Question about Texas Instruments Office Equipment & Supplies

# Cannot figure out how to use the reverse log on my Staples Textbook display BD-6410 Calculator the pOH is 6.59 I need to use the reverse log to get the answer for the H+ which is the reverse log of 6.59 answer is 2.6 x 10 to the -7 I get an answer of -1.9981 x 10 the -1 I tried reading instructions but they were no help I press In then log then put in the number my textbook says put in -6.59 but when I try that it won't calculate I've tried switching and pressing log first that don't work Help please I need to write a test Thank you Lillian

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• Texas Instru... Master

Hello,

You should use the equivalence
y=10^(x) is equivalent to x=log(y)

You should not use word that have no meaning. x above is sometimes called antilog, not reverse log.

The relation linkin pH and pOH is as follows
pH+pOH=14, thus pH=14-pOH

Let c[H+] be the concentation (or if you use the hydronium ion, instead of H+ ) c[H3O+] the concentration of hydronium ion)
c[H+]=c[H3O+]=10^(-pH)

pOH= 6.95 thus pH=14-6.95 = 7.05
If pH=7.05 the c[H+]= 10 ^(-7.05) =8.9125E(-8)

pH= 10^ [X to the power] [(-)]7.05
The key/buttom to raise to the power is the one to the right of x squared

Hope it helps

Posted on Sep 10, 2009

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Posted on Jan 02, 2017

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