Question about The Office Equipment & Supplies

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Posted on Jan 02, 2017

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SOURCE: Older Delta 10'' Miter Saw Zero setting is out by 1/2 degree.

Undid the RH fence-bolt in the table behind the fence and tapped the end of the fence forward to make it perpendicular to the blade. Tighten bolt. When you look down on the two fence bolt heads, one is easy to rotate with a socket wrench, the LH bolt head would be very, very difficult to move. Undo the RH bolt to swing the fence angle WRT the blade.

Posted on Apr 09, 2009

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SOURCE: I have a irregular triagle

use general Pitagora's theorem ( if you can not just make the measurements) ...I mean get the long one on the ground ..and after that measure with a protractor the angle ..and draw the second one ..when you draw a line from the ends of the 2 of them you will have the 3rd.

or ..this is the Pitagora's theorem in general cases..**BC2=AB2+AC2-2*AB*AC*cosA meaning **

and will be with approximation

BC=24.44

Posted on Jan 03, 2011

SOURCE: bottom of screen is projecting

It is called as keystone distortion. To correct the problem press the "Keystone" button on the projector, then press left, right, down & up arrow buttons to adjust the angle at 90 degrees.

Posted on Aug 15, 2011

Need to know the engine type really, for the **X14XE and Z14 XE** Haynes recommend:

This for the 1.4 8v as you did not stipulate the engine, they are all different........

Cylinder headbolts (use new bolts)

stage 1 ... 25 Nm (18 lb ft)

stage 2 ... angle tighten + 90 degrees

stage 3 ... angle tighten + 90 degrees

stage 4 ... angle tighten + 90 degrees

stage 5 ... angle tighten + 45 degrees

This for the 1.4 8v as you did not stipulate the engine, they are all different........

Cylinder headbolts (use new bolts)

stage 1 ... 25 Nm (18 lb ft)

stage 2 ... angle tighten + 90 degrees

stage 3 ... angle tighten + 90 degrees

stage 4 ... angle tighten + 90 degrees

stage 5 ... angle tighten + 45 degrees

Mar 06, 2018 | Cars & Trucks

Lots and lots and lots. When you think the angle is nearly 180 degrees or a straight line, it must have lots and lots of sides.

The total of the interior angles of a polygon is given by (n-2)180, so the angle of each interior angle of a regular polygon is given by ((n-2)180)/n.

Now we set this to be equal to 176 and solve for n.

(n-2)180 = 176

-----------

n

Multiplying both sides by n, we get (n-2) 180 = 176n

Expanding the left side of the equation, 180n - 360 = 176n

Subtracting 176n from both sides and adding 360 to both sides, we get

180n - 176n = 360

4n = 360

Dividing both sides by 4, n = 90

Thus, you need a regular polygon of 90 sides to get an internal angle of 176 degrees.

Hopefully you don't have to construct it.

Good luck,

Paul

The total of the interior angles of a polygon is given by (n-2)180, so the angle of each interior angle of a regular polygon is given by ((n-2)180)/n.

Now we set this to be equal to 176 and solve for n.

(n-2)180 = 176

-----------

n

Multiplying both sides by n, we get (n-2) 180 = 176n

Expanding the left side of the equation, 180n - 360 = 176n

Subtracting 176n from both sides and adding 360 to both sides, we get

180n - 176n = 360

4n = 360

Dividing both sides by 4, n = 90

Thus, you need a regular polygon of 90 sides to get an internal angle of 176 degrees.

Hopefully you don't have to construct it.

Good luck,

Paul

Mar 26, 2017 | Homework

NINETY (90) sides

Mar 26, 2017 | Cars & Trucks

Lots and lots and lots. When you think the angle is nearly 180 degrees or a straight line, it must have lots and lots of sides.

The total of the interior angles of a polygon is given by (n-2)180, so the angle of each interior angle of a regular polygon is given by ((n-2)180)/n.

Now we set this to be equal to 176 and solve for n.

(n-2)180 = 176

-----------

n

Multiplying both sides by n, we get (n-2) 180 = 176n

Expanding the left side of the equation, 180n - 360 = 176n

Subtracting 176n from both sides and adding 360 to both sides, we get

180n - 176n = 360

4n = 360

Dividing both sides by 4, n = 90

Thus, you need a regular polygon of 90 sides to get an internal angle of 176 degrees.

Hopefully you don't have to construct it.

Good luck,

Paul

The total of the interior angles of a polygon is given by (n-2)180, so the angle of each interior angle of a regular polygon is given by ((n-2)180)/n.

Now we set this to be equal to 176 and solve for n.

(n-2)180 = 176

-----------

n

Multiplying both sides by n, we get (n-2) 180 = 176n

Expanding the left side of the equation, 180n - 360 = 176n

Subtracting 176n from both sides and adding 360 to both sides, we get

180n - 176n = 360

4n = 360

Dividing both sides by 4, n = 90

Thus, you need a regular polygon of 90 sides to get an internal angle of 176 degrees.

Hopefully you don't have to construct it.

