Width is 10 metres
Length is 12 metres
Derive an equation for area in the form of x
Area= length x width
120sqm = x(x-2)
120sqm = xsquared - 2x
Then apply to formula for solving a quadratic equation.
Hope that helps.
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Area =Length*width =L*W=660
Length=L=-14 +2*W
(2W-14)*W=660
2W^2-14W=660 Quadratic equation
Simplify by 2
W^2-7W-330=0
Factor the left hand side or use the quadratic formula
Factoring
W^2-7W-330=(W+15)(W-22)=0
A product is =0 if any of its factors is = 0
Thus you can have
W+15 =0 -------> W=-15 Discard it : a length cannot be negative
W-22=0 ---------> W= 22
Length L= -14 +2*22=44-14=30 yd
Check: area = 30*22 = 660 yd^2
Checks OK
L=22 yds
SOURCE: area of rectangle is 4122cm2
Area = length X width, and you know the area and the width. So,
4122 sq cm = length X 3 cm
length = 4122 sq cm / 3 cm
length = 1374 cm
(That is one long, skinny rectangle, isn't it?)
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