Question about Office Equipment & Supplies

Let me know if I answer your question.

a^2 + b^2 = c^2

If you are given a and c and have to solve for b, let's do it this way.

5^2 + b^2 = 13^2

25 + b^2 = 169

25 + b^2 -25 = 169 - 25

b^2 = 144

b = sqrt(144)

b = 12.

I hope this helps.

Good luck.

Paul

p.s. Here is a great video of Pythagorean Theorem in water;)

Pythagorean theorem water demo

Posted on Dec 17, 2016

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Posted on Jan 02, 2017

https://www.mathsisfun.com/geometry/rhombus.html

### Lesson HOW TO solve problems on the rhombus sides and ...

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Lesson HOW TO solve problems on the **rhombus sides** and **diagonals** measures - Examples ... Find the perimeter of the **rhombus**, if its **side** is 7 **cm** long. ... Since **all** four **sides of the rhombus** have the same **length**, the measure of the **side** ... 32/4 **cm** = **8 cm**. ... In our case the legs are 12/2 **cm** = **6 cm** and 16/2 **cm** = **8 cm** long.
### SOLUTION: The diagonals of a rhombus are 6 cm and 8 cm ...

www.algebra.com > Geometry > Customizable Word Problem Solvers
SOLUTION: **The diagonals of** a **rhombus** are **6 cm** and **8 cm**. What is the ... (paid link). Click here to see **ALL** problems on Geometry Word Problems ... We need to find the **side of the rhombus** using the Pythagorean Theorem. After that, we use ...
### The diagonals of a rhombus are of lengths 6 cm and 8 cm. Find the ...

https://in.answers.yahoo.**com**/question/index?qid...
Jun 29, 2013 - **The diagonals of** a **rhombus** are of **lengths 6 cm** and **8 cm**. ... rough aketch and you will see that in **each** triangle the shorter **sides** are 3 **cm** and 4 **cm**, so using the Theorem of Pythagoras, if we call the hypotenuse l **cm**, **then** l^2 ...
Rhombus

Mar 30, 2016 | Office Equipment & Supplies

10 x 10 = 100

8 x 8 = 64

x = sqroot (100-64)

x = sqroot (36)

x = 6 feet

the square of the hypotenuse equals the square of the adjacent + Square of the opposite.

So H^2 = O^2 + A^2

the convention is C^2 = A ^2 + B^2

square root of any of the components gives the actual value

but the addition or subtraction has to be the square of the values

http://www.mathsisfun.com/pythagoras.html

8 x 8 = 64

x = sqroot (100-64)

x = sqroot (36)

x = 6 feet

the square of the hypotenuse equals the square of the adjacent + Square of the opposite.

So H^2 = O^2 + A^2

the convention is C^2 = A ^2 + B^2

square root of any of the components gives the actual value

but the addition or subtraction has to be the square of the values

http://www.mathsisfun.com/pythagoras.html

Feb 07, 2015 | Office Equipment & Supplies

Assuming that the angle at A is the right angle, Pythagoras' theorem says that the length of the hypotenuse (the side opposite the right angle) is the square root of the sum of the squares of the other two sides. In your case, AB and AC are 'the other two sides' and BC is the hypotenuse, so:

__ __ __ __

/ 2 2 /

length BC = V 10 + 20 = V 100 + 400

__ __

= V 500 = 22.36 cm

(To find the angle at C, you need trigonometry and is arc-tan(10/20)

and the angle at B is arc-tan(20/10) - 26.5 deg and 63.5 deg)

/ 2 2 /

length BC = V 10 + 20 = V 100 + 400

= V 500 = 22.36 cm

(To find the angle at C, you need trigonometry and is arc-tan(10/20)

and the angle at B is arc-tan(20/10) - 26.5 deg and 63.5 deg)

Oct 17, 2014 | Computers & Internet

"Hypotenuse" implies a right angle triangle is wanted here. With Pythagoras' Theorem it is always good to look first for a 3-4-5 pattern, the simplest ratio, although a right angle triangle easily can be other ratios too.

24 x 32 is (3 x 8) x (4 x 8) so it is a 3-4-5 triangle after all, and the hypotenuse is then 5 x 8 = 40

Or, you could calculate SQRT (24^2 + 32^2) = 40

24 x 32 is (3 x 8) x (4 x 8) so it is a 3-4-5 triangle after all, and the hypotenuse is then 5 x 8 = 40

Or, you could calculate SQRT (24^2 + 32^2) = 40

Aug 12, 2014 | Computers & Internet

It is the diagonal of a square 14" on a side. So by Pythagoras' Theorem

D^ = s^2 + s^2 = 392

D = 19.8"

D^ = s^2 + s^2 = 392

D = 19.8"

Mar 28, 2014 | Mcgraw-Hill Computers & Internet

Draw a vector of length five. From the head of it, draw another vector of length twelve. Now measure the distance from the tail of the first vector to the head of the second.

If the two vectors are at right angles then Pythagoras' theorem applies. Square five to get 25. Square twelve to get 144. Add them to get 169. Take the square root to get 13.