Good luck,

Paul

Mar 26, 2017 | Homework

stage 1 ... 25 Nm (18 lb ft)

stage 2 ... angle tighten + 90 degrees

stage 3 ... angle tighten + 90 degrees

stage 4 ... angle tighten + 90 degrees

stage 5 ... angle tighten + 45 degrees

Jun 25, 2016 | Vauxhall Cars & Trucks

stage 1 ... 25 Nm (18 lb ft)

stage 2 ... angle tighten + 90 degrees

stage 3 ... angle tighten + 90 degrees

stage 4 ... angle tighten + 90 degrees

stage 5 ... angle tighten + 45 degrees

stage 2 ... angle tighten + 90 degrees

stage 3 ... angle tighten + 90 degrees

stage 4 ... angle tighten + 90 degrees

stage 5 ... angle tighten + 45 degrees

Feb 26, 2015 | Opel Corsa Cars & Trucks

Well, there is classification by sides, **equilateral** with 3 equal sides, **Isosceles** with two equal sides, and **scalene** with no equal sides, but you talk about angles, but I wanted to point out equilaterals have 3 equal angles, isoceles have 2 equal angles and scalene have no equal angles.

So, now we talk about angles: a**Right** trianlge has one angle that is 90 degrees, an **Obtuse** triangle has one angle greater than 90 degrees, and an **Acute** has no angles over 90 degrees.

Thus, it is possible to have a (scalene or isoceles) AND (acute, obtuse, or right) triangle, but never an equilateral AND (obtuse or right). The angles can't be equal and 90+ degrees if all three must equal 180 degrees.

So, now we talk about angles: a

Thus, it is possible to have a (scalene or isoceles) AND (acute, obtuse, or right) triangle, but never an equilateral AND (obtuse or right). The angles can't be equal and 90+ degrees if all three must equal 180 degrees.

Oct 06, 2012 | Mathsoft StudyWorks! Middle School Deluxe...

Two lines are perpendicular if they belong to the same plane and intersect (cut) one another at right angle. They make a 90 degree angle. If you are doing analytic geometry, two lines are perpendicular if the product of their slopes ia equal to -1.

Other relative positions of lines are parallel (they have the same slope/direction) or they are just secant at an angle not equal to 90 degrees.

Other relative positions of lines are parallel (they have the same slope/direction) or they are just secant at an angle not equal to 90 degrees.

Feb 03, 2012 | Office Equipment & Supplies

When dealing with trigonometric functions and their inverses one has to make sure the angle unit is chosen accordingly.

I am including a few screen capture to help you do the graph.

First, in Home screen Run the NewProb command to reset the calculator and ready it as a clean slate.

Set the correct angle unit. By default, after the NewProb command the angle unit is reset to Radian. If you want something else change it. See picture. Select 1:radian or 2:Degree.

I will use Radian first.

Press the key sequence that opens the Y= editor. Enter Y1=sin(X)

Remember after a newProb command unit is Radian, Window is standard.

Here is what you get.

Here are the window dimension that gave this picture

Now I am going to change the angle unit to degree and redraw a better framed graph. (I could have done it with the radian unit too.)

As you can see I played with the window dimensions (Xmin=-3*180=-540 and Xmax=3*180=540. The Xscale factor was set to 90 and the range of y-values was reduced to -1.2 to 1.2)

Here is what you get

Before hitting the Graph sequence make sure that the function to be drawn has a check mark to its left (see the 3rd screen capture from the top).

I am including a few screen capture to help you do the graph.

First, in Home screen Run the NewProb command to reset the calculator and ready it as a clean slate.

Set the correct angle unit. By default, after the NewProb command the angle unit is reset to Radian. If you want something else change it. See picture. Select 1:radian or 2:Degree.

I will use Radian first.

Press the key sequence that opens the Y= editor. Enter Y1=sin(X)

Remember after a newProb command unit is Radian, Window is standard.

Here is what you get.

Here are the window dimension that gave this picture

Now I am going to change the angle unit to degree and redraw a better framed graph. (I could have done it with the radian unit too.)

As you can see I played with the window dimensions (Xmin=-3*180=-540 and Xmax=3*180=540. The Xscale factor was set to 90 and the range of y-values was reduced to -1.2 to 1.2)

Here is what you get

Before hitting the Graph sequence make sure that the function to be drawn has a check mark to its left (see the 3rd screen capture from the top).

Jul 21, 2010 | Texas Instruments TI-89 Calculator

Hello,

That habit of TI, Casio, and Sharp to label the inverse trigonometric functions with the -1 superscript can cause confusions.

Hope it helps

That habit of TI, Casio, and Sharp to label the inverse trigonometric functions with the -1 superscript can cause confusions.

- The inverse trigonometric functions arcosine, arcsine, and arctangent (labeled by manufacturers as cos^-1, sin^-1, and tan^-1) should not be confused with the other trigonometric functions known as secant(x) =1/cos(x), cosecant(x)=1/sin(x) and cotangent(x) = 1/tan(x).
- To avoid errors in the use of the inverse trigonometric functions, one must be careful and set the angle unit to the one required by the problem at hand (degrees, or radians)
- To make the trigonometric functions really functions, their range is restricted.
- In this calculator arcosine (x) gives results between 0 and 180 degrees (if angle MODE is Degree) or between 0 and Pi radians (if angle MODE is Radian).
- The range of results for arcsine(x) and arctangent(x) is between -90 degrees and +90 degrees (if angle MODE Degree) or -Pi/2 and Pi/2 (if angle MODE is Radian)

Hope it helps

Nov 06, 2009 | Texas Instruments TI-83 Plus Calculator

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