Question about Dimensions Office Equipment & Supplies

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Posted on Jan 02, 2017

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SOURCE: i need the following info

Exterior Dimensions

Wheelbase

2519 mm

Front Track

1527 mm

Rear Track

1503 mm

Overall length

4159 mm

Overall Width

1763 mm

Height (unloaded)

1415 mm

Ground clearance

n

Unladen weight in kg / gross weight limit in kg

1375 kg / 1935 kg

Posted on Nov 05, 2008

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SOURCE: I have an argos 214. Running windows XP. When I

when u want to use it, set it as default printer. then the setting of the design will not go back. and don't set anything setting on the printer, use program to amend the location of the design.

Posted on Jul 31, 2009

SOURCE: 1998 acura cl 3.0l battery dimensions? height,

Hello. 12 V, 720 cranking amps at 0 degrees F, 910 cranking amps at 32 degrees F, 9-5/16 x 6-13/16 x 7-5/8 in. tall, 31.7 lbs., Joe

4 thumbs up please. ty

Posted on Oct 27, 2010

Dimension of the prism is the number of cubes in width x length x height.

Surface area is 2(w x l) + 2(l x h) + 2 (wxh)

Volume is the number of cubes.

Good luck,

Paul

Surface area is 2(w x l) + 2(l x h) + 2 (wxh)

Volume is the number of cubes.

Good luck,

Paul

Dec 07, 2016 | Office Equipment & Supplies

Never. Even if it a regular shape.

Oct 18, 2016 | Miscellaneous

160 by 140

The perimeter is 600, so 2w+2l=600 where w is the width and l is the length.

Divide both sides by 2: w+l=300

The length is 20 more than the width: l=w+20

Substituting in the previous equation: w+(w+20)=300

Collecting terms: 2w+20=300

Subtract 20 from both sides: 2w=280

Divide by 2: w=140

Thus the width is 140. Substituting into the equation for length: l=140+20

Simplifying: l=160

The width is 140 and the length is 160

The perimeter is 600, so 2w+2l=600 where w is the width and l is the length.

Divide both sides by 2: w+l=300

The length is 20 more than the width: l=w+20

Substituting in the previous equation: w+(w+20)=300

Collecting terms: 2w+20=300

Subtract 20 from both sides: 2w=280

Divide by 2: w=140

Thus the width is 140. Substituting into the equation for length: l=140+20

Simplifying: l=160

The width is 140 and the length is 160

Sep 15, 2014 | MathAid Algebra II

The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Oct 11, 2013 | Lands Phones

The dimensions of the yard are 13.5m x 10.5m.

May 03, 2011 | Texas Instruments TI-30 XIIS Calculator

Dimensions (W X H X D): 23-1/4" x 17-1/2" x 19"

Dec 28, 2010 | Toshiba 20AF46 20" TV

Exterior Dimensions

Wheelbase

2519 mm

Front Track

1527 mm

Rear Track

1503 mm

Overall length

4159 mm

Overall Width

1763 mm

Height (unloaded)

1415 mm

Ground clearance

n

Unladen weight in kg / gross weight limit in kg

1375 kg / 1935 kg

Wheelbase

2519 mm

Front Track

1527 mm

Rear Track

1503 mm

Overall length

4159 mm

Overall Width

1763 mm

Height (unloaded)

1415 mm

Ground clearance

n

Unladen weight in kg / gross weight limit in kg

1375 kg / 1935 kg

Nov 05, 2008 | 2005 Audi A3

Most likely cause is that a roller has degraded during storeage. Measure the distance from the centre of the first band to the second and from the center of the second band to the third. If this dimesion is fairly constant you can work out exactly which roller is causing the problem.
The most likely culprit will be the Photo Conductor Unit. This will give a large dimension - (approx the 29cm??)
A service manual should give you the dimensions (circumferences) of the rollers within the machine. If you have a spare pcu around, put it in and see if it makes ANY difference.

May 13, 2007 | Konica Minolta magicolor 2300DL Laser...

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