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A straight line can be written in the form y=mx+b, where m is the slope and b is the y-intercept.

In this case, we are given the slope (2) and the y-intercept (-3).

y=2x-3

Good luck,

Paul

Posted on Dec 06, 2017

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Posted on Jan 02, 2017

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Posted on May 20, 2015

SOURCE: A line with a slope of 1 passes through the point 4, 8.What is its equation in slope-intercept form?

2- 4 - 8 - 16

Posted on Nov 03, 2015

Subtract 90 from both sides of the equation

Mar 09, 2018 | Homework

I'm not sure which calculator you are using, but the website desmos.com can be used as an online calculator. You would enter the two lines and where they intersect, it will tell you the coordinates.

Doing it manually, you could use the elimination or substitution method.

By the elimination method:

x + y = 7 (1)

x + 2y = 11 (2)

------------------

0 - y = -4 subtracting (2) from (1)

y = 4

Substituting into (1) x + 4 = 7

x = 3 After subtracting 4 from both sides

Checking in the second equation

LS RS

3 + 2 (4) 11

3 + 8 11

11 11

LS = RS

QED

Good luck,

Paul

Doing it manually, you could use the elimination or substitution method.

By the elimination method:

x + y = 7 (1)

x + 2y = 11 (2)

------------------

0 - y = -4 subtracting (2) from (1)

y = 4

Substituting into (1) x + 4 = 7

x = 3 After subtracting 4 from both sides

Checking in the second equation

LS RS

3 + 2 (4) 11

3 + 8 11

11 11

LS = RS

QED

Good luck,

Paul

Mar 08, 2018 | Homework

5x + 7 = 45

5x = 45 -7

5x = 38

X = 38/5 = 7 3/5 or in decimal

X = 7.6

Or this could be a straight line equation of y = mx + c

Were y = 45 m = 5 = gradient of 5. Through the point of origin c = 7 at x =0

Question not specific enough

What topic are you doing?

5x = 45 -7

5x = 38

X = 38/5 = 7 3/5 or in decimal

X = 7.6

Or this could be a straight line equation of y = mx + c

Were y = 45 m = 5 = gradient of 5. Through the point of origin c = 7 at x =0

Question not specific enough

What topic are you doing?

Feb 26, 2018 | Homework

Slope is defined in many ways, but they are all essentially the same. It is the change in y divided by the change in x.

I like my students writing one above the other so that (as) they always start with the same point, and (b) they don't mix up their x's and y's.

The formula for slope is y (sub 1 - y sub 2) / (x sub 1 - x sub 2), where sub means subscript, which just denotes which point it is.

(x,y)

(-1,-7)

(-3,8)

change in y's: -7 - 8 = -15

change in x's: -1 - (-3) = -1 + 3 = 2 *** note - (-3) is + 3

So plugging into our formula we have m = -15/2 or -7 1/2 or -7.5.

Good luck,

Paul

I like my students writing one above the other so that (as) they always start with the same point, and (b) they don't mix up their x's and y's.

The formula for slope is y (sub 1 - y sub 2) / (x sub 1 - x sub 2), where sub means subscript, which just denotes which point it is.

(x,y)

(-1,-7)

(-3,8)

change in y's: -7 - 8 = -15

change in x's: -1 - (-3) = -1 + 3 = 2 *** note - (-3) is + 3

So plugging into our formula we have m = -15/2 or -7 1/2 or -7.5.

Good luck,

Paul

Feb 16, 2018 | Homework

that sounds like a problem about "slopes" so I am looking at using the derivative, which is basically the slope of the graph.

- the equation of line PQ can be simplified to y(x) = -2kx + k -8

- derivative relative to X (k is a constant) gives you -2k

- derivative of y(x) = 4x + 7 relative to x gives you 4

if the lines are parallel then the slopes are equal:

-2k=4 gives you k = -2 => your function becomes y = 4x - 8

if the lines are perpendicular the two slopes multiplied together give you -1:

-2k * 4 = -1 gives you k=1/8 => function becomes y = -1/4x - 7/8 or in other words y = -(2x+7)/8

I have made graphic representation and it looks to be correct.

I hope it makes sense.

- the equation of line PQ can be simplified to y(x) = -2kx + k -8

- derivative relative to X (k is a constant) gives you -2k

- derivative of y(x) = 4x + 7 relative to x gives you 4

if the lines are parallel then the slopes are equal:

-2k=4 gives you k = -2 => your function becomes y = 4x - 8

if the lines are perpendicular the two slopes multiplied together give you -1:

-2k * 4 = -1 gives you k=1/8 => function becomes y = -1/4x - 7/8 or in other words y = -(2x+7)/8

I have made graphic representation and it looks to be correct.

I hope it makes sense.

Apr 12, 2017 | Homework

It's a vertical line so the slope is infinite.

Mar 29, 2017 | Homework

8m - 6 =2(4m - ????

You are trying to fetch the common part from the equation.

Let's know what is 2 here? It is the common part right?

Now dividing 2 from 8 and 6.

What the process left behind??

It is - 4 and 3

So the final equation you are looking for is:

8m-6=2(4m-3)

Reference - Algebra Tutor - https://www.tutoreye.com/online-tutors/Algebra

You are trying to fetch the common part from the equation.

Let's know what is 2 here? It is the common part right?

Now dividing 2 from 8 and 6.

What the process left behind??

It is - 4 and 3

So the final equation you are looking for is:

8m-6=2(4m-3)

Reference - Algebra Tutor - https://www.tutoreye.com/online-tutors/Algebra

Mar 26, 2017 | Homework

slope or m = (y2 -y1)/(x2-x1)

always start with the same point.

m = (1 - (-5))/(-2-5)

m = (1 + 5)/(-7)

m = 6/-7

m = -6/7

The y-intercept is the b in the equation y=mx+b.

We can use either point to calculate b. Let's use (-2,1). So every time we see x, we put in -2, and every time we see y, we put in 1.

y = -6/7x + b

1 = -6/7 (-2) + b

1 = 12/7 + b

1 = 1 5/7 + b

-5/7 = b

So, y = -6/7x - 5/7

To check, we substitute in the other point and see if the left side is equal to the right side.

LS RS

-5 -6/7(5) - 5/7

-5 -30/7 - 5/7

-5 -35/7

-5 -5

LS = RS

QED

Good luck,

Paul

always start with the same point.

m = (1 - (-5))/(-2-5)

m = (1 + 5)/(-7)

m = 6/-7

m = -6/7

The y-intercept is the b in the equation y=mx+b.

We can use either point to calculate b. Let's use (-2,1). So every time we see x, we put in -2, and every time we see y, we put in 1.

y = -6/7x + b

1 = -6/7 (-2) + b

1 = 12/7 + b

1 = 1 5/7 + b

-5/7 = b

So, y = -6/7x - 5/7

To check, we substitute in the other point and see if the left side is equal to the right side.

LS RS

-5 -6/7(5) - 5/7

-5 -30/7 - 5/7

-5 -35/7

-5 -5

LS = RS

QED

Good luck,

Paul

Mar 23, 2017 | Homework

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