If the density is 7.8g/cm3 and the length is 10cm what is the mass

Hi,

Density is mass divided by volume.

Mass of the Sun is 1.989E30 kg, in exponential notation, where we have to move the decimal, in this case, 30 places to the right.

16 times the mass of the sun is 31.824E30 kg or 3.1824E31 kg.

Volume of the disk is 4/3 pi r ^ 3, where ^ means raised to the power of.

First, we have to take the diameter of 3000km and divide by 2 to get a radius of 1,500km. I get a volume of 14137166941.15 or 1.4137E10 km^3.

Now, dividing the mass by the volume, we get the density.

Good luck.

Paul

Here is how volume/weight conversions work. A gram is a unit of weight. A cup is a unit of volume. Volume is the amount of space an ingredient occupies and weight is the mass or "heaviness" of an ingredient.

500 grams of mini marshmallows = 10 cups
500 grams of flour = 4 cups
500 grams of sugar = 2.5 cups

As you can see, the weight for these ingredients are the same, yet the volumes are different. This is because each ingredient has a different density.

Here is another example:
A cup of feathers and a cup of lead pellets both occupy 8 fluid ounces of volume. The feathers will weigh a lot less than 8 ounces on a scale and the lead will weigh a lot more than 8 ounces on a scale.

Asking how many cups equal 100 grams would be the same as asking how many hours are in a 100 inches. Volume and weight are two completely different measurement systems... just as time and length are two different measurement systems. The only difference is that volume and weight can be linked through density.... mathematically speaking. Density = Mass divided by Volume. Density can change for the same ingredient. For example, a cup of sifted flour will weigh a lot less than a cup of unsifted flour. A pint of water will vary in weight depending on the temperature of the water.

There are websites that do volume/weight conversions based on density. Two great websites are:
http://www.onlineconversion.com and
http://www.gourmetsleuth.com or, you can look in a cookbook that has a volume/weight equivalency chart.

Sounds like a trick question. A "cc" is a cubic centimeter. "cm3" is technically the same thing. So if the mass is 1g/cc, then the mass of the volume is 20g.

1000'75=1.34

The difference is 7.59 - 6.7 = 0.89 in the low or minus direction.

Taking the correct value as the basis, the error is
0.89 / 7.59 x 100 = 11.73% low

This may be quoted as - 11.73% of true value

density is defined as the ratio of the mass of a substance to the volume occupied by that substance.
To represent density one use the Greek letter RHO (looks like a rounded p)
RHO= mass/volume
Unit of density is gram/ cm^3 or kg/m^3
Relative density is the ratio of the density of a substance to the density of pure water (at about 4 degrees Celsius). In this relation both densities must be expressed in the same units.

easy,?
1: measure its volume, then its weight and calculate its density
against gold. 9.32 g/cm3 = pure gold.
that is grams per cubic centimeter.
Any high school chem lab can do this. (mass/volume)

2: the acid test. (ask any jewelry store on earth)
coins can be plated/filled/dipped, or coated in gold or fake gold alloys.
or non plated coins can be cut. that is not pure. (alloyed )

a pro measures and weighs the coil
or looks up the coils real mass, and weight from the makers mint.
then checks your coin to see if it weighs the same amount and the size is not wrong.

http://hypertextbook.com/facts/2004/RuwanMeepagala.shtml

4 cm3. ....

The density is the mass divided by the volume. Divide 405 by 0.15 to get the density in kg/cubic-meter.

(0.540 g)(6.02 1023 atoms) 27.0 g 1.20 1022 atoms

Because density equals mass per unit volume, the mass of the cube is m V (2.70 g/cm3)(0.200 cm3) 0.540 g write this relationship twice, once for the actual sample of aluminum in the problem and once for a 27.0-g sample, and then we divide the first equation by the second: m sample m 27.0 g kN sample kN27.0 g

m sample m 27.0 g

Nsample N27.0 g

To solve this problem, we will set up a ratio based on the fact that the mass of a sample of material is proportional to the number of atoms contained in the sample. This technique of solving by ratios is very powerful and should be studied and understood so that it can be applied in future problem solving. Let us express our proportionality as m kN, where m is the mass of the sample, N is the number of atoms in the sample, and k is an unknown proportionality constant. We

Notice that the unknown proportionality constant k cancels, so we do not need to know its value. We now substitute the values: 0.540 g 27.0 g Nsample 6.02 N sample 1023 atoms