Question about Book Computers & Internet

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Posted on Jan 02, 2017

SOURCE: write a mathematical model representing the total monthly cost

Mathematical Model for the problem:-

Option1: C=42+5*x

Option2: C=0+ 8.5*x

Thanks

Zulfikar Ali

ali_zulfikar@yahoo.com

09899780221

Posted on Feb 06, 2009

SOURCE: iit mathematics questions 2+3=24, 7+2=30, 6+5=72,

a + b = (a+b+1) x (b+1)

2 + 3 = 24 : (2+3+1 x 3+1)

7 + 2 = 30 : (7+2+1 x
2+1)

9 + 7 = 136

Posted on Jun 05, 2010

SOURCE: 2002 Ford Mustang GT I used OBD-II to get the

Because you got a misfire on cylinder #1 PO301

A misfire on cylinder #2 PO302

Misfires first 1000 rev PO316

O2 Codes PO 174

Etc,Etc

The LTT, is the result of not learning (yet-thus long term)

what isn't working correctly---Your Engine

Replace bad Coil--which ever is missing

Do not go by the codes,alone ,TEST

Posted on Dec 11, 2010

1/2 (or one half).

Mar 12, 2015 | Newmark Learning Common Core Mathematics...

Download the full solutions of IITJEE 2011 from below given links.

IITJEE 2011 FULL SOLUTIONS PAPER 1

IITJEE 2011 FULL SOLUTIONS PAPER 2

IIT-JEE 2011 AnalysisIIT JEE 2011 was conducted on 10th April 2011 in 131 cities all over India in 1051 centres for 4,85,262 registered candidates. For the first time, JEE has announced that scanned images of the Optical Response Sheets (ORS) with the candidates' details and their responses (answers) will be displayed on the JEE website after 25th May 2011. Answer Keys to JEE 2011 questions will be displayed on the JEE website on 15th May 2011 after completing the evaluation of OMR Sheets.

There were 10 versions for IIT-JEE 2011 - 0 to 9. The order of subjects in both papers were the same - Chemistry, Mathematics and Physics but the total marks, the number of questions and types of questions in both papers were distinct from each other.

**Paper-1**Paper1 had 69 questions in total for 240 marks - in the order of Chemistry, Physics and Mathematics. Each subject had 23 questions and the pattern was exactly the same for all the subjects.

**Chemistry**

This is a moderate level paper leaning more towards easy level of difficulty. The usual weightage of Physical > Organic > Inorganic Chemistry is maintained. Most of the questions in this paper evaluate the conceptual clarity of the student.

**Physics**

Overall the difficulty level of the paper was moderate. Still there were a few numerical questions involving elaborate mathematical calculations making them time consuming and hence difficult. No representation of Optics in this paper. Major focus in this paper was on Mechanics (for a total marks of 31)

**Mathematics**

Mathematics part of the 2011 JEE paper 1 was considered easier than the paper 1 of 2010. Few questions in Integer answer type require in-depth understanding of the concepts with perseverance in solving problems. Trigonometry had a good representation in the paper; the passage on matrices required quick thinking to interpret and solve the questions. One question about '3 x 3 non-singular skew symmetric matrices' has a basic flaw since odd ordered skew symmetric matrices are always singular. Paper 1 was a moderately difficult paper.

**Pattern of Paper-1:**

Paper-2Paper 2 had 60 questions in total - in the order of Chemistry, Physics and Mathematics. Each subject had 20 questions and as in paper 1 the pattern was exactly the same across the subjects. Questions had differential markings, each subject had 80 marks and the maximum mark for the paper was 240.

**Chemistry**

Paper 2 of IIT-JEE 2011 was difficult compared to paper 1. Weightage wise the Physical > Organic > Inorganic formula is maintained. Generally the nature of the questions in Physical chemistry is calculation oriented and hence the difficulty. Also complexity of Organic questions made this paper a challenging one.

**Physics**

Questions from certain areas which were not represented in paper 1 (gravitation, optics etc.) appeared in paper 2 thus balancing the Syllabus coverage. The difficulty level of this paper was slightly less than paper 1 especially the Integer Answer Type.

**Mathematics**

Paper 2 Mathematics part was tougher than the first paper - for the complexity in combining topic areas, for e.g. the matrix match had questions from 4 different areas posing a challenge for the student in the exam hall. Likewise, this paper required more calculations in solving than the first paper. Overall Mathematics part of IIT-JEE 2011 was less difficuly and less time consuming than that of 2010. The second paper was restricted to lesser number of areas, for e.g. there were no questions from Trigonometry. But this time Differential Calculus and Coordinate Geometry were well

represented.

