# A line with a slope of -2 passes through the points (F, -5) and (-6, -7) what is the value of f?

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The slope of a line is -2

= ( y_2 - y_1) / ( x_2 - x_1)

= ( -5 - (-7) ) / ( F - ( -6) )

= 2 / ( F + 6 )

so -2 ( F + 6 ) = 2

-2F -12 = 2

2F = -14

F = -7
.

Posted on Dec 30, 2016

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The value of f is -7

Posted on Dec 29, 2016

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## Related Questions:

### A line with a slope of - 1 7 passes through the points u, - 1 and 5, - 3. What is the value of u?

Slope is usually designed by the letter m. m=delta y/delta x or change in y/change in x or (y2-y1)/(x2-x1).
What we know.
m = -17 (very very steep, with a negative slope, going up to the left)
Point (5, -3)
Point (u,-1)

Putting everything into the above equation, we get
m = (-3-(-1))/(5 - u) , where m =-17
-17 = (-3 + 1)/(5 - u)
-17 = (-2)/(5-u)
To get rid of the fraction, multiply both sides by (5 - u)
-17(5-u) = -2
-85 + 17u = -2
Add 85 to both sides to get rid of the -85.

-85 + 85 +17u = -2 + 85

17u = 83
Divide both side to get u by itself.

17u/(17) = 83 / 17

u = 4.89 (rounded to 2 decimals)

Good luck,

Paul

Oct 24, 2016 | Office Equipment & Supplies

### Write an equation in slope intercept form that passes through -4,-6 and is parallel to y=-5x+1

Let's break this down into a few parts first.

Slope intercept form is otherwise known as y = mx + b, where m is the slope and b is the y-intercept.
Parallel means that the two lines will never meet. They are parallel to each other. In math terms, their slopes are the same, so the m values must be the same.

Starting with y = -5x + 1, putting into slope intercept form, y = mx + b, m = -5 and b=1.

Since it is parallel, it must have the same slope and the m values are the same.

So, y = -5x + b, but we don't know what the value of b is. To determine this, we know the point (-4,-6) is on the line that we are trying to find, so we can substitute it into the equation and calculate b to make it work.

Every time we see an x we put in -4 and every time we see a y, we put in -6.

-6 = -5(-4) + b
-6 = 20 + b
subtract 20 from both sides
-6 - 20 = 20 + b - 20
-26 = b
Now substitute this into the equation.

y = -5x + -26
Putting it into correct form, we get y = -5x - 26.

Let's check it to see if it is correct.

It has a slope of -5, so it is parallel to y=-5x + 1

Is the point (-4,-6) on the line? Let's substitute it in to see if it is on the line.

Again, everywhere we see an x, we put in -4 and everywhere we see a y we put in -6.

-6 = -5(-4) - 26
-6 = 20 - 26
-6 = -6

Sorry for the very long explanation, but after you do a few of them, you will be able to knock them off in minutes.

Good luck,

Paul

Apr 03, 2016 | Office Equipment & Supplies

### Write an equation in standard form for vertex(6,1) passing through the point (4,5)

Assuming the 'standard form' is "slope-intercept", calculate the slope from the equation m = y2-y1 = 5 - 1 = 4 = -2
x2-x1 4 - 6 -2
The intercept can be found by substituting either of the two points into the equation y = mx + b
5 = (-2)4 + b
5 = (-8) + b
13 = b
(OR, using the other point, y = mx + b
1 = (-2)6 + b
1 = (-12) + b
13 = b )
Then expressing in general:
y = (-2) x + 13

Oct 10, 2014 | Computers & Internet

### How do i find slope and then graph it

Select two points P1 and P2 on the line. Read their coordinates P1(X_1, Y_1), and P2(X_2, Y_2). If the points are given to you that is even better: you will not have to approximate their coordinates.
The slope of the straight line that passes through P1 and P2 is the ratio s=(Y_2-Y_1)/(X_2-X_1).
A slope is a number and cannot be graphed. The line that has the slope can be graphed if you have its complete equation y=slope*x + initial value.
To graph a curve on the TI84 open the Y= editor, type in the second member (right side) of the function say on line Y1= then press the Graph function key.

Feb 05, 2013 | Texas Instruments TI-84 Plus Calculator

### Write an equation of the line in standard form that pass through (-5,-11) and 10,7)

Calcualte the slope of the line as
a=(7-(-11))/(10-(-5))=18/15=6/5
Use the fact that the line passes through one of the two points, for example (10,7)
7=(6/5)*10+b=12+b
Obtain b as b=7-12=-5
The equation of the line in functional form is y=(6/5)x-5
Multiply everything by 5 to clear the fraction
5y=6x-25 or 0=6x-5y-25
Finally, the equation in general form (standard?) is 6x-5y-25=0.

Check the calculation by verifying that the point (10,7) lies on the line.
6(10)-5(7)-25=60-35-25=60-60=0 CHECKed!
Check that the second point (-5,-11) lies on the line also (if you want to)
6*(-5)-5*(-11)-25=-30+55-25=0
That checks OK.

