Question about HP LaserJet 3055 All-In-One Printer

1) Print is missing along a 'one inch' width patch for the entire lengh of document. A white patch is appearing on the document due to non-printing.

2) After reinstallation of the driver once again, the 'one inch wide white patch' is reduced to 'one straight line of black colour' along the entire length of document

3) Now the problem mentioned at (1) above repeats at a different location of the paper while the line mentined at (1) above remains .

Ad

Try a new toner cartridge

if it doesn't fix your problem then you willneed a new fuser

it is probably delaminated

Posted on Jan 11, 2008

Ad

Hi,

A 6ya expert can help you resolve that issue over the phone in a minute or two.

Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

The service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

Good luck!

Posted on Jan 02, 2017

Ad

It sounds like the hole is relatively small. You can make a patch using a piece of sheet metal or a piece of flat aluminum which you can purchase at Lowes or Home Depot in the hardware dept. Use sheet metal if the metal surround is metal. Use aluminum if the surround is aluminum. You can tell which is which by taking a magnet and touching the metal. If the magnet sticks, it's metal not aluminum. Cut the patch using sheet metal shears to a size that is 4 inches by four inches larger than the hole. Then you'll have two inches on each side of the hole. You are going to need to put the patch on the inside of the metal, between the liner and the metal surround. This so the hole edges won't tear the liner. When you cut the patch, round off the edges so there are no sharp edges. Take duct tape and cover the edges of the patch. Place 1/2 the width of the duct tape and apply it to one side of the patch and fold the other half over to the other side. You can cut a round patch, but a square or rectangle patch will be easier. Just cut the corners round. Purchase a small tube of silicone sealant ( when you but the patch material) and apply a bead around the patch edges and in the middle. Then affix the patch over the hole. Wipe off any sealant that ozzed through the patch so it doesn't bond to the liner.

Jun 01, 2014 | Karcher 2500 PSI Pressure Washer

Hi!

fixed the 203 dpi new head in zebra 105sl printer then 1 week print is correct size to 4x6 inches label but after 15 days its not comming full page print.

pls help to get soultion

thanks / Khokan

fixed the 203 dpi new head in zebra 105sl printer then 1 week print is correct size to 4x6 inches label but after 15 days its not comming full page print.

pls help to get soultion

thanks / Khokan

Jul 15, 2012 | Office Equipment & Supplies

(All values below are rounded to the nearest tenth)

615 meters = 24212.6 inches

330 meters = 12992.1 inches

700 meters = 27559.1 inches

The area of this box would be 8,669,335,548,609.2 inches^3 (cubed). Since this is an absurdly large number, I'm going to assume that you meant "m" to mean millimeters. The proper abbreviation of millimeters is "mm."

615 mm = 24.2 inches

330mm = 13 inches

700mm = 27.6 inches

The area of THIS box would be 8,683 inches^3 (cubed) or 723.6 cubic feet.

Incidentally, this is not a problem with a calculator, but a problem done using a calculator.

615 meters = 24212.6 inches

330 meters = 12992.1 inches

700 meters = 27559.1 inches

The area of this box would be 8,669,335,548,609.2 inches^3 (cubed). Since this is an absurdly large number, I'm going to assume that you meant "m" to mean millimeters. The proper abbreviation of millimeters is "mm."

615 mm = 24.2 inches

330mm = 13 inches

700mm = 27.6 inches

The area of THIS box would be 8,683 inches^3 (cubed) or 723.6 cubic feet.

Incidentally, this is not a problem with a calculator, but a problem done using a calculator.

Apr 12, 2011 | Office Equipment & Supplies

If we assume the width of the frame is X. Then the one dimension of the framed picture will be 2X + 20 and the other dimension of the picture will be 2X + 34. We know the total area of the framed picture should be 640 in^2. Therefore:

(2X + 10) * (2X + 34) = 640

If you multiply this out you get:

4X^2 + 88X + 340 = 640

Subtract 640 from both sides:

4X^2 + 88X - 300 = 0

Divide both sides by 4:

X^2 + 22X - 75 = 0

Use the quadratic equation to solve for X, with A=1, B=22, C=75

X = [-22 +/- sqr(22^2-4*(-75)] /2

This reduces to:

(-22 +/- 48) / 2

The negative solution doesn't make sense in this case. Therefore: X = (-22 + 28) /2 = 6/3 = 3

Therefore the width of the frame should be 3 inches.