**Pattern of Paper 2:**

*Courtesy: TIME*

IITJEE 2011 FULL SOLUTIONS PAPER 1

IITJEE 2011 FULL SOLUTIONS PAPER 2

IIT-JEE 2011 AnalysisIIT JEE 2011 was conducted on 10th April 2011 in 131 cities all over India in 1051 centres for 4,85,262 registered candidates. For the first time, JEE has announced that scanned images of the Optical Response Sheets (ORS) with the candidates' details and their responses (answers) will be displayed on the JEE website after 25th May 2011. Answer Keys to JEE 2011 questions will be displayed on the JEE website on 15th May 2011 after completing the evaluation of OMR Sheets.

There were 10 versions for IIT-JEE 2011 - 0 to 9. The order of subjects in both papers were the same - Chemistry, Mathematics and Physics but the total marks, the number of questions and types of questions in both papers were distinct from each other.

This is a moderate level paper leaning more towards easy level of difficulty. The usual weightage of Physical > Organic > Inorganic Chemistry is maintained. Most of the questions in this paper evaluate the conceptual clarity of the student.

Overall the difficulty level of the paper was moderate. Still there were a few numerical questions involving elaborate mathematical calculations making them time consuming and hence difficult. No representation of Optics in this paper. Major focus in this paper was on Mechanics (for a total marks of 31)

Mathematics part of the 2011 JEE paper 1 was considered easier than the paper 1 of 2010. Few questions in Integer answer type require in-depth understanding of the concepts with perseverance in solving problems. Trigonometry had a good representation in the paper; the passage on matrices required quick thinking to interpret and solve the questions. One question about '3 x 3 non-singular skew symmetric matrices' has a basic flaw since odd ordered skew symmetric matrices are always singular. Paper 1 was a moderately difficult paper.

- Q.No.1 to 7 - Single Correct Choice Type (7 questions for 21 marks). +3 for correct answer and -1 for wrong answer
- Q.No. 8 to 11 - Multiple Correct Choice Type (4 questions for 16 marks). +4 for correct answer with NO negatives
- Q.No. 12 to 16 - Paragraph Type(5 questions for 15 marks). There were 2 paragraphs- one paragraph with 2 questions and the second one with 3 questions. All questions were of Single Correct Choice Type. +3 for correct answer and -1 for wrong answer
- Q.No.17 to 23- Integer Type (7 questions for 28 marks). Answers were of single digit (ie, 0 to 9) . +4 for correct answer with NO negatives.

Paper-2Paper 2 had 60 questions in total - in the order of Chemistry, Physics and Mathematics. Each subject had 20 questions and as in paper 1 the pattern was exactly the same across the subjects. Questions had differential markings, each subject had 80 marks and the maximum mark for the paper was 240.

Paper 2 of IIT-JEE 2011 was difficult compared to paper 1. Weightage wise the Physical > Organic > Inorganic formula is maintained. Generally the nature of the questions in Physical chemistry is calculation oriented and hence the difficulty. Also complexity of Organic questions made this paper a challenging one.

Questions from certain areas which were not represented in paper 1 (gravitation, optics etc.) appeared in paper 2 thus balancing the Syllabus coverage. The difficulty level of this paper was slightly less than paper 1 especially the Integer Answer Type.

Paper 2 Mathematics part was tougher than the first paper - for the complexity in combining topic areas, for e.g. the matrix match had questions from 4 different areas posing a challenge for the student in the exam hall. Likewise, this paper required more calculations in solving than the first paper. Overall Mathematics part of IIT-JEE 2011 was less difficuly and less time consuming than that of 2010. The second paper was restricted to lesser number of areas, for e.g. there were no questions from Trigonometry. But this time Differential Calculus and Coordinate Geometry were well

represented.

