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I have a engine on my sawbench which is rated at 3000 r.p,m thepulley on the output is 6 ins .what size pulley do i need on the saw to make it turn at 800 r.p.m.

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The RPM's of the motor x the size of the pulley (3000rpm x 6inchs = 18000) = the output RPM's of the drive x the size of the pulley (in this case 800rpm x D ) Diameter would = 22.5 inchs.
Basically:
3000 X 6 / 800 = 22.5

You will have to change the pulley size on the motor to a smaller pulley. A 2" pulley on your motor would require a 7.5" pulley on your drive. Or you could use two belts to reduce the size of the pulleys even more. If you halve the RPMs to 1600 first from the 2" pulley you would need a 3.75" pulley followed by another belt hooked up to a 4" pulley to get your 800rpm. Hope this helps.

Posted on Oct 16, 2009

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