(2X + 10) * (2X + 34) = 640

If you multiply this out you get:

4X^2 + 88X + 340 = 640

Subtract 640 from both sides:

4X^2 + 88X - 300 = 0

Divide both sides by 4:

X^2 + 22X - 75 = 0

Use the quadratic equation to solve for X, with A=1, B=22, C=75

X = [-22 +/- sqr(22^2-4*(-75)] /2

This reduces to:

(-22 +/- 48) / 2

The negative solution doesn't make sense in this case. Therefore: X = (-22 + 28) /2 = 6/3 = 3

Therefore the width of the frame should be 3 inches.

Feb 16, 2011 | SoftMath Algebrator - Algebra Homework...

Definitely. possible solution match the width of your label and ribbon. if your ribbon is wider for .5 inch it should be good.

1. check your spindle alignment, printhead alignment and rotate the green knob on the printhead while printing so that you'll see the difference.

1. check your spindle alignment, printhead alignment and rotate the green knob on the printhead while printing so that you'll see the difference.

Jan 29, 2010 | Datamax DMX I-4206 Printer

4' = 48"

thickness" x width" x lengh" = cubic inches

2" x 8" x 48" = 768

1 cubic foot is 144 cubic inches

768 divided by 144 = 5.3333333333------

thickness" x width" x lengh" = cubic inches

2" x 8" x 48" = 768

1 cubic foot is 144 cubic inches

768 divided by 144 = 5.3333333333------

Dec 09, 2008 | Electric 1/2hp 1140RPM 56 Frame 230/460V...

The difference is 3/4 of a inch in lengh and 2 cm thicker. I would go with the 7-3/8, it bigger in lengh and thickness.

Dec 02, 2008 | Master Lock Bicycle Lock

Set the roll size to 44 inch, set your left margin to 0 (in your preprint software), experiment. With margins set at 0, using Onyx Productionhouse 7.3, the 9800 will print approx 41.8 inch image on 42 inch roll 43.8 on 44, etc. This is considered borderless printing. No matter what size roll you tell the printer it has in it, it will print to about an eighth to a sixteenth of an inch short of the paper's actual edge (that's the left side of the roll paper coming out of the printer - the right side of the print). If you load, for example, a 36 inch roll, tell the printer its a 44 inch roll, and send a 40 inch wide print, with a left margin of 0 it will print around 35.8 inches, cutting off the image just before it would overprint and get ink on the machine (1/8 - 1/16inch before the edge of your 36 inch stock). It is possible that these tollerances will be different depending on what software you send your images with... hope this helps!

May 08, 2008 | Epson Stylus Pro 9800 InkJet Printer

Try using the "manual" width calibration. With the printer on, press and hold the green button. It will flash once, then twice, e.g. the sequence:

*

* *

* * *

* * * *

* * * * *

after the 5th flash, let go of the button. The printer will begin drawing rectangles which get wider and wider. Press the green button once (don't hold it) to indicate "when" the width is appropriate. However, I found the width was best calibrated when I let the printer draw rectangles right until the edge (where it automatically stops).

*

* *

* * *

* * * *

* * * * *

after the 5th flash, let go of the button. The printer will begin drawing rectangles which get wider and wider. Press the green button once (don't hold it) to indicate "when" the width is appropriate. However, I found the width was best calibrated when I let the printer draw rectangles right until the edge (where it automatically stops).

Dec 27, 2007 | Zebra LP 2844 Thermal Printer

Verify your LCD Display Print Width setting is set wider than your actual label width. The printer will only print to the width of the PRINT WIDTH setting. Also verify any driver or software settings as these override your printer settings.

Jun 30, 2007 | Zebra 140XiIII Plus Thermal Label Printer

Oct 03, 2016 | HP LaserJet 3055 All-In-One Printer

172 people viewed this question

Usually answered in minutes!

×