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Find the slope of the line that passes through (6, 10) and (1, 1)

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Posted on Dec 03, 2016

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Write an equation in slope intercept form that passes through -4,-6 and is parallel to y=-5x+1


Let's break this down into a few parts first.

Slope intercept form is otherwise known as y = mx + b, where m is the slope and b is the y-intercept.
Parallel means that the two lines will never meet. They are parallel to each other. In math terms, their slopes are the same, so the m values must be the same.

Starting with y = -5x + 1, putting into slope intercept form, y = mx + b, m = -5 and b=1.

Since it is parallel, it must have the same slope and the m values are the same.

So, y = -5x + b, but we don't know what the value of b is. To determine this, we know the point (-4,-6) is on the line that we are trying to find, so we can substitute it into the equation and calculate b to make it work.

Every time we see an x we put in -4 and every time we see a y, we put in -6.

-6 = -5(-4) + b
-6 = 20 + b
subtract 20 from both sides
-6 - 20 = 20 + b - 20
-26 = b
Now substitute this into the equation.

y = -5x + -26
Putting it into correct form, we get y = -5x - 26.

Let's check it to see if it is correct.

It has a slope of -5, so it is parallel to y=-5x + 1

Is the point (-4,-6) on the line? Let's substitute it in to see if it is on the line.

Again, everywhere we see an x, we put in -4 and everywhere we see a y we put in -6.

-6 = -5(-4) - 26
-6 = 20 - 26
-6 = -6

Sorry for the very long explanation, but after you do a few of them, you will be able to knock them off in minutes.

Good luck,

Paul

Apr 03, 2016 | Office Equipment & Supplies

1 Answer

Write an equation in slope intercept form that passes through (-4,7) and is perpendicular to y+4=1/4(x-7)


Let's break this down into a few parts first.

Slope intercept form is otherwise known as y = mx + b, where m is the slope and b is the y-intercept.
Perpendicular means that the two lines will intersect each other at a 90 degree angle. In math terms, their slopes will be negative reciprocals of each other.
Starting with y + 4 = 1/4(x -7), putting into slope intercept form, y = mx + b, m = 1/4 and b=-7/4 -4.

Since it is perpendicular, it must have a slope that is a negative reciprocal. The slope of the original line is 1/4, so the multiplying it -1, we get -1/4, and taking the reciprocal, we get -4. So the slope of the perpendicular line is -4.

So, y = -4x + b, but we don't know what the value of b is. To determine this, we know the point (-4,7) is on the line that we are trying to find, so we can substitute it into the equation and calculate b to make it work.

Every time we see an x we put in -4 and every time we see a y, we put in 7.

y = -4x + b
7 = -4(-4) + b
7 = 16 + b
subtract 16 from both sides
7 - 16 = 16 + b - 16
-9 = b

Now substitute this into the equation.

y = -4x + -9
Putting it into correct form, we get y = -4x - 9.

Let's check it to see if it is correct.

It has a slope of -4, so it is perpendicular to y=1/4x - 5 3/4.
Is the point (-4,7) on the line? Let's substitute it in to see if it is on the line.

Again, everywhere we see an x, we put in -4 and everywhere we see a y we put in 7.

y= -4x - 9
7 = -4 (-4) - 9
7 = 16 - 9
7 = 7

Sorry for the very long explanation, I was being overly thorough, but after you do a few of them, you will be able to knock them off in minutes.

Good luck,

Paul

Apr 03, 2016 | Office Equipment & Supplies

1 Answer

A line with a slope of 1 passes through the point (4, 8).What is its equation in slope-intercept form?


A math teacher might know the answer to that one. Do you know a math teacher you could ask?

Nov 03, 2015 | Miscellaneous

1 Answer

How do i find slope and then graph it


Select two points P1 and P2 on the line. Read their coordinates P1(X_1, Y_1), and P2(X_2, Y_2). If the points are given to you that is even better: you will not have to approximate their coordinates.
The slope of the straight line that passes through P1 and P2 is the ratio s=(Y_2-Y_1)/(X_2-X_1).
A slope is a number and cannot be graphed. The line that has the slope can be graphed if you have its complete equation y=slope*x + initial value.
To graph a curve on the TI84 open the Y= editor, type in the second member (right side) of the function say on line Y1= then press the Graph function key.

Feb 05, 2013 | Texas Instruments TI-84 Plus Calculator

1 Answer

3x+9y=17


  1. Transform this equation to its functional form:
  2. 9y=-3x+17 or y=(-1/3)x+17/9
  3. In the last equation, the slope is the coefficient of x, namely -1/3.
  4. A line parallel to this one must have the same slope (-1/3).
  5. So the equation of your line starts this way: y=(-1/3)x+b.
  6. To identify (calculate) b, you must make use of the fact that the parallel line passes through the point (1,5).
  7. That means that the coordinates of the point (1,5) satisfy the equation of the parallel line y=(-1/3)x+b
  8. Substitute 5 for y, and 1 for x and solve for b.
And that is as far I will go. I leave it to you finish up the work : find b and write the equation in the functional form, then convert it to the general form (Ax+By+C=0) if that is what you are asked to produce.

Aug 05, 2012 | Office Equipment & Supplies

1 Answer

Can i ask how to answer this?2x-4y-9=o


That is an equation describing a straight line. The "slope-intercept" form of a line is

y = mx + b

where m is the slope (change in y-value / change in x-value)
and b is the y-intercept (the point where the line crosses the y-axis when x=0)

Positive slope means the line is rising and negative slope means it's falling.

You can rewrite the original equation 2x - 4y -9 = 0 in slope-intercept form:

y = (1/2)x - (9/4)

So you know the slope is positive 1/2 (line rises 1 y-unit for each 2 x-unit change) and crosses the y-axis at -9/4. With this information you can graph the line.

Jul 12, 2011 | Sewing Machines

1 Answer

Can u calculate the gradient of a line?. If s how?


What you call the gradient is usually called the slope of the line. Select two points P1 and P2 on the line. Read their coordinates P1(X_1, Y_1), and P2(X_2, Y_2).
The slope of the straight line that passes through P1 and P2 is the ratio s=(Y_2-Y_1)/(X_2-X_1).

Nov 18, 2010 | Casio fx-300ES Calculator

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