If 15 men or 7 women can earn rs.525 per day, how much would 7 men and 13 women earn per day

Re: ratio and propotion

15 men earns 525

1 man raens 525/15

equals to 35

7 women earns 525

1 women earns 75

so 7 men and 13 women earns 7 *35+13*75=245+975=1220

Posted on Apr 14, 2009

Re: ratio and propotion - Bagatrix Algebra Solved! 2005 (105101) for PC Educational & Reference Software

What is propotion in math??

Posted on Oct 06, 2008

Re: ratio and propotion

26.25

Posted on Mar 11, 2008

Re: ratio and propotion

X\5.25=7\13*15\7

x=26.25

Posted on Mar 11, 2008

Re: ratio and propotion

Ans-26.25rs

Posted on Mar 11, 2008

Re: ratio and propotion

1220

Posted on Jan 31, 2008

Re: ratio and propotion

Ans.-245

Posted on Mar 12, 2008

Fire on water

Aug 18, 2014 | Educational & Reference Software

Let m represent the subscription rate for a man, and w the subscription rate for a woman.

m/w=4/3, or** m=(4/3)w**.

2 men and 5 women paid 460. Thus

**2m+5w=460.**

Substitute**(4/3)w** for **m**, in **2m+5w=460**.

This gives an equation in the unknown w. Solve for w

2(4/3)w +5w=460 or (23/3)w=460.**Answer is w=60**

Use this value in the relation m=(4/3)w to get m=80.

**Check m/w=80/60=4/3**

m/w=4/3, or

2 men and 5 women paid 460. Thus

Substitute

This gives an equation in the unknown w. Solve for w

2(4/3)w +5w=460 or (23/3)w=460.

Use this value in the relation m=(4/3)w to get m=80.

May 09, 2014 | The Learning Company Achieve! Math &...

There is a problem with the numbers you quote.

20 x 2/3 = 13.3 boys

You can't have 0.3 of a boy. So round that off to 13 boys. Girls are

20 - 13 = 7 in number. This is the nearest sensible answer.

20 x 2/3 = 13.3 boys

You can't have 0.3 of a boy. So round that off to 13 boys. Girls are

20 - 13 = 7 in number. This is the nearest sensible answer.

Apr 09, 2014 | Educational & Reference Software

Two ways to get to the same answer:

1) If X,Y, & Z are invested in the ratio of 4:5:6 then the amount invested in Z is 6/(4+5+6) times the total of N1200

= 6/15 * 1200

= N480

(Note: X is 4/15 and Y is 5/15 of the total investment,

4/15 + 5/15 + 6/15 = 15/15)

2) The second sentence says: Income from X plus income from Y minus income from Z is N140 and total income is N700. Total income is 700/1200 of the investment.

As formulas:

(Inc X + Inc Y) - Inc Z = 140 (rewriting: Inc X + Inc Y = 140 + Inc Z)

Inc X + Inc Y + Inc Z = 700

Substituting second formula into third:

(140 + Inc Z) + Inc Z = 700

140 + 2 Inc Z = 700

2Inc Z = 700 - 140 = 560

Inc Z = N280

Inc Z is also 700/1200 of investment in Z.

N280 = 700/1200 investment in Z

Investment in Z is 1200/700 * N280

Investment in Z is N480.

1) If X,Y, & Z are invested in the ratio of 4:5:6 then the amount invested in Z is 6/(4+5+6) times the total of N1200

= 6/15 * 1200

= N480

(Note: X is 4/15 and Y is 5/15 of the total investment,

4/15 + 5/15 + 6/15 = 15/15)

2) The second sentence says: Income from X plus income from Y minus income from Z is N140 and total income is N700. Total income is 700/1200 of the investment.

As formulas:

(Inc X + Inc Y) - Inc Z = 140 (rewriting: Inc X + Inc Y = 140 + Inc Z)

Inc X + Inc Y + Inc Z = 700

Substituting second formula into third:

(140 + Inc Z) + Inc Z = 700

140 + 2 Inc Z = 700

2Inc Z = 700 - 140 = 560

Inc Z = N280

Inc Z is also 700/1200 of investment in Z.

N280 = 700/1200 investment in Z

Investment in Z is 1200/700 * N280

Investment in Z is N480.

