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I have a square baking tin which is 36 x 36 x 10 cm. What is the volume of this? What volume would I require to fill the above square tin to an 8 cm height?

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Volume of the tin would be 36 x 36 x 10 or 12,960 cm^3.

If it was filled to only 8 cm, it would be 36 x 36 x 8 or 10,368cm^3.

Good luck,

Paul

Posted on Dec 21, 2016

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Ingredients
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How many square meters in 90,000 linear feet of 41.3" wide material?


First, we need to determine the number of square units in the Imperial system. We can choose to do the calculation in feet or inches.

Let's do it in inches first. There are 12" in a foot, so we multiply 90,000 by 12 to get 1,080,000 linear inches. Multiplying this by 41.3", we get 44,604,000 square inches. We can convert this to square feet by dividing the number of square feet by the square inches in a square foot. Since a square foot is one foot by one foot, or 12 inches by 12 inches, there are 144 square inches in a square foot. Dividing our previous answer by 144 will give us 309,750 square feet.

Converting to square metres. An inch is defined as 2.54 centimetres ("cm"). Thus, there are 2.54cm x 2.54cm in a square inch or 6.4516cm^2 in a square inch.

Using the 44,604,000 square inches we got above, and multiplying this by 6.4516, we get 287,767,166.4 square cm. There are 100 cm in a metre, so there are 100cm x 100cm in a square metre. So there are 10,000 square centimetres in a square metre. I get 28,776.7 square metres.

There are 3.280839895 feet in a metre. So there are 3.280839895 x 3.280839895, or 10.76391042 square feet in a square metre. Taking 309,750 square feet and dividing by the 10.76391042 we get 28,776.7 square metres.

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Regular pentagon QRSTU has a side length of 12 cm and an area of about 248 square cm. Regular pentagon VWXYZ has a perimeter of 140 cm. Find the area of VWXYZ. Round to the nearest tenth.


The two pentagons are similar. If k is the scale factor for the lengths, the ratio of the areas is k^2.
Pent 1 side =12 cm
Pent 2 side =140/5 =28 cm
Scale factor (larger over smaller) is k=28/12=7/3
Area of Pent_2= (49/9)*Area of Pent_1
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Solid mensuration problem solving


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Need manual and cookware


The Use and Care Manual for the Hamilton Beach 31197 Countertop Oven with Convection can be found online here:

http://useandcares.hamiltonbeach.com/files/840156300.pdf

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The base of a cylinder has a diameter of 6.2 cm. The cylinder is 18 cm tall. What is the volume of the cylinder?


When you have to deal with problems of this sort, you usually are given recipes or mathematical formulas which you apply to find the result. It so happens that for the volumes of cylinders, the formula to use is
Volume = Area of the base times the height=Ab*h
If the cylinder is circular, then the area of the base is that of a disk, Ab=PI*r^2`where r is the radius.
In your case, you are given the diameter (twice the radius) and the height.
Volume =PI*h*(6.2/2)^2, the unit being cm^2

To type in the value of PI, press [2nd] [^] (the latter is key under CLEAR, and above the division sign.
To raise a number to power 2 (to square it), use the key marked x with a superscript 2, or x with a raised 2.
After you have typed in all necessary ingredients in the formula, press the [ENTER] key and the calculator will give you the result.

Now, it is your turn to do some mathematics.

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Find the area of a square measures know that the diagonal 2.82


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1 Answer

The difference between the inner and outer surfaces of a cylindrical pipe is 88cm sq..if the height of the cylindrical pipe is 14cm and the volume is 176cm cube. Find the inner and outer radius of the...


The surface area of the outer surface is the circumference of the outside of the pipe times its length. So, if OR is the radius of the outside of the pipe and SO is the outer surface area,
SO = 2 * pi * OR * 14
Similarly, the surface area of the outer surface is SI = 2 * pi * IR *14 (if SI is the inner surface area and IR is the radius of the inside of the pipe.
The question states that the difference between the outside surface area and the inside surface area is 88 sq. cm:
SO - SI = 88 ; substituting:
(2 * pi * OR * 14) - (2 * pi * IR * 14) = 88 ; factoring
(2 * pi * 14) (OR - IR) = 88 ;dividing both sides by 2*pi*14
(OR - IR) = 88/(2 * pi) = 88/(2 * 3.14159*14) = 1.00
So, the outside radius is 1 cm more than the inside radius.

It's not clear if the volume stated is the volume of the metal in the pipe or the volume of air inside the pipe, so I will solve it both ways:
If volume of 176cc is of the air inside, the formula for this volume is 14 * pi * IR *IR
176 = 14 * 3.14159 * IR * IR ; dividing both sides by 14 * 3.14159
176/(14 * 3.14159) = IR * IR ; doing the arithmetic
4 = IR * IR ; taking the square root of both sides
sqrt(4) = IR
IR = 2 cm
substituting back into the first equation, the OR is 1cm more than the IR, so
OR = 3 cm

If volume of 176cc is of the iron in the pipe, the formula for that volume is the difference between the volume of the outside of the pipe and the volume of the inside of the pipe, or
(14 * pi * OR * OR) - (14 * pi * IR * IR) = 176 ; factoring
(14 * pi) ((OR * OR) - (IR * IR)) = 176 ; dividing both sides by 14 * pi
((OR * OR) - (IR * IR)) = 176/(14 * 3.14159) = 4
but, since OR is 1 cm more than IR (from above), we can substitute OR = IR + 1
and OR * OR = (IR + 1) * (IR + 1) = (IR*IR) + 2*IR +1
So, ((OR * OR) - (IR * IR)) = 4 becomes
(IR*IR) + 2*IR +1 - (IR*IR) = 4 ; simplifying (IRsquared - IRsquared = 0)
2*IR + 1 = 4 ; subtract 1 from both sides
2*IR = 3 ; divide both sides by 2
IR = 3/2 ;
IR = 1.5cm
OR = 2.5cm

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1 Answer

Calculation of cylinder capacity


volume of a cylinder = height time Pi r squared

dia = 43cm so radius = 21.5cm

so 109 x 3.14 x 21.5squared = 158209.69 cubic cm

1 cubic cm = 0.001 litre

so 158.20969 litres

with a more correct value for Pi is actually 158.28993 Litres

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