Question about Homework

Ad

It sounds like you are trying to determine the surface area of a cylinder.

The area of the top and the bottom of the cylinder (which are circles) are pi x r ^ 2. Since there are two of them, we have to multiply this answer by 2.

The surface area of the side is going to be the circumference of the circle times the height. The circumference is 2 x pi x r and the height is 15 inches.

To get the total surface area, we have to add these amounts together.

Good luck,

Paul

Posted on May 23, 2017

Ad

Hi,

A 6ya expert can help you resolve that issue over the phone in a minute or two.

Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

The service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

Good luck!

Posted on Jan 02, 2017

Ad

SOURCE: Over The Range Microwave new models too tall need under 15 in hig

cut the cabinet off. a cabinet maker can do it and you can tell if they ar good

Posted on Jul 28, 2009

SOURCE: find the rate of change of the volume of a

I have no idea about your knowledge of calculus. But the solution requires calculus (I am in no mood to introduce a Delta V and Delta t and let Delta t approach zero.)

Posted on Aug 24, 2010

SOURCE: What is the capacity of

The formula for volume of a cylinder is

so, the volume of your stated beaker is 1178.097225 cubic centimeters.

Posted on Mar 07, 2011

SOURCE: How many square inches in 31 1/8 x 15 3/4 inches

31.125 multiplied by 15.75 = 490.21875 square inches.

.21875 is the same as 7/32

So, final answer: 490 7/32" squared.

Posted on Apr 07, 2015

https://www.scribd.com/doc/109721558/Bifilar-Suspension

https://www.scribd.com/doc/109721558/Bifilar-Suspension

THEORY OF MACHINES AND MECHANISNMS I LAB MANUALEXPERIMENT NO. 2 TITLE : RADIUS OF GYRATION BY BIFILAR SUSPENSION METHOD

AIM:

To determine the radius of gyration of given bar using bifilar suspensionmethod.

APPARATUSUSED:

Uniform steel bar, cylindrical weights, stop watch.

DESCRIPTION

Fig 1 shows the general arrangement for carrying out experiment. A

SET UP

uniform rectangular section bar is suspended from support frame by twoparallel cords.

Two small chucks fitted in the frame and other endssecured in bifilar bar. Ends of these cords pass through a chuck so as tofacilitate for change in length of the cord it is possible to adjust length of chord by loosening the chuck.The suspension may also be used to determine radius of gyrationof any body,In this case the body under investigation is bolted to thecenter. Radius of gyration of combined bar and body is then determined.

PROCEDURE

1) Suspend the bar from chuck and adjust length of chord ' L' convenientlynote the suspension length of each cord must be same.2) Allow the bar to oscillate about the vertical axis passing through center of gravity and measure periodic time 'T' by knowing time for 20oscillations.3) Repeat the experiment by mounting the weights one equal distancefrom the center.

THEORY

Consider bar AB whose moment of inertia is to be determine issuspended by two parallel strings as shown in figure 2.Let, L = length of each string.m = mass of bar.K = radius of gyration about the vertical axis through G.I = mass moment of inertia about the vertical axis through G.2r = distance between two stringsT = tension in each string

?

= angle of twist of bar.

?

= angle of twist of string

?

= angular accelaration of the bar.Initial position of bar is AGB. Now, if bar is set gently in vibration inhorizontal plane, it will start oscillating about vertical axis through its masscenter G. when bar is twisted about its C.G, through an angle

?

, bar is inposition A'GB' as shown. When bar is getting

?

as angular displacement,then string is getting

?

as angular displacement about vertical, distancemoved by point A is arc AA'

arc AA' = r

?

=L

?

?

= r

?

L

( 1)PIMPRI CHINCHWAD COLLEGE OF ENGG. MECHANICAL ENGG DEPT

https://www.scribd.com/doc/109721558/Bifilar-Suspension

THEORY OF MACHINES AND MECHANISNMS I LAB MANUALEXPERIMENT NO. 2 TITLE : RADIUS OF GYRATION BY BIFILAR SUSPENSION METHOD

AIM:

To determine the radius of gyration of given bar using bifilar suspensionmethod.

APPARATUSUSED:

Uniform steel bar, cylindrical weights, stop watch.

DESCRIPTION

Fig 1 shows the general arrangement for carrying out experiment. A

SET UP

uniform rectangular section bar is suspended from support frame by twoparallel cords.

Two small chucks fitted in the frame and other endssecured in bifilar bar. Ends of these cords pass through a chuck so as tofacilitate for change in length of the cord it is possible to adjust length of chord by loosening the chuck.The suspension may also be used to determine radius of gyrationof any body,In this case the body under investigation is bolted to thecenter. Radius of gyration of combined bar and body is then determined.

PROCEDURE

1) Suspend the bar from chuck and adjust length of chord ' L' convenientlynote the suspension length of each cord must be same.2) Allow the bar to oscillate about the vertical axis passing through center of gravity and measure periodic time 'T' by knowing time for 20oscillations.3) Repeat the experiment by mounting the weights one equal distancefrom the center.

