Question about Dmm Conservatory 16 Foot x 8 Foot x 9 Foot 6 Inches

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Posted on Jan 02, 2017

We are given the following data:

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

Nov 29, 2016 | The Computers & Internet

Ok

2L + 2W = 50 (i)

W = L/4 + 5 (ii)

So 4W = L + 20 from (ii) and

4W = 100 - 4L from (i)

L + 20 = 100 - 4L

5L = 80

L = 16

W = 9 from (ii)

check

(i) 2*16 + 2*9 = 50

(ii) 16/4 + 5 = 9 = W

2L + 2W = 50 (i)

W = L/4 + 5 (ii)

So 4W = L + 20 from (ii) and

4W = 100 - 4L from (i)

L + 20 = 100 - 4L

5L = 80

L = 16

W = 9 from (ii)

check

(i) 2*16 + 2*9 = 50

(ii) 16/4 + 5 = 9 = W

Oct 10, 2014 | Computers & Internet

160 by 140

The perimeter is 600, so 2w+2l=600 where w is the width and l is the length.

Divide both sides by 2: w+l=300

The length is 20 more than the width: l=w+20

Substituting in the previous equation: w+(w+20)=300

Collecting terms: 2w+20=300

Subtract 20 from both sides: 2w=280

Divide by 2: w=140

Thus the width is 140. Substituting into the equation for length: l=140+20

Simplifying: l=160

The width is 140 and the length is 160

The perimeter is 600, so 2w+2l=600 where w is the width and l is the length.

Divide both sides by 2: w+l=300

The length is 20 more than the width: l=w+20

Substituting in the previous equation: w+(w+20)=300

Collecting terms: 2w+20=300

Subtract 20 from both sides: 2w=280

Divide by 2: w=140

Thus the width is 140. Substituting into the equation for length: l=140+20

Simplifying: l=160

The width is 140 and the length is 160

Sep 15, 2014 | MathAid Algebra II

Solve the resulting quadratic equation

2X^2+3X-90=0

Discriminant: (3)^2-4(2)(-90)=729=(27)^2

Two roots

X_1=(1/4)*(-3+27)=6

X-2=(1/4)*(-3-27) =-(15/2), negative

Since the width must be positive, reject the negative root and keep X_1=6

**Width =6**

Length=2(6)+3=15

Check 6*(15)=90. Checks OK

2X^2+3X-90=0

Discriminant: (3)^2-4(2)(-90)=729=(27)^2

Two roots

X_1=(1/4)*(-3+27)=6

X-2=(1/4)*(-3-27) =-(15/2), negative

Since the width must be positive, reject the negative root and keep X_1=6

Length=2(6)+3=15

Check 6*(15)=90. Checks OK

Apr 23, 2014 | Office Equipment & Supplies

A rectangle is a two-dimensional figure and doesn't have a volume. It has an area equal to length times width. A rectangular prism has a volume equal to length times width times height.

Feb 06, 2014 | Office Equipment & Supplies

The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Oct 11, 2013 | Lands Phones

Translate the English into Mathematics.

W=L-5 (in inches)

P=2(L+W)=2(L+L-5)=2(2L-5)

Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)

P=4L-10.

Set P= 50 (inches), to get 4L-10=50

**Solve for L: Do it'! **

Find W= L (the one you just found) -5 =

Now, with W the value you just calculated

the new length is** L'=-4+3W**

and the new perimeter is** P'=2(L'+W)**

Now your turn to do some work.

W=L-5 (in inches)

P=2(L+W)=2(L+L-5)=2(2L-5)

Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)

P=4L-10.

Set P= 50 (inches), to get 4L-10=50

Find W= L (the one you just found) -5 =

Now, with W the value you just calculated

the new length is

and the new perimeter is

Now your turn to do some work.

Jan 02, 2012 | Office Equipment & Supplies

Area = length X width, and you know the area and the width. So,

4122 sq cm = length X 3 cm

length = 4122 sq cm / 3 cm

length = 1374 cm

(That is one long, skinny rectangle, isn't it?)

4122 sq cm = length X 3 cm

length = 4122 sq cm / 3 cm

length = 1374 cm

(That is one long, skinny rectangle, isn't it?)

Mar 02, 2011 | Office Equipment & Supplies

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