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Help please george has one solution that is 40% water and a second solution that is 75% water. how much of each solution should he use to get 70ml of solution that is 50% water>

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Solution 1 = 50mL
Solution 2 = 20mL

Pls check if correct;
x = first solution
y = 2nd solution

.4x + .75y = .5(70) first equation
x+y = 70 2nd equation

x = 70 - y

subtitute x to 1st equation to get value of y, then subtitute value of y for x = 70 - y to get value of x.

There you go. Hope it is correct


Posted on Sep 30, 2009

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Volume 1 x .4 + Volume 2 x .75 = 70 mL x .5

Volume 2 = 70 - Volume 1

V1 x .4 + (70-V1) x .75 = 70 mL x .5

solve for V1

Posted on Sep 30, 2009

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