- Q.No.1 to 8 - Single Correct Choice Type (8 questions for 24 marks). +3 for correct answer and -1 for wrong answer
- Q.No. 9 to 12 - Multiple Correct Choice Type (4 questions for 16 marks). +4 for correct answer with NO negatives. There was NO partical marking as well.
- Q.No. 13 to 18 - Integer Type (6 questions for 24 marks). Answers were of single digit (ie, 0 to 9) . +4 for correct answer with NO negatives.
- Q.No.19 & 20- Matrix Match Type (2 questions with 4 rows each - for 16 marks). There were 4 elements in the first column to be matched with 5 elements in the second column. Each row carried 2 marks. There were NO negarive marking.

on Apr 11, 2011 | Computers & Internet

Writing a term paper is one of the most common requirements for an upper-division course such as the one for which this book was probably assigned. Such term papers usually count for a significant part of your final grade. Yet many, perhaps most, students have never received formal instruction about how to write a good research report. The following pages are meant to help you write an "A" paper by giving you some guidelines about how to go about your research and writing.

Step 1: Relax Your Mind (15 Minutes)

Step 2: Develop a Great Thesis Statement (45 minutes)

Step 3: Write a Killer Introduction (15 minutes)

Step 4: Defend Your Thesis in a Brainstorming Session (30 minutes)

Step 5: Start Your Research to Defend Your Thesis (2 hours)

Best essay writing companies are always at your service. There are quite a few legitimate academic essay writing companies out there which deliver quality writing services in almost all academic fields.

Step 1: Relax Your Mind (15 Minutes)

Step 2: Develop a Great Thesis Statement (45 minutes)

Step 3: Write a Killer Introduction (15 minutes)

Step 4: Defend Your Thesis in a Brainstorming Session (30 minutes)

Step 5: Start Your Research to Defend Your Thesis (2 hours)

Best essay writing companies are always at your service. There are quite a few legitimate academic essay writing companies out there which deliver quality writing services in almost all academic fields.

Oct 31, 2013 | Office Equipment & Supplies

You only gave one pair of points so I assume you want a line going through those two points.

y = (2/3)x - 7/3

y = (2/3)x - 7/3

Jul 31, 2013 | Newmark Learning Common Core Mathematics...

In algebra x represents something. It is a place holder for some value. Now let that value be the word** orange** or some other word you prefer.

Read out loud the mathematical phrase :3 oranges minus 2 oranges

Complete the sentence as you used to do in grade school: 3 oranges take away 2 ( minus) 2 oranges leaves 1 orange.

Translate that sentence into mathematics : 3 oranges - 2 oranges = 1 orange.

Since this operation is true for oranges, pears, pencils, what have you, use the symbol x as a place holder for oranges, pears, pencils, what have you and write the universal truth which is

3x-2x=1x.

Make it more sophisticated by remembering that if a factor before a variable has value 1, you can just drop it. That leaves 3x=2x=x.

By the way, your calculator is just a scientific calculator without a Computer Algebra System and cannot make sense of symbols that have no values. So it cannot do it.

Read out loud the mathematical phrase :3 oranges minus 2 oranges

Complete the sentence as you used to do in grade school: 3 oranges take away 2 ( minus) 2 oranges leaves 1 orange.

Translate that sentence into mathematics : 3 oranges - 2 oranges = 1 orange.

Since this operation is true for oranges, pears, pencils, what have you, use the symbol x as a place holder for oranges, pears, pencils, what have you and write the universal truth which is

3x-2x=1x.

Make it more sophisticated by remembering that if a factor before a variable has value 1, you can just drop it. That leaves 3x=2x=x.

By the way, your calculator is just a scientific calculator without a Computer Algebra System and cannot make sense of symbols that have no values. So it cannot do it.

Jul 30, 2011 | Casio FX-115ES Scientific Calculator

The answer is 98:

2 + 3 = 2 * ( 2 + 3 ) - 2 = 8

3 + 7 = 3 * ( 3 + 7 ) - 3 = 27

4 + 5 = 4 * ( 4 + 5 ) - 4 = 32

5 + 8 = 5 * ( 5 + 8 ) - 5 = 60

6 + 7 = 6 * ( 6 + 7 ) - 6 = 72

7 + 8 = 7 * ( 7 + 8 ) - 7 = 98

2 + 3 = 2 * ( 2 + 3 ) - 2 = 8

3 + 7 = 3 * ( 3 + 7 ) - 3 = 27

4 + 5 = 4 * ( 4 + 5 ) - 4 = 32

5 + 8 = 5 * ( 5 + 8 ) - 5 = 60

6 + 7 = 6 * ( 6 + 7 ) - 6 = 72

7 + 8 = 7 * ( 7 + 8 ) - 7 = 98

Mar 11, 2011 | Vivendi Excel@ Mathematics Study Skills...

If X=2 or X=1 or X-1=0 then there is no answer.