THEORY

Consider bar AB whose moment of inertia is to be determine issuspended by two parallel strings as shown in figure 2.Let, L = length of each string.m = mass of bar.K = radius of gyration about the vertical axis through G.I = mass moment of inertia about the vertical axis through G.2r = distance between two stringsT = tension in each string

?

= angle of twist of bar.

?

= angle of twist of string

?

= angular accelaration of the bar.Initial position of bar is AGB. Now, if bar is set gently in vibration inhorizontal plane, it will start oscillating about vertical axis through its masscenter G. when bar is twisted about its C.G, through an angle

?

, bar is inposition A'GB' as shown. When bar is getting

?

as angular displacement,then string is getting

?

as angular displacement about vertical, distancemoved by point A is arc AA'

arc AA' = r

?

=L

?

?

= r

?

L

( 1)PIMPRI CHINCHWAD COLLEGE OF ENGG. MECHANICAL ENGG DEPT

Feb 25, 2018 | Homework

Slope is defined in many ways, but they are all essentially the same. It is the change in y divided by the change in x.

I like my students writing one above the other so that (as) they always start with the same point, and (b) they don't mix up their x's and y's.

The formula for slope is y (sub 1 - y sub 2) / (x sub 1 - x sub 2), where sub means subscript, which just denotes which point it is.

(x,y)

(-1,-7)

(-3,8)

change in y's: -7 - 8 = -15

change in x's: -1 - (-3) = -1 + 3 = 2 *** note - (-3) is + 3

So plugging into our formula we have m = -15/2 or -7 1/2 or -7.5.

Good luck,

Paul

I like my students writing one above the other so that (as) they always start with the same point, and (b) they don't mix up their x's and y's.

The formula for slope is y (sub 1 - y sub 2) / (x sub 1 - x sub 2), where sub means subscript, which just denotes which point it is.

(x,y)

(-1,-7)

(-3,8)

change in y's: -7 - 8 = -15

change in x's: -1 - (-3) = -1 + 3 = 2 *** note - (-3) is + 3

So plugging into our formula we have m = -15/2 or -7 1/2 or -7.5.

Good luck,

Paul

Feb 16, 2018 | Homework

to work out area of a circle you must use area = pi x R^2

Area = pi x Radius squared

Area = 22/7 x 2^2

Area = 88/7

Area = 12.571 metres squared (M with a little 2 next to right corner of M)

pi is 22/7= 3.1428571429 (rounded up) just use 22/7

Area = pi x Radius squared

Area = 22/7 x 2^2

Area = 88/7

Area = 12.571 metres squared (M with a little 2 next to right corner of M)

pi is 22/7= 3.1428571429 (rounded up) just use 22/7

Feb 06, 2018 | Homework

[1]: To query or describe the method via a task or series of tasks to complete a goal.

[2]: To query or describe an unknown quantity.

"How do I log on to Wiki"?

"How far is the sun from Earth"?

"To calculate how to cut the tree trunk, the surveyor had to measure how far the base was from the house then used trig to calculate the height using his theodolite".

[2]: To query or describe an unknown quantity.

"How do I log on to Wiki"?

"How far is the sun from Earth"?

"To calculate how to cut the tree trunk, the surveyor had to measure how far the base was from the house then used trig to calculate the height using his theodolite".

Feb 04, 2018 | Homework

The weight of the ship is 20,000*3*1,025 = 61,500,000 kg; To have a 3m draught in fresh water, it would have to weigh 20,000*3*1000 = 60,000,000 kg; That means it needs to remove 1,500,000 kg (1,500 T) of cargo before sailing into fresh water.

Mar 22, 2017 | Homework

a^2 + b^2 = c^2

a squared + b squared = c squared, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides in a right-angled triangle.

https://www.youtube.com/watch?v=CAkMUdeB06o

a squared + b squared = c squared, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides in a right-angled triangle.

https://www.youtube.com/watch?v=CAkMUdeB06o

Mar 10, 2017 | Homework

That ratio is 3/4, height/base, in both triangles. Is that what you mean?

Ratios are normally expressed as a fraction, not a decimal.

.

Ratios are normally expressed as a fraction, not a decimal.

.

Mar 09, 2017 | Homework

No.eclesias 9:5,10 ezequiel 18:20proves that the soul dies.but God will resuracte humans.acts 24:15.this is the eternal life john 3:16 revelation 21:3,4.which will be on this earth.isaias 65:21-25

Jan 04, 2017 | Homework

2 feet 8 inches is is 32 inches.

4,500 x 32 is 144,000 inches

divide it by 12 to to bring it back to feet. The answer is 12,000.

When working in feet, which have 12 inches, it is easier to bring to a single figure rather than using fractions. This is the benefit of the Metric system as everything is based on 10s and hundreds and thousands. Millimeters, Centimeters and Metres.

4,500 x 32 is 144,000 inches

divide it by 12 to to bring it back to feet. The answer is 12,000.

When working in feet, which have 12 inches, it is easier to bring to a single figure rather than using fractions. This is the benefit of the Metric system as everything is based on 10s and hundreds and thousands. Millimeters, Centimeters and Metres.

Jan 04, 2017 | Homework

Mar 14, 2018 | Homework

29 people viewed this question

Usually answered in minutes!

×