Feb 19, 2014 | Bagatrix Educational & Reference Software

To solve this, you need to multiply the ratios together.

(2/5)*(3/4) = A/C

So (2*3)/(5*4) = A/C

6/20 = A/C

You can reduce that be dividing both sides by 2

3/10 = A/C

Here is an example:

Let X = 3

The problem states that A/B = 2/5

So let A = 2X & B = 5X

A = 2*(3) = 6

B = 5*(3) = 15

Now check the ratio: 6/15 = 2/5. The same as what was given.

Now lets look at the ratio for B/C. The given ratio for B/C was 3/4

Using the value of B that we just solved we get:

B = 15

C = (4/3)*15 = 20

Check the ratio.

15/20 = 3/4

Now we have the values for each of the variables

A = 6

B = 15

C = 20

The ratio of A/C is 6/20

6/20 can be reduced to 3/10 be dividing both numbers by 2

(2/5)*(3/4) = A/C

So (2*3)/(5*4) = A/C

6/20 = A/C

You can reduce that be dividing both sides by 2

3/10 = A/C

Here is an example:

Let X = 3

The problem states that A/B = 2/5

So let A = 2X & B = 5X

A = 2*(3) = 6

B = 5*(3) = 15

Now check the ratio: 6/15 = 2/5. The same as what was given.

Now lets look at the ratio for B/C. The given ratio for B/C was 3/4

Using the value of B that we just solved we get:

B = 15

C = (4/3)*15 = 20

Check the ratio.

15/20 = 3/4

Now we have the values for each of the variables

A = 6

B = 15

C = 20

The ratio of A/C is 6/20

6/20 can be reduced to 3/10 be dividing both numbers by 2

Aug 22, 2010 | The Learning Company Achieve! Math &...

use simultaneous equations, with x = # of men and y = # of women:

x + y = 5000 --> convert to x = 5000 - y 1.1x + 1.15y = 5600

1.1 (5000 - y) + 1.15y = 5600 5500 - 1.1y + 1.15y = 5600 .05y = 100 y = 2000 plug y = 2000 into x + y = 5000

therefore x = 3000

x + y = 5000 --> convert to x = 5000 - y 1.1x + 1.15y = 5600

1.1 (5000 - y) + 1.15y = 5600 5500 - 1.1y + 1.15y = 5600 .05y = 100 y = 2000 plug y = 2000 into x + y = 5000

therefore x = 3000

Jul 09, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

From the second step the difference between pirate x and pirate x+1 is 5.

1 pirate- 3 men 2 pirates- 8 men 3 pirates - 13 men 4 pirates- 18 men 5 pirates- 23

1 pirate- 3 men 2 pirates- 8 men 3 pirates - 13 men 4 pirates- 18 men 5 pirates- 23

Jun 27, 2010 | Mathsoft StudyWorks! Middle School Deluxe...

Let x = the width of the women's court. Then 2x is the length of the women's court.

the area of the womens court is x times 2x = 2x^2

the length of the mens court is 4 ft longer than the women's or 2x + 4

The width of the men's court is 5 ft wider than the womwn's or x + 5

The are of the mens court is 650 square feet larger that the womens so we have to add 650 to the area of the womens court so the men's and women's will be equal

Now we have area of the women's court = area of the men's court

2x^2 + 650 = (x + 5) (2x + 4) = 2x^2 + 14x + 20

The x^2 cancel out and we are left with 14X + 20 + 650 solving for x we get x = 45

Plugging x back into the length and width equations we get the length is 94 and the width is 50

Hope this helped

Good luck Loringh

the area of the womens court is x times 2x = 2x^2

the length of the mens court is 4 ft longer than the women's or 2x + 4

The width of the men's court is 5 ft wider than the womwn's or x + 5

The are of the mens court is 650 square feet larger that the womens so we have to add 650 to the area of the womens court so the men's and women's will be equal

Now we have area of the women's court = area of the men's court

2x^2 + 650 = (x + 5) (2x + 4) = 2x^2 + 14x + 20

The x^2 cancel out and we are left with 14X + 20 + 650 solving for x we get x = 45

Plugging x back into the length and width equations we get the length is 94 and the width is 50

Hope this helped

Good luck Loringh

Oct 03, 2008 | Educational & Reference Software

701 people viewed this question

Usually answered in minutes!

×