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I have a square baking tin which is 36 x 36 x 10 cm. What is the volume of this? What volume would I require to fill the above square tin to an 8 cm height?

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Volume of the tin would be 36 x 36 x 10 or 12,960 cm^3.

If it was filled to only 8 cm, it would be 36 x 36 x 8 or 10,368cm^3.

Good luck,


Posted on Dec 21, 2016


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The difference between the inner and outer surfaces of a cylindrical pipe is 88cm sq..if the height of the cylindrical pipe is 14cm and the volume is 176cm cube. Find the inner and outer radius of the...

The surface area of the outer surface is the circumference of the outside of the pipe times its length. So, if OR is the radius of the outside of the pipe and SO is the outer surface area,
SO = 2 * pi * OR * 14
Similarly, the surface area of the outer surface is SI = 2 * pi * IR *14 (if SI is the inner surface area and IR is the radius of the inside of the pipe.
The question states that the difference between the outside surface area and the inside surface area is 88 sq. cm:
SO - SI = 88 ; substituting:
(2 * pi * OR * 14) - (2 * pi * IR * 14) = 88 ; factoring
(2 * pi * 14) (OR - IR) = 88 ;dividing both sides by 2*pi*14
(OR - IR) = 88/(2 * pi) = 88/(2 * 3.14159*14) = 1.00
So, the outside radius is 1 cm more than the inside radius.

It's not clear if the volume stated is the volume of the metal in the pipe or the volume of air inside the pipe, so I will solve it both ways:
If volume of 176cc is of the air inside, the formula for this volume is 14 * pi * IR *IR
176 = 14 * 3.14159 * IR * IR ; dividing both sides by 14 * 3.14159
176/(14 * 3.14159) = IR * IR ; doing the arithmetic
4 = IR * IR ; taking the square root of both sides
sqrt(4) = IR
IR = 2 cm
substituting back into the first equation, the OR is 1cm more than the IR, so
OR = 3 cm

If volume of 176cc is of the iron in the pipe, the formula for that volume is the difference between the volume of the outside of the pipe and the volume of the inside of the pipe, or
(14 * pi * OR * OR) - (14 * pi * IR * IR) = 176 ; factoring
(14 * pi) ((OR * OR) - (IR * IR)) = 176 ; dividing both sides by 14 * pi
((OR * OR) - (IR * IR)) = 176/(14 * 3.14159) = 4
but, since OR is 1 cm more than IR (from above), we can substitute OR = IR + 1
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So, ((OR * OR) - (IR * IR)) = 4 becomes
(IR*IR) + 2*IR +1 - (IR*IR) = 4 ; simplifying (IRsquared - IRsquared = 0)
2*IR + 1 = 4 ; subtract 1 from both sides
2*IR = 3 ; divide both sides by 2
IR = 3/2 ;
IR = 1.5cm
OR = 2.5cm

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so 109 x 3.14 x 21.5squared = 158209.69 cubic cm

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so 158.20969 litres

with a more correct value for Pi is actually 158.28993 Litres

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