Multiply each term by the same expression, to get:

(2-x)*(x-1)*(x+1) * 7/(2-x) +

(2-x)*(x-1)*(x+1) * 3/(x+1) =

(2-x)*(x-1)*(x+1) * -4/(x-1)

Cancel identical terms, to get:

(x-1)*(x+1) * 7 +

(2-x)*(x-1) * 3 =

(2-x)*(x+1) * -4

Expand, to get:

(x*x -1) * 7 +

(2*x - 2 - x*x + x) * 3 =

(2*x - x*x + 2 - x) * -4

Use associativity, to get:

7*x*x - 7 + 6*x - 6 - 3*x*x + 3x = -8*x + 4*x*x - 8 +4*x

And again, to get:

4*x*x + 9*x -13 = 4*x*x - 4*x - 8

Cancel, to get:

9*x -13 = - 4*x - 8

Associativity, again:

13*x = -21

As an exercise for the reader, solve for X.

P.S. Check my work, before you submit it, and claim it to be your work.

There is at least one _deliberate_ error. :-)

Multiply each term by the same expression, to get:

(2-x)*(x-1)*(x+1) * 7/(2-x) +

(2-x)*(x-1)*(x+1) * 3/(x+1) =

(2-x)*(x-1)*(x+1) * -4/(x-1)

Cancel identical terms, to get:

(x-1)*(x+1) * 7 +

(2-x)*(x-1) * 3 =

(2-x)*(x+1) * -4

Expand, to get:

(x*x -1) * 7 +

(2*x - 2 - x*x + x) * 3 =

(2*x - x*x + 2 - x) * -4

Use associativity, to get:

7*x*x - 7 + 6*x - 6 - 3*x*x + 3x = -8*x + 4*x*x - 8 +4*x

And again, to get:

4*x*x + 9*x -13 = 4*x*x - 4*x - 8

Cancel, to get:

9*x -13 = - 4*x - 8

Associativity, again:

13*x = -21

As an exercise for the reader, solve for X.

P.S. Check my work, before you submit it, and claim it to be your work.

There is at least one _deliberate_ error. :-)

Feb 01, 2011 | TOPICS Entertainment CollegePro...

1/25 IS the ratio of 1 to 25. There is not much you can say about it.

Can it be reduced to simpler terms? No! because there no factor common to the numerator (1) and the denominator (25) which you can simplify.

So 1/25 is in its reduced form.

Case of the ratio 2/100

It is clear that we can write the numerator as 1*2. To hope to reduce the ratio to simpler terms we must be able to find a factor that is common to the numerator and the denominator.

Although 100 =1*100=2*50=4*25=4*5*5 it is clear that the only factors common to 2 and 100 are 1, and 2.

To take 1 amounts to doing nothing, but if we take 2 we can write

2/100= (2*1)/(2*50)

Simplifying by 2 (the two 2 cancel each other) we get

2/100=1/50

That is the reduced form.

Can it be reduced to simpler terms? No! because there no factor common to the numerator (1) and the denominator (25) which you can simplify.

So 1/25 is in its reduced form.

Case of the ratio 2/100

It is clear that we can write the numerator as 1*2. To hope to reduce the ratio to simpler terms we must be able to find a factor that is common to the numerator and the denominator.

Although 100 =1*100=2*50=4*25=4*5*5 it is clear that the only factors common to 2 and 100 are 1, and 2.

To take 1 amounts to doing nothing, but if we take 2 we can write

2/100= (2*1)/(2*50)

Simplifying by 2 (the two 2 cancel each other) we get

2/100=1/50

That is the reduced form.

May 26, 2010 | Vivendi Excel@ Mathematics Study Skills...

a + b = (a+b+1) x (b+1)

2 + 3 = 24 : (2+3+1 x 3+1)

7 + 2 = 30 : (7+2+1 x 2+1)

9 + 7 = 136

2 + 3 = 24 : (2+3+1 x 3+1)

7 + 2 = 30 : (7+2+1 x 2+1)

9 + 7 = 136

Apr 18, 2010 | Mathematical Technologies Inc. MTI Tristan...

Mathematical Model for the problem:-

Option1: C=42+5*x

Option2: C=0+ 8.5*x

Thanks

Zulfikar Ali

ali_zulfikar@yahoo.com

09899780221

Option1: C=42+5*x

Option2: C=0+ 8.5*x

Thanks

Zulfikar Ali

ali_zulfikar@yahoo.com

09899780221

Jan 08, 2009 | SoftMath Algebrator - Algebra Homework...

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