Question about The Computers & Internet

Hi! I think I can do your homework but I need a complete formulation of this problem. If you have it, please write it here.

Posted on May 12, 2017

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Posted on Jan 02, 2017

Dimension of the prism is the number of cubes in width x length x height.

Surface area is 2(w x l) + 2(l x h) + 2 (wxh)

Volume is the number of cubes.

Good luck,

Paul

Surface area is 2(w x l) + 2(l x h) + 2 (wxh)

Volume is the number of cubes.

Good luck,

Paul

Dec 07, 2016 | Office Equipment & Supplies

Hello Jacqueline;

My name Peter. I am a engineering college graduate. Later I changed careers and now, I am a retired field service appliance technician. So, I work on the side and it you have any appliances that need repair call me @ 414306-1362.

The length on one side of the end triangle is "a"

The area of the end triangle is: (a x a) x 0.433 = Surface Area

The surface area of the prism face = a x length.

The volume is: The surface area of the end x the surface area of the face.

My name Peter. I am a engineering college graduate. Later I changed careers and now, I am a retired field service appliance technician. So, I work on the side and it you have any appliances that need repair call me @ 414306-1362.

The length on one side of the end triangle is "a"

The area of the end triangle is: (a x a) x 0.433 = Surface Area

The surface area of the prism face = a x length.

The volume is: The surface area of the end x the surface area of the face.

Mar 06, 2015 | ixl.com

First a square has equal sides, it means s= square root of 225 = 15.

Height of the base is equal to 15. Volume of the prism = Base area x Height = 225(15) = 3375 cu. cm x 1 liter / 1000 cu. cm = 3.375 liters

Ans = 3.375 liters

Height of the base is equal to 15. Volume of the prism = Base area x Height = 225(15) = 3375 cu. cm x 1 liter / 1000 cu. cm = 3.375 liters

Ans = 3.375 liters

May 11, 2013 | Cars & Trucks

The total area of the prism is made up of the areas of the two bases plus the lateral area.

Atotal =2 A_base +P_base*height. Here A_b is the area pf a base, and P_b is the perimeter of the base.

If you take the base to be a rectangle with length L=9in, and width W=4 in, then**height= 6 in.**

With this choice**A_b=9*4=36 sq. in**

**P_b=2*(9+4)=26 in.**

Now I leave the rest to you.

Understand this calculation and apply it to the other similar questions you posted.

Atotal =2 A_base +P_base*height. Here A_b is the area pf a base, and P_b is the perimeter of the base.

If you take the base to be a rectangle with length L=9in, and width W=4 in, then

With this choice

Now I leave the rest to you.

Understand this calculation and apply it to the other similar questions you posted.

Mar 05, 2013 | Computers & Internet

If that is a **right rectangular prism**

Volume =14*12*3 c.f.

For the area here is the formula.

Total area of right rectangular prism =**2*A_b +P_b*h**

**A_b**= area of base (take 14*12 feet squares)

**P_b** is perimeter of base (14+12)*2 =52 ft.

**h** is the height (3 ft)

Lateral area =P_b*h=52*3 feet square

Add all areas.

Volume =14*12*3 c.f.

For the area here is the formula.

Total area of right rectangular prism =

Lateral area =P_b*h=52*3 feet square

Add all areas.

Mar 05, 2013 | SoftMath Algebrator - Algebra Homework...

Since the 'base' and 'top' of any prism have the same shape, the surface area can be found by

- surface area of prism = 2 * area of base + perimeter of base * H

- surface area = 2LW + 2(L+W)H
- = 2 * 7 * 4 + 2*(7+4)*5
- = 56 + 2 * 11 * 5
- = 56 +110
- = 166 sq cm

Sep 05, 2011 | Encore Math Advantage Algebra II and...

Surface area of any prism is the sum of the areas of the sides

A trapezium is A = h(a + b)/2

h is the perpendicular height, a and b are the parallel sides

A trapezium is A = h(a + b)/2

h is the perpendicular height, a and b are the parallel sides

Aug 10, 2011 | Encore Math Advantage Algebra II and...

Hello

**Rectangular Prism/Cuboid Definition:**

A Rectangular Prism/Cuboid is a solid figure bounded by six rectangular faces, a rectangular box. All angles are right angles, and opposite faces of a cuboid are equal. It is also a right rectangular prism.

**Rectangular Prism/Cuboid Formula**:

Area of Base(A) = l * w

Perimeter of Base(P) = 2l + 2w

Surface Area of Prism = 2(lw) + (2l + 2w)h = 2A + Ph

Volume of Prism = lwh = Ah

Diagonal of Prism = Sqrt(l² + w² + h²)

where

l = length, w = width, h = height

Hope this helps, if so do rate the solution

A Rectangular Prism/Cuboid is a solid figure bounded by six rectangular faces, a rectangular box. All angles are right angles, and opposite faces of a cuboid are equal. It is also a right rectangular prism.

Area of Base(A) = l * w

Perimeter of Base(P) = 2l + 2w

Surface Area of Prism = 2(lw) + (2l + 2w)h = 2A + Ph

Volume of Prism = lwh = Ah

Diagonal of Prism = Sqrt(l² + w² + h²)

where

l = length, w = width, h = height

Hope this helps, if so do rate the solution

Jan 15, 2011 | MathRescue Word Problems Of Algebra Lite

The surface area of the outer surface is the circumference of the outside of the pipe times its length. So, if OR is the radius of the outside of the pipe and SO is the outer surface area,

SO = 2 * pi * OR * 14

Similarly, the surface area of the outer surface is SI = 2 * pi * IR *14 (if SI is the inner surface area and IR is the radius of the inside of the pipe.

The question states that the difference between the outside surface area and the inside surface area is 88 sq. cm:

SO - SI = 88 ; substituting:

(2 * pi * OR * 14) - (2 * pi * IR * 14) = 88 ; factoring

(2 * pi * 14) (OR - IR) = 88 ;dividing both sides by 2*pi*14

(OR - IR) = 88/(2 * pi) = 88/(2 * 3.14159*14) = 1.00

So, the outside radius is 1 cm more than the inside radius.

It's not clear if the volume stated is the volume of the metal in the pipe or the volume of air inside the pipe, so I will solve it both ways:

If volume of 176cc is of the air inside, the formula for this volume is 14 * pi * IR *IR

176 = 14 * 3.14159 * IR * IR ; dividing both sides by 14 * 3.14159

176/(14 * 3.14159) = IR * IR ; doing the arithmetic

4 = IR * IR ; taking the square root of both sides

sqrt(4) = IR

**IR = 2 cm**

substituting back into the first equation, the OR is 1cm more than the IR, so

**OR = 3 cm**

If volume of 176cc is of the iron in the pipe, the formula for that volume is the difference between the volume of the outside of the pipe and the volume of the inside of the pipe, or

(14 * pi * OR * OR) - (14 * pi * IR * IR) = 176 ; factoring

(14 * pi) ((OR * OR) - (IR * IR)) = 176 ; dividing both sides by 14 * pi

((OR * OR) - (IR * IR)) = 176/(14 * 3.14159) = 4

but, since OR is 1 cm more than IR (from above), we can substitute OR = IR + 1

and OR * OR = (IR + 1) * (IR + 1) = (IR*IR) + 2*IR +1

So, ((OR * OR) - (IR * IR)) = 4 becomes

(IR*IR) + 2*IR +1 - (IR*IR) = 4 ; simplifying (IRsquared - IRsquared = 0)

2*IR + 1 = 4 ; subtract 1 from both sides

2*IR = 3 ; divide both sides by 2

IR = 3/2 ;

**IR = 1.5cm**

**OR = 2.5cm**

SO = 2 * pi * OR * 14

Similarly, the surface area of the outer surface is SI = 2 * pi * IR *14 (if SI is the inner surface area and IR is the radius of the inside of the pipe.

The question states that the difference between the outside surface area and the inside surface area is 88 sq. cm:

SO - SI = 88 ; substituting:

(2 * pi * OR * 14) - (2 * pi * IR * 14) = 88 ; factoring

(2 * pi * 14) (OR - IR) = 88 ;dividing both sides by 2*pi*14

(OR - IR) = 88/(2 * pi) = 88/(2 * 3.14159*14) = 1.00

So, the outside radius is 1 cm more than the inside radius.

It's not clear if the volume stated is the volume of the metal in the pipe or the volume of air inside the pipe, so I will solve it both ways:

If volume of 176cc is of the air inside, the formula for this volume is 14 * pi * IR *IR

176 = 14 * 3.14159 * IR * IR ; dividing both sides by 14 * 3.14159

176/(14 * 3.14159) = IR * IR ; doing the arithmetic

4 = IR * IR ; taking the square root of both sides

sqrt(4) = IR

substituting back into the first equation, the OR is 1cm more than the IR, so

If volume of 176cc is of the iron in the pipe, the formula for that volume is the difference between the volume of the outside of the pipe and the volume of the inside of the pipe, or

(14 * pi * OR * OR) - (14 * pi * IR * IR) = 176 ; factoring

(14 * pi) ((OR * OR) - (IR * IR)) = 176 ; dividing both sides by 14 * pi

((OR * OR) - (IR * IR)) = 176/(14 * 3.14159) = 4

but, since OR is 1 cm more than IR (from above), we can substitute OR = IR + 1

and OR * OR = (IR + 1) * (IR + 1) = (IR*IR) + 2*IR +1

So, ((OR * OR) - (IR * IR)) = 4 becomes

(IR*IR) + 2*IR +1 - (IR*IR) = 4 ; simplifying (IRsquared - IRsquared = 0)

2*IR + 1 = 4 ; subtract 1 from both sides

2*IR = 3 ; divide both sides by 2

IR = 3/2 ;

Jan 11, 2011 | Mathsoft StudyWorks! Mathematics Deluxe...

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