What is the length and width of the ASW Unimax U673C

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There may be volume increasing apps or patches that you could try(Modding)

But I strongly suggest you not to try those. Because that will surely destroy the output sound quality.

But I strongly suggest you not to try those. Because that will surely destroy the output sound quality.

Jun 10, 2017 | Android Cell Phones

We are given the following data:

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

Nov 29, 2016 | The Computers & Internet

Never. Even if it a regular shape.

Oct 18, 2016 | Miscellaneous

I have done tons of roofing and we always use square feet .length X width= sq ft .like 50 ft long by16 =800 then double to get both sides of roof is 1600 sq ft

Feb 12, 2015 | Cars & Trucks

160 by 140

The perimeter is 600, so 2w+2l=600 where w is the width and l is the length.

Divide both sides by 2: w+l=300

The length is 20 more than the width: l=w+20

Substituting in the previous equation: w+(w+20)=300

Collecting terms: 2w+20=300

Subtract 20 from both sides: 2w=280

Divide by 2: w=140

Thus the width is 140. Substituting into the equation for length: l=140+20

Simplifying: l=160

The width is 140 and the length is 160

The perimeter is 600, so 2w+2l=600 where w is the width and l is the length.

Divide both sides by 2: w+l=300

The length is 20 more than the width: l=w+20

Substituting in the previous equation: w+(w+20)=300

Collecting terms: 2w+20=300

Subtract 20 from both sides: 2w=280

Divide by 2: w=140

Thus the width is 140. Substituting into the equation for length: l=140+20

Simplifying: l=160

The width is 140 and the length is 160

Sep 15, 2014 | MathAid Algebra II

Solve the resulting quadratic equation

2X^2+3X-90=0

Discriminant: (3)^2-4(2)(-90)=729=(27)^2

Two roots

X_1=(1/4)*(-3+27)=6

X-2=(1/4)*(-3-27) =-(15/2), negative

Since the width must be positive, reject the negative root and keep X_1=6

**Width =6**

Length=2(6)+3=15

Check 6*(15)=90. Checks OK

2X^2+3X-90=0

Discriminant: (3)^2-4(2)(-90)=729=(27)^2

Two roots

X_1=(1/4)*(-3+27)=6

X-2=(1/4)*(-3-27) =-(15/2), negative

Since the width must be positive, reject the negative root and keep X_1=6

Length=2(6)+3=15

Check 6*(15)=90. Checks OK

Apr 23, 2014 | Office Equipment & Supplies

Say length is x.

Width is x-24.

Perimeter is length plus width plus length plus width = 228.

x + (x-24) + x + (x-24) = 228

4x-48 = 228

4x=276

x=69

length = 69

width = 69-24= 45

check: 45 + 69 + 45 + 69 = 228

Width is x-24.

Perimeter is length plus width plus length plus width = 228.

x + (x-24) + x + (x-24) = 228

4x-48 = 228

4x=276

x=69

length = 69

width = 69-24= 45

check: 45 + 69 + 45 + 69 = 228

Dec 18, 2013 | Computers & Internet

The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Oct 11, 2013 | Lands Phones

Area = length X width, and you know the area and the width. So,

4122 sq cm = length X 3 cm

length = 4122 sq cm / 3 cm

length = 1374 cm

(That is one long, skinny rectangle, isn't it?)

4122 sq cm = length X 3 cm

length = 4122 sq cm / 3 cm

length = 1374 cm

(That is one long, skinny rectangle, isn't it?)

Mar 02, 2011 | Office Equipment & Supplies

After putting on the buttonhole foot, you lower the foot, put in the size button you want into the button hole foot. Lower the button hole lever all the way (so machine does not blip) Then the machine automatically sets the length and width of the button hole...you can adjust the length and width manually by pushing the button on the top right hand part of the machine above the LED screen the top one is stich length the other is stich width....if you put the levers to the left it will be the smallest stich length or width...if to the right it will be the largest stich length or width the machine allows. But, really the machine automatically does this for you...so I don't see the need to do it.....but you can....BBill01

Jul 22, 2008 | Juki HZL-E80 Computerized Sewing Machine

Nov 17, 2017 | The Office Equipment & Supplies

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