Question about Electrical Supplies

Ad

Most likely the power circuits as there is no internal surge protection

have the set properly diagnosed and go from there

always use a power board with surge protection for all electronic equipment

as the voltage from a genset is reasonably well controlled , even at over rpms the voltage would not go high enough to cause damage for example a 240 volts running at correct rpms will only get to 255 volts uncontrolled rpms as the governor lever is fully open

however a lower voltage (200 volts ) increases amp flow and that is probably what did the damage

Posted on Jan 04, 2017

Ad

Hi there,

Save hours of searching online or wasting money on unnecessary repairs by talking to a 6YA Expert who can help you resolve this issue over the phone in a minute or two.

Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

Here's a link to this great service

Good luck!

Posted on Jan 02, 2017

Ad

Generally 20 Kva power generator can produce more power. The voltage used in this 20 kva generator is 3 phase with frequency 50 Hz. 20 kva generator engine is already very enough for use on buildings that require large electrical power or public places such as shops. According to me HARGEN provides the best high quality genset.

To fill the fuel tank to the full required 62 liters of fuel in order to use this 20 kva generator engine with more leverage.

20 kva generator engine is also issued a noise that can reach 61.7 db or can be heard up to a distance of 7 meters away from where this generator is located.

To fill the fuel tank to the full required 62 liters of fuel in order to use this 20 kva generator engine with more leverage.

20 kva generator engine is also issued a noise that can reach 61.7 db or can be heard up to a distance of 7 meters away from where this generator is located.

Sep 11, 2017 | Cars & Trucks

A 5.5 KW draw needs a 5,500 kva generator. Think in thousands.

Oct 27, 2016 | Electrical Supplies

yes

the adjustment is by the rpm setting on the governor spring

thee is a nut that you adjust the spring tension with and lower the rpms and watch the voltage gauge until you get the desired voltage

if the load is going to be constant but is well within the rated capacity( example 2kva of a 6.5 kva set) of the gen set then the variation when the load comes on will be less than 5 volts

however if the power required is close to the max capacity of the gen set ( example 4.5kva of a rated 5 kva set) , then turn the unit on and adjust the rpms up to the required voltage required

remember that an advertised kva is not the rated kva

rated kva is what the gen set will produce all day and is normally around 1kva less than advertised kva

so if you have a 6.5 kva gen set ,it will handle current peaks to 6.5 kva but will burn out if required to run long time at that load

if the gen set is 1000 watts then rated watts will be less ( 750-800) for long time use

the adjustment is by the rpm setting on the governor spring

thee is a nut that you adjust the spring tension with and lower the rpms and watch the voltage gauge until you get the desired voltage

if the load is going to be constant but is well within the rated capacity( example 2kva of a 6.5 kva set) of the gen set then the variation when the load comes on will be less than 5 volts

however if the power required is close to the max capacity of the gen set ( example 4.5kva of a rated 5 kva set) , then turn the unit on and adjust the rpms up to the required voltage required

remember that an advertised kva is not the rated kva

rated kva is what the gen set will produce all day and is normally around 1kva less than advertised kva

so if you have a 6.5 kva gen set ,it will handle current peaks to 6.5 kva but will burn out if required to run long time at that load

if the gen set is 1000 watts then rated watts will be less ( 750-800) for long time use

Oct 22, 2015 | Electrical Supplies

fuel consumption in stationary motors relies on the load on the motor, choke position and air filter cleanliness

a rated load on a gen set is considerable less than advertised power rate

that means that if you have a gen set bought at 5.5 kva, the continuous rating is actually 4.5 kva and anything more puts considerable load on the motor and increases the fuel consumption

the difference in the ratings is to allow for the extra surge required on electric motor start up

add up all the appliances that you have going at once and see ti it is close to max out put as that may be a start of you consumption problems

a rated load on a gen set is considerable less than advertised power rate

that means that if you have a gen set bought at 5.5 kva, the continuous rating is actually 4.5 kva and anything more puts considerable load on the motor and increases the fuel consumption

the difference in the ratings is to allow for the extra surge required on electric motor start up

add up all the appliances that you have going at once and see ti it is close to max out put as that may be a start of you consumption problems

Apr 26, 2015 | Electrical Supplies

the unit has gone into over load

The total power requirement has exceed the output of the generator

for example if the generator is a 2.500 kw or kva then it will generate well at 1.8 kva or kw but it will not run forever at 2.5 kva -kw

When a ac is running the power requirement will be constant on the generator and with the fridge as well then the load will be at the maximum out put of the unit.

when the fridge starts again the extra load will exceed the max out put of the generator and it will slow down ( lights dimming ) and eventually go into overload mode

have an accredited electrician calculate your maximum load requirement for an external power supply and then get a unit that is at least 15.. kva kw better that required

generally fridges use 1000watts , ac conditions will draw over 3000watts and any thing else adds up . I am guessing that your generator is only 2500 unit

The total power requirement has exceed the output of the generator

for example if the generator is a 2.500 kw or kva then it will generate well at 1.8 kva or kw but it will not run forever at 2.5 kva -kw

When a ac is running the power requirement will be constant on the generator and with the fridge as well then the load will be at the maximum out put of the unit.

when the fridge starts again the extra load will exceed the max out put of the generator and it will slow down ( lights dimming ) and eventually go into overload mode

have an accredited electrician calculate your maximum load requirement for an external power supply and then get a unit that is at least 15.. kva kw better that required

generally fridges use 1000watts , ac conditions will draw over 3000watts and any thing else adds up . I am guessing that your generator is only 2500 unit

Apr 12, 2015 | Northstar Electrical Supplies

494 is possibly control board hours with power on it, not engine run hours

Feb 13, 2015 | Kipor Electrical Supplies

Try here. Click Enter Parts System, then select Rockworth from the list on the left. They may be able to help.

Generator Guru

Generator Guru

Dec 18, 2014 | Electrical Supplies

philliprabay,

This is the formula The conversion of W to KVA is governed by the equation KVA=W/(1000*PF)

For example 1500W/(1000*0.83) = 1.8 kVA (assuming a power factor of 0.83)

Thanks for using FixYa and for the great rating.

hardrocko

This is the formula The conversion of W to KVA is governed by the equation KVA=W/(1000*PF)

For example 1500W/(1000*0.83) = 1.8 kVA (assuming a power factor of 0.83)

Thanks for using FixYa and for the great rating.

hardrocko

Sep 28, 2010 | Honda 6370C - Parallel Power Kit For ...

kva = kilo-volt-amps

watts = volts x amps = va

Therefore, 5.8kva = 5800 watts

watts = volts x amps = va

Therefore, 5.8kva = 5800 watts

Mar 24, 2010 | Honda 3000 Watt Portable Generator

27 people viewed this question

Usually answered in minutes!

×