Dec 04, 2011 | Super Tutor Pre Algebra (ESDPALG)

That is an equation describing a straight line. The "slope-intercept" form of a line is

y = mx + b

where m is the slope (change in y-value / change in x-value)
and b is the y-intercept (the point where the line crosses the y-axis when x=0)

Positive slope means the line is rising and negative slope means it's falling.

You can rewrite the original equation 2x - 4y -9 = 0 in slope-intercept form:

y = (1/2)x - (9/4)

So you know the slope is positive 1/2 (line rises 1 y-unit for each 2 x-unit change) and crosses the y-axis at -9/4. With this information you can graph the line.

Jul 12, 2011 | Sewing Machines

### What is the equation of the pair of points (-5,-8) and (-3, -1)

The site seems to eat the plus signs I enter, so I will use PLUS to symbolize addition.

To find the equation of the straight line (
y = a*x PLUS b) that passes through two points P1(x1,y1) and P(x2,y2) , you need to use
1. the coordinates of the points to calculate the slope a (gradient) as a=(y2-y1)/(x2-x1)
2.
Replace the calculated value of a in the equation and write that one of the points ( P1(x1,y1) for example) satisfies the equation. In other words y1=a*x1 PLUS b.
Here y1 and x1 are known values, a has been calculated, and only b is still unknown. You can now use the equation
y1=a*x1 PLUS b to calculate b as
b=(y1-a*x1)

Example: Equation of the line through (1,5) and (3,6)

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2
The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=(1/2)*3 PLUS b.
Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5
Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

I trust you can substitute you own values for (x1,y1, x2,y2) to duplicate the calculations above.

Jan 27, 2011 | Texas Instruments TI-84 Plus Calculator

### How to determine function in terms of coordinates

It depends on how complex the function is; there are different techniques. For a straight line of the standard form, usually shown as y=mx+b; this is a simple function of y in terms of x. So, determining the function in this case means finding values for m and b. --- m is the slope of the line, commonly called rise over run. Since your question asks in terms of coordinates, I would assume that you are looking at a problem giving you 2 points.

Probably something like p1 = (3,4); p2 = (5,8); the general form of this is p1=(x1,y1); p2=(x2,y2). The slope in this case is rise over run, in other words, the change in y divided by the change in x. This can be calculate between these two points as (y2-y1)/(x2-x1). In my sample above, this would be (8-4)/(5-3) = 4/2 = 2 giving the value of m.

To find the value of b (the y intercept) you need the value of y when x = 0. Since you already know that m, the slope is 2, consider a new point, call it p3 (x3,y3), pick either of the known points and solve the slope equation again, this time for y3. [m=(y3-y1)/(x3-x1)]. We know that x3 is 0, since we are trying to solve for y where that is true, so the equation becomes:

m=(y3-y1)/(-x1)
-x1*m=y3-y1
y3=y1-x1*m

y3 is really b in the standard form, since it is, by definition the intercept, or the value when x=0,
so
b=y1-x1*m -- this gives you the y intercept anytime you know the slope and one point on the line.

In the example, y1 = 4, x1=3 and we've already calculated m to be 2, so
b=4-3*2 = -2
So, the function would be

y = 2x -2

To check, plug in the values of the other point, p2, and see if they work

y2 = 2*x2 - 2

8=2*5-2

It's easier than it looks. It can help you to understand if you get some old fashioned graph paper and plot it so you can see what is happening.

Jun 16, 2009 | Computers & Internet

### How do i find the slope of a line

difference in y (Y2-Y1) divided by difference in x (X2-X1). Example: 1st point (5,3) and second point (10,6) means subtract 3 from 6 (2nd y value from first)= 3- this is your numerator. now subtract second X value from firt X value (10-5)= 5; this is the denominator. the slope (m) is 3/5 or .6

Mar 15, 2009 | Texas Instruments TI-85 Calculator

### Analytic geometry

assuming the question is what is the circle equation?
and if (-2,2) is the center of the circle
the equation should look like this: (x+2)^2+(Y-2)^2=R^2

And now only R is needed.

given 2x-5y+4=0 equation of line perpendicular

we can rearange the equation to be y=(2x+4)/5
from that we can see that the slope of the line is 2/5
And from the fact of perpendicular line we can say that the slope
of the radius line is -2/5.

The motivation now is to calculate the distance between the center of the circle to the cross point of the radius with the line perpendicular

For that we would calculate the radius line equation and compare it to the equation of line perpendicular

As mentioned earlier the slope of the radious line is -2/5.

So the equation is y=-2/5x+b and b can be calculated by using the center of the circle coordinates

2= - (2/5)*(-2)+b ------> b=2-4/5=1.2

Now the cross point is calculated by comparing the equations:
-(2/5)x+1.2=(2x+4)/5 --> -2x+6=2x+4 --> 4x=2 --> x=1/2 --> y=1

So the cross point is (1/2,1).

The distance between the points is calculated by the following
Formula:

R=SQR(((1/2)-(-2))^2+(2-1)^2)=SQR(2.5^2+1^2)=SQR(6.25+1)=
SQR(7.25)

Therefore the circle eq is (x+2)^2+(Y-2)^2=7.25

Oct 26, 2008 | Casio FX-115ES Scientific Calculator

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