The angle of elevation to the top of a tree from a distance of 33m is 19 degrees. Work out the height of the tree.

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**11.3628 M**

Posted on Sep 12, 2009

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What the ****!!!!

Posted on Sep 29, 2009

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Posted on Jan 02, 2017

11.4 meters.

Since this looks like a homework problem, be sure to show YOUR work.

Since this looks like a homework problem, be sure to show YOUR work.

Feb 16, 2014 | Computers & Internet

31 degrees. If this is homework, make sure you show your work.

Sep 25, 2013 | Office Equipment & Supplies

e.

If this is homework, be sure to show your work.

If this is homework, be sure to show your work.

Sep 25, 2013 | Computers & Internet

x is the height of tree, y and z are as denoted in picture:

Please rate my answer if it was helpful :)

- cos(22°)=y/215==>y=cos(22°)*215=199.3 ft
- sin(22°)=z/215==>z=sin(22°)*215=80.5 ft
- tan(52°)=(x+z)/y==>x+z=y*tan(52°)=255.1 ft
- x=255.1-z=255.1-80.5=174.6 ft

Please rate my answer if it was helpful :)

Sep 06, 2011 | Casio fx-300ES Calculator

Draw one right-angle triangle:

D

C

/'

/ '

/ '

/ '

A===B

A = your location

B = bottom of the hill

C = bottom of the antenna

D = top of the antenna

The A-B distance is constant.

The B-C distance is unknown.

The B-C-D distance is unknown.

The C-D distance is given.

The C-A-B angle is given as 25 degrees.

The D-A-C angle is given as 1.5 degrees.

Use SINE and COSINE functions to determine the B-C distance.

Tell your teacher that you found the answer to your homework on the Internet.

D

C

/'

/ '

/ '

/ '

A===B

A = your location

B = bottom of the hill

C = bottom of the antenna

D = top of the antenna

The A-B distance is constant.

The B-C distance is unknown.

The B-C-D distance is unknown.

The C-D distance is given.

The C-A-B angle is given as 25 degrees.

The D-A-C angle is given as 1.5 degrees.

Use SINE and COSINE functions to determine the B-C distance.

Tell your teacher that you found the answer to your homework on the Internet.

Sep 24, 2010 | Computers & Internet

Hi there,

Using the measurements you have given and calculating the others as follows:

Angle A= 30 degrees

Side b= 900 metres

Angle B= 60 degrees

Side b= 1558.845 metres

Therefore length of the slope = 1,800.0000000000002 metres (side c)

Hope this helps. Regards, James

Using the measurements you have given and calculating the others as follows:

Angle A= 30 degrees

Side b= 900 metres

Angle B= 60 degrees

Side b= 1558.845 metres

Therefore length of the slope = 1,800.0000000000002 metres (side c)

Hope this helps. Regards, James

Apr 22, 2010 | Televison & Video

height =50

length = 60

angle=x

tangent(x)=50/60

tangent(x)=0.833

x=39.8 degree

length = 60

angle=x

tangent(x)=50/60

tangent(x)=0.833

x=39.8 degree

Mar 01, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

Depends ur height and building's height

Feb 12, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

Hi Jehho soria

Draw a right triangle with the vertical portion of the triangle representing the 37 meters of the light house The base of the triangle is the distance we are trying to find. If the angle of depression is 15 degrees, the other angle is 75 degrees. This is the angle from the boat to the top of the lighthouse.

so The Tangent of 75 degrees is equal to the side opposite the angle (the height of the lighthouse) divided by the side adjacent (the distance we are trying to find.

solving for the distance we get distance = 37 divided by the tangent of 37 degrees

Looking up the tangent of 15 degrees on google give .2679

dividing 137 by .2679=138,1 meters

Hope this helps Loringh PS Please leave a rating for me.

Draw a right triangle with the vertical portion of the triangle representing the 37 meters of the light house The base of the triangle is the distance we are trying to find. If the angle of depression is 15 degrees, the other angle is 75 degrees. This is the angle from the boat to the top of the lighthouse.

so The Tangent of 75 degrees is equal to the side opposite the angle (the height of the lighthouse) divided by the side adjacent (the distance we are trying to find.

solving for the distance we get distance = 37 divided by the tangent of 37 degrees

Looking up the tangent of 15 degrees on google give .2679

dividing 137 by .2679=138,1 meters

Hope this helps Loringh PS Please leave a rating for me.

Nov 14, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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