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Naomi Avila Posted on Nov 25, 2017

The width of a rectangle is 2 meters less than the length. if the area is 120square meters, find the length and width.

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Peter Ravi

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  • Contributor 11 Answers
  • Posted on Nov 25, 2017
Peter Ravi
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Width is 10 metres
Length is 12 metres
Derive an equation for area in the form of x
Area= length x width
120sqm = x(x-2)
120sqm = xsquared - 2x
Then apply to formula for solving a quadratic equation.
Hope that helps.

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3 Related Answers

k24674

  • 8093 Answers
  • Posted on Dec 12, 2013

SOURCE: The area of a rectangle is 660 yards. The length is 14 yards less than 2 times its width. What is the length?

Area =Length*width =L*W=660
Length=L=-14 +2*W
(2W-14)*W=660
2W^2-14W=660 Quadratic equation
Simplify by 2
W^2-7W-330=0
Factor the left hand side or use the quadratic formula
Factoring
W^2-7W-330=(W+15)(W-22)=0
A product is =0 if any of its factors is = 0
Thus you can have
W+15 =0 -------> W=-15 Discard it : a length cannot be negative
W-22=0 ---------> W= 22
Length L= -14 +2*22=44-14=30 yd
Check: area = 30*22 = 660 yd^2
Checks OK
L=22 yds

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Anonymous

  • 66 Answers
  • Posted on Oct 02, 2010

SOURCE: the length of the rectangle

54cm

Anonymous

  • 2992 Answers
  • Posted on Mar 02, 2011

SOURCE: area of rectangle is 4122cm2

Area = length X width, and you know the area and the width. So,

4122 sq cm = length X 3 cm

length = 4122 sq cm / 3 cm

length = 1374 cm

(That is one long, skinny rectangle, isn't it?)

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Related Questions:

0helpful
1answer

The length, l, of a rectangle is 5/2 its width, w. The length, l, of the rectangle is 10 inches. What is the perimeter of the rectangle? What Iis the area of the rectangle, in sauare inches?

We are given the following data:

length = 5/2 * width
length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5
width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width
Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width
Area = (10 in)(4 in)=40 in^2
0helpful
1answer

X(2x+3)=90

Solve the resulting quadratic equation
2X^2+3X-90=0
Discriminant: (3)^2-4(2)(-90)=729=(27)^2
Two roots
X_1=(1/4)*(-3+27)=6
X-2=(1/4)*(-3-27) =-(15/2), negative
Since the width must be positive, reject the negative root and keep X_1=6
Width =6
Length=2(6)+3=15

Check 6*(15)=90. Checks OK
0helpful
2answers
0helpful
2answers

How do you solve a rectangle is eight inches longer than its width. find the dimensions of the rectangle if the perimeter is 60 cm

The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.
0helpful
1answer

Please show all of the information and answers to: The plane was purchased new in 2006; therefore, x =0 represents the year 2006. X - Axis (horizontal) = years starting from 0 = 2006 and increasing b

Translate the English into Mathematics.
W=L-5 (in inches)
P=2(L+W)=2(L+L-5)=2(2L-5)
Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)
P=4L-10.
Set P= 50 (inches), to get 4L-10=50
Solve for L: Do it'!
Find W= L (the one you just found) -5 =

Now, with W the value you just calculated
the new length is L'=-4+3W
and the new perimeter is P'=2(L'+W)

Now your turn to do some work.
0helpful
1answer

Area of rectangle is 4122cm2 .width of rectangle is 3cm.how do i find the length of it

Area = length X width, and you know the area and the width. So,

4122 sq cm = length X 3 cm

length = 4122 sq cm / 3 cm

length = 1374 cm

(That is one long, skinny rectangle, isn't it?)
0helpful
1answer

Area and perimeter

Area= width * length
Perimeter= 2 * width + 2* length

Are you looking for an Excel function?
There are no Area or Perimeter functions I am aware of in Excel.
Not finding what you are looking for?

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