If the two vectors are at right angles then Pythagoras' theorem applies. Square five to get 25. Square twelve to get 144. Add them to get 169. Take the square root to get 13.

Jan 24, 2014 | USAF Security Forces Shield Decal

in building terms there is the 3, 4, 5 rule, which allows you to determine a perfect right angle. This is from the Pythagoras theorem which says - the square on the hypotenuse equals the sum of the squares on the other two sides.... so to calculate the hypotenuse we square 3 and 4 to get 9 and 16 respectively. Adding these give 25. Getting the square root of 25 gives 5 which is the dimension of the hypotenuse...

Any combination of 3/4/5 works - so 6/8/10 is also valid.

Hope this helps.

Any combination of 3/4/5 works - so 6/8/10 is also valid.

Hope this helps.

Oct 22, 2013 | Measuring Tools & Sensors

1) There is a big difference between Bosch promo manual and Bosch operation manual:

2) Online promo manual says: Combined Indirect/Pythagoras for measuring total height from a distance

http://www.boschtools.com/AboutBoschTools/RequestProductLiterature/Documents/2010%20Catalog%20PDF/2010%20Measuring%20Tools.pdf

3) Online operation manual shows no instructions for Pythagoras measuring.

And shows no button for displaying E value or height.

http://www.engineersupply.com/images/bosch-tools/Bosch_Digital_Distance_Measurer_130k_User_Manual.pdf

4) Operation manual shows:

Length Measurement** and tells you to measure the height while promo says tool will calculate height E

Area Measurement*** shows rectangle only and not triangle

Volume Measurement

Area or Volume

Rounding of Large Calculations

Continuous Measurement (Tracking)

5) I would contact Bosch directly:

http://boschtools.com/Service/ContactUs/Pages/default.aspx

6) Until you get satisfaction from Bosch, the Bosch device gives precise menasurements that can be entered into a Pythagorean calculator online, which defeats the purpose of a jobsite tool: But you can access online calculator via cell phone while on jobsite.

http://www.analyzemath.com/Geometry_calculators/pythagorean.html

2) Online promo manual says: Combined Indirect/Pythagoras for measuring total height from a distance

http://www.boschtools.com/AboutBoschTools/RequestProductLiterature/Documents/2010%20Catalog%20PDF/2010%20Measuring%20Tools.pdf

3) Online operation manual shows no instructions for Pythagoras measuring.

And shows no button for displaying E value or height.

http://www.engineersupply.com/images/bosch-tools/Bosch_Digital_Distance_Measurer_130k_User_Manual.pdf

4) Operation manual shows:

Length Measurement** and tells you to measure the height while promo says tool will calculate height E

Area Measurement*** shows rectangle only and not triangle

Volume Measurement

Area or Volume

Rounding of Large Calculations

Continuous Measurement (Tracking)

5) I would contact Bosch directly:

http://boschtools.com/Service/ContactUs/Pages/default.aspx

6) Until you get satisfaction from Bosch, the Bosch device gives precise menasurements that can be entered into a Pythagorean calculator online, which defeats the purpose of a jobsite tool: But you can access online calculator via cell phone while on jobsite.

http://www.analyzemath.com/Geometry_calculators/pythagorean.html

Feb 19, 2011 | Bosch DLR130K Laser Distance Measurer

You should checkout Bitesize revision:

http://www.bbc.co.uk/scotland/education/bitesize/standard/mathsI/pythagoras/pythagoras_rev1.shtml

To summarise - Pythagoras works with right angled triangles only (with one 90 degree angle). One side is always bigger than the other two - it's always the one opposite the 90 degrees.

The long side (hypotenuse) times by itself is the same as if you times-ed the other sides by themselves and added them together.

In your question, you're trying to find the across (which you guess as 12?).

The diagonal (14) is opposite the right angle so it's the biggest (and equal to the other two). We'll call across a, we don't know what it is.

14 * 14 = (7.5 * 7.5) + (a * a)

Rearrange:

(14 * 14) - (7.5 * 7.5) = (a * a)

Type that bit on the left into a calculator (you might need to do it in parts - work out 14 * 14 and write it down...). Once you've got the answer you need to use the square root button to find out what a is.

http://www.bbc.co.uk/scotland/education/bitesize/standard/mathsI/pythagoras/pythagoras_rev1.shtml

To summarise - Pythagoras works with right angled triangles only (with one 90 degree angle). One side is always bigger than the other two - it's always the one opposite the 90 degrees.

The long side (hypotenuse) times by itself is the same as if you times-ed the other sides by themselves and added them together.

In your question, you're trying to find the across (which you guess as 12?).

The diagonal (14) is opposite the right angle so it's the biggest (and equal to the other two). We'll call across a, we don't know what it is.

14 * 14 = (7.5 * 7.5) + (a * a)

Rearrange:

(14 * 14) - (7.5 * 7.5) = (a * a)

Type that bit on the left into a calculator (you might need to do it in parts - work out 14 * 14 and write it down...). Once you've got the answer you need to use the square root button to find out what a is.

May 06, 2009 | SoftMath Algebrator - Algebra Homework...

Debs,

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

Dec 19, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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