I have no stake in the outcome of the calculation, but the way you wrote the expression is ambiguous (in my opinion). Look at the screen and see if that is what you meant. Result is displayed. Nevermind the calculator from which I grabed the screen, that is an irrelevant detail.
I notice that you have log(10), and wondered why you failed to take advantage of the fact that log(10)=1. Had you taken advantage of that fact, you could have (log(10))^6010 =1.
Now look athe next screen capture
If the last part of your expression is log(10^6010), a calculator much more sphisticated that yours was not able to handle the calculation, and found an infinite result but the result is finite. If you use the rule of the common logs log(10^6010) = 6010.
I am merely trying to convey the idea that any expression must be simplified as much as possible before typing it.
Now I make use of the rule about the logs
On the last screen, (log(10))^6010 is set equal to 1. The two expressions yiels identical results.
Once you use the rules about the logs, you expression becomes very easy to handle: You have one power to calculate. For that power you use the [^] key, below the [CLEAR] key.
I think that what I showed you above should help you figure out how to enter the expression on your calculator.