helps

Suppose you want to draw the circle the equation of which is X^2+Y^2=4, a circle centered at the origin with radius 2.

When you isolate Y^2 and then extarct the squre root you obtain two solutions, call them Y1 and Y2

Y1=SQRT(4-X^2), Y2= -SQRT(4-X^2)

You press[Y=] and type in the right hand side of the equations above, one in Y1= and the other in Y2. Press [GRAPH].

Ih a graphic does not appear within the scree window adjust the window parameters ( [WINDOW]) or Press [ZOOM] and select ZoomIn, ZoomOut, ZoomSTD, etc.

Explore the program Draw accessible by pressing [2nd][DRAW].

Hope it helps

Sep 04, 2009 | Texas Instruments TI-84 Plus Calculator

When you go to Y=, you should get a list that says:

Y1=

Y2=

Y3=

etc. You just enter the first equation into the Y1= space then hit ENTER and it will go to Y2=. Enter the second equation there. After you have entered all of your equations, push GRAPH and they should come up in order but they will all appear.

Also, make sure your window is set appropriately so that you are able to see all of the graphs.

Lastly, when you look at your Y= screen, are there funny looking arrows before the Y=? If so, do this:

Press [APPS] key
Select Transfrm from the menu
Press 1:Uninstall

Hope one of these are helpful!!

-Gretchen

Y1=

Y2=

Y3=

etc. You just enter the first equation into the Y1= space then hit ENTER and it will go to Y2=. Enter the second equation there. After you have entered all of your equations, push GRAPH and they should come up in order but they will all appear.

Also, make sure your window is set appropriately so that you are able to see all of the graphs.

Lastly, when you look at your Y= screen, are there funny looking arrows before the Y=? If so, do this:

Hope one of these are helpful!!

-Gretchen

Feb 18, 2008 | Texas Instruments TI-84 Plus